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Basic Arithmetic : Increase

Study concepts, example questions & explanations for Basic Arithmetic

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Example Questions

Example Question #1 : Finding Percent Change

In 2012, a university received 150,249 applicants. In 2013, the same university received 190,201 applicants. By what percent did the total number of applicants increase from 2012 to 2013?

Possible Answers:

$26.6\%$ $\displaystyle 26.6\%$

$21.0\%$ $\displaystyle 21.0\%$

$27.8\%$ $\displaystyle 27.8\%$

$24.6\%$ $\displaystyle 24.6\%$

Correct answer:

$26.6\%$ $\displaystyle 26.6\%$

Explanation:

To find the percent change, use the following formula:

$\bigg(\frac{new-original}{original}\bigg)\times 100$ $\displaystyle \bigg(\frac{new-original}{original}\bigg)\times 100$

Our new number of applicants is 190,201, while the original number of applicants is 150,249.

$\bigg(\frac{190201-150249}{150249}\bigg)\times100=26.6\%$ $\displaystyle \bigg(\frac{190201-150249}{150249}\bigg)\times100=26.6\%$

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Example Question #1 : Increase

In January, Widget Company made 180 $\displaystyle 180$, 129 $\displaystyle 129$ widgets. In February, the same company made 200 $\displaystyle 200$, 382 $\displaystyle 382$ widgets. By what percentage did the amount of widgets made increase?

Possible Answers:

$11.2\%$ $\displaystyle 11.2\%$

$12.4\%$ $\displaystyle 12.4\%$

$12.6\%$ $\displaystyle 12.6\%$

$10.1\%$ $\displaystyle 10.1\%$

Correct answer:

$11.2\%$ $\displaystyle 11.2\%$

Explanation:

To find the percent increase, use the following formula:

$(\frac{\text{New value-Old value}}{\text{Old value}})\times 100$ $\displaystyle (\frac{\text{New value-Old value}}{\text{Old value}})\times 100$

In the case of Widget Company,

$(\frac{200382-180129}{180129})\times 100 = 11.2%$ $\displaystyle (\frac{200382-180129}{180129})\times 100 = 11.2%$

Therefore, the percent increase is $11.2 \%$ $\displaystyle 11.2 \%$

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Example Question #2 : Increase

Derek ran his first mile in $\displaystyle 10$ minutes and his second mile in $\displaystyle 11$ minutes.

What is the percent increase between the time it took Derek to run the first and second mile?

Possible Answers:

$8\%$ $\displaystyle 8\%$

$15\%$ $\displaystyle 15\%$

$10\%$ $\displaystyle 10\%$

$9\%$ $\displaystyle 9\%$

$11\%$ $\displaystyle 11\%$

Correct answer:

$10\%$ $\displaystyle 10\%$

Explanation:

The correct answer is a percent change (increase) of $10\%$ $\displaystyle 10\%$.

This can be calculated using the following equation:

$\frac{\text{new}-\text{original}}{\text{original}}\cdot100 = \frac{11-10}{10}\cdot100 = \frac{1}{10} \cdot 100 = 10$ $\displaystyle \frac{\text{new}-\text{original}}{\text{original}}\cdot100 = \frac{11-10}{10}\cdot100 = \frac{1}{10} \cdot 100 = 10$

Therefore, the answer is a percent increase of $10\%$ $\displaystyle 10\%$.

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Example Question #1 : Finding Percent Change

In May of the past year, Harry's company made $\$189,281$ $\displaystyle \$189,281$ in profit, and in June of that same year, his company made $\$210,219$ $\displaystyle \$210,219$ in profit. By what percent did his profit increase from May to June?

Possible Answers:

$11.06\%$ $\displaystyle 11.06\%$

$8.76\%$ $\displaystyle 8.76\%$

$9.96\%$ $\displaystyle 9.96\%$

$13.81\%$ $\displaystyle 13.81\%$

Correct answer:

$11.06\%$ $\displaystyle 11.06\%$

Explanation:

To find percent change, use the following formula:

$\frac{\text{New Value - Old Value}}{\text{Old Value}}\times 100$ $\displaystyle \frac{\text{New Value - Old Value}}{\text{Old Value}}\times 100$

Our new value is the profit in June, $210,219. Our old value is the profit in May, $189,281.

$\frac{210219-189281}{189281}\times100=11.06\%$ $\displaystyle \frac{210219-189281}{189281}\times100=11.06\%$

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Basic Arithmetic : Increase

Study concepts, example questions & explanations for Basic Arithmetic

All Basic Arithmetic Resources

Example Questions

Example Question #1 : Finding Percent Change

Example Question #1 : Increase

Example Question #2 : Increase

Example Question #1 : Finding Percent Change

All Basic Arithmetic Resources

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