To tackle this question, first convert 2 and 3/4ths into a fraction.

$\displaystyle 2 \cdot \frac{4}{4} = \frac{8}{4}$

$\displaystyle \frac{8}{4} + \frac{3}{4} =\frac{11}{4}$

Then, you can subtract $\displaystyle 1/3$ from $\displaystyle 11/4$:

$\displaystyle \frac{11}{4} - \frac{1}{3} = ?$

$\displaystyle \frac{11\cdot3}{4 \cdot3} + \frac{1\cdot4}{3\cdot4} = ?$

$\displaystyle 33/12 - 4/12 = 29/12$

Then you convert to a mixed number for your final answer. 

$\displaystyle 29/12=$ $\displaystyle 2\frac{5}{12}$.  

To find the answer for this problem, first figure out how much of each pie is left:

$\displaystyle 3 - 3/4 = ?$

$\displaystyle 12/4 - 3/4 = 9/4$

Then, because $\displaystyle 4/4 = 1$, you know that you have $\displaystyle 2$ whole pies left, and a quarter besides.  

$\displaystyle \frac{9}{4}=2\frac{1}{4}$ 

To subtract fractions, they must have the same number in the denominator. Begin by simplifying $\displaystyle \frac{12}{36}$ so that its denominator is $\displaystyle 6$.

To simplify, divide the numerator and denominator by 6. 

$\displaystyle 12 \div6=2$

$\displaystyle 36\div6=6$

$\displaystyle \frac{12}{36}=\frac{2}{6}$

Then, subtract:

$\displaystyle \frac{5}{6}-\frac{2}{6}=\frac{3}{6}=\frac{1}{2}$

To solve this we need to first find common denominators. We do that by multiplying the first fraction by 2 over 2 and the second fraction by 3 over 3.

$\displaystyle \frac{2}{3}*\frac{2}{2}=\frac{4}{6}$

$\displaystyle \frac{1}{2}*\frac{3}{3}=\frac{3}{6}$

Subtract these fractions to get the final answer.

$\displaystyle \frac{4}{6}-\frac{3}{6}=\frac{1}{6}$

To solve this we need to first find common denominators. We do that by multiplying the first fraction by 3 over 3 and the second fraction by 5 over 5.

$\displaystyle \frac{4}{5}*\frac{3}{3}=\frac{12}{15}$

$\displaystyle \frac{1}{3}*\frac{5}{5}=\frac{5}{15}$

Subtract the numerators of the fractions to get the final answer.

$\displaystyle \frac{12}{15}-\frac{5}{15}=\frac{7}{15}$

To solve this we need to first find common denominators. We do that by multiplying the first fraction by 4 over 4 and the second fraction by 7 over 7.

$\displaystyle \frac{3}{7}*\frac{4}{4}=\frac{12}{28}$

$\displaystyle \frac{1}{4}*\frac{7}{7}=\frac{7}{28}$

Subtract the numerators of these fractions to get the final answer.

$\displaystyle \frac{12}{28}-\frac{7}{28}=\frac{5}{28}$

To solve this we need to first find common denominators. We do that by multiplying the first fraction by 9 over 9 and the second fraction by 8 over 8.

$\displaystyle \frac{1}{8}*\frac{9}{9}=\frac{9}{72}$

$\displaystyle \frac{1}{9}*\frac{8}{8}=\frac{8}{72}$

Subtract the numerators of these fractions to get the final answer.

$\displaystyle \frac{9}{72}-\frac{8}{72}=\frac{1}{72}$

To solve this we need to first find common denominators. We do that by multiplying the first fraction by 3 over 3 and the second fraction by 7 over 7.

$\displaystyle \frac{6}{7}*\frac{3}{3}=\frac{18}{21}$

$\displaystyle \frac{1}{3}*\frac{7}{7}=\frac{7}{21}$

Subtract the numerators of these fractions to get the final answer.

$\displaystyle \frac{18}{21}-\frac{7}{21}=\frac{11}{21}$

To get the reciprocal of a fraction, you simply switch the numerator and the denominator.

In our case our numerator is $\displaystyle 4$ and our denominator is $\displaystyle 7$.

So $\displaystyle \frac{4}{7}$ becomes $\displaystyle \frac{7}{4}$.

We will need to rewrite this in order to eliminate the negative exponent in the problem.  

Because the denominator has a negative exponent, that is the same as having a positive exponent in the numerator. Therefore we can rewrite the problem as follows and then multiply.

$\displaystyle \frac{x}{\left(2x)^{-2}\right } = x\cdot (2x)^2 = x\cdot4x^2 = 4x^3$