Start by adding 10 to both sides.

\(\displaystyle \frac{5}{9}x=64\)

Multiply both side by 9 to get rid of the fraction.

\(\displaystyle 5x=576\)

Divide by 5

\(\displaystyle x=\frac{576}{5}\)

Since all the answer choices have mixed fractions, you will also need to reduce down to a mixed fraction

\(\displaystyle \frac{576}{5}=100\frac{76}{5}=115\frac{1}{5}\)

Add both sides by 9 to isolate the x on one side.

\(\displaystyle \frac{9}{5}x=18\)

Multiply both sides by 5.

\(\displaystyle 9x=90\)

Divide boths ides b 9.

\(\displaystyle x=10\)

First, add 10 to both sides so the term with "z" is isolated on one side.

\(\displaystyle \frac{2}{3}z=22\)

To get rid of the fraction, multiply both sides by 3.

\(\displaystyle 2z=66\)

Divide by 2.

\(\displaystyle z=33\)

Start by adding the terms with \(\displaystyle x\) together. Find the least common denominator for the two fractions.

\(\displaystyle \frac{4}{5}x+\frac{3}{2}x=\frac{8}{10}x+\frac{15}{10}x=12\)

\(\displaystyle \frac{8}{10}x+\frac{15}{10}x=\frac{23}{10}x=12\)

\(\displaystyle \frac{23}{10}x=12\)

Now, multiply both sides by 10.

\(\displaystyle 23x=120\)

Then divide both sides by 23.

\(\displaystyle x=\frac{120}{23}\)

Start by adding 9 to both sides.

\(\displaystyle \frac{2}{3}p=6\)

Next, multiply both sides by 3.

\(\displaystyle 2p=18\)

Finally, divide both sides by 2.

\(\displaystyle p=9\)

When we are solving equations, we must always remember that what's on the left side equals the right side. Therefore, any changes that we make to one side of the equation, we must make to the other side so that the equation stays equal and balanced. When solving single-variable equations, we try to isolate the variable on one side so that we can get a number which it's equal to on the other side. Therefore, everything we do to solve this equation must work towards getting just the variable on one side, and a number on the other side. Let's take a look at our equation again:

\(\displaystyle \small \frac{2}{3}x+5=15\)

We want to isolate our \(\displaystyle \small x\) term on the left-hand side, so our first step is to get rid of the \(\displaystyle \small 5\). To do that, we can perform the inverse operation; we can subtract \(\displaystyle \small 5\) from both sides:

\(\displaystyle \small \frac{2}{3}x+5-5=15-5\)

\(\displaystyle \small \frac{2}{3}x=10\)

Now we have our \(\displaystyle \small x\) on one side and a number on the other, but we need to see what one \(\displaystyle \small x\) is equal to, not \(\displaystyle \small \frac{2}{3}x\). We therefore need to multiply \(\displaystyle \small \frac{2}{3}x\) by a number which will make it just \(\displaystyle \small x\). You might remember from fractions that multiplying a fraction by its reciprocal will give you \(\displaystyle \small 1\), so let's try multiplying each side by the reciprocal of \(\displaystyle \small \frac{2}{3}\), which is \(\displaystyle \small \frac{3}{2}\):

\(\displaystyle \small \frac{3}{2}\times\frac{2}{3}x=10\times\frac{3}{2}\)

\(\displaystyle \small \frac{6}{6}x=\frac{30}{2}\)

\(\displaystyle \small x=15\)

We have one \(\displaystyle \small x\) on the left side and a number on the right side, therefore our final answer is \(\displaystyle \small x=15\)