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AP Physics C: Mechanics : Calculating Weight

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Example Questions

Example Question #1 : Calculating Weight

The force on an object due to gravity on the moon is one-sixth of that found on Earth. What is the acceleration due to gravity on the moon?

Possible Answers:

$1.85\frac{m}{s^2}$ $\displaystyle 1.85\frac{m}{s^2}$

$0.16\frac{m}{s^2}$ $\displaystyle 0.16\frac{m}{s^2}$

$1.63\frac{m}{s^2}$ $\displaystyle 1.63\frac{m}{s^2}$

$2.32\frac{m}{s^2}$ $\displaystyle 2.32\frac{m}{s^2}$

Correct answer:

$1.63\frac{m}{s^2}$ $\displaystyle 1.63\frac{m}{s^2}$

Explanation:

We can use Newton's second law:

F=ma $\displaystyle F=ma$

Set up equations for the force on the moon and the force on Earth:

$F_m=ma_m,\ F_E=ma_E$ $\displaystyle F_m=ma_m,\ F_E=ma_E$

Now we can use substitution:

$F_m=\frac{1}{6}F_E$ $\displaystyle F_m=\frac{1}{6}F_E$

$\frac{1}{6}F_E=ma_m\rightarrow F_E=m(6a_m)$ $\displaystyle \frac{1}{6}F_E=ma_m\rightarrow F_E=m(6a_m)$

From this, we can see that $\displaystyle a_E=6a_m$. Using the acceleration due to gravity on Earth, we can find the acceleration due to gravity on the moon.

$9.8\frac{m}{s^2}=6a_m$ $\displaystyle 9.8\frac{m}{s^2}=6a_m$

$a_m=1.63\frac{m}{s^2}$ $\displaystyle a_m=1.63\frac{m}{s^2}$

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Example Question #101 : Ap Physics C

A large planet exerts a gravitational force five times stronger than that experienced on the surface of Earth. What is the weight of a 50kg object on this planet?

Possible Answers:

250N $\displaystyle 250N$

50N $\displaystyle 50N$

2450N $\displaystyle 2450N$

2675N $\displaystyle 2675N$

Correct answer:

2450N $\displaystyle 2450N$

Explanation:

The weight of the object on Earth's surface is:

$F_E=ma=(50kg)(9.8\frac{m}{s^2})=490N$ $\displaystyle F_E=ma=(50kg)(9.8\frac{m}{s^2})=490N$

The force on the new planet is five times that on Earth, so we can simply multiply:

$\displaystyle F=5(F_E)=5(490N)=2450N$

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Example Question #103 : Ap Physics C

A space woman finds herself in an unkown planet with gravity $5\frac{m}{s^2}$ $\displaystyle 5\frac{m}{s^2}$. If her weight on Earth is 500N, what is her weight on the unkown planet?

$g_{Earth}=10\frac{m}{s^2}$ $\displaystyle g_{Earth}=10\frac{m}{s^2}$

Possible Answers:

500 N $\displaystyle 500 N$

25 N $\displaystyle 25 N$

225 N $\displaystyle 225 N$

250 N $\displaystyle 250 N$

5 N $\displaystyle 5 N$

Correct answer:

250 N $\displaystyle 250 N$

Explanation:

We know that the weight of an object is given by:

w = mg $\displaystyle w = mg$

$\displaystyle m$ is the mass of the object and $\displaystyle g$ is the gravitational acceleration of whatever planet the object happens to be on.

We know the gravity on the unkown planet, so the weight of the woman is given by:

$w_{u}=mg_{u}$ $\displaystyle w_{u}=mg_{u}$

We need only to find the mass of the woman to solve the problem. Since the mass of the woman is constant, we can use the information about her weight on Earth to figure out her mass.

$m=\frac{w_{e}}{g_{e}}=\frac{500N}{10\frac{m}s^2{}}=50kg$ $\displaystyle m=\frac{w_{e}}{g_{e}}=\frac{500N}{10\frac{m}s^2{}}=50kg$

Use this mass to solve for her weight on the new planet.

$w_{u}=mg_{u}=(50kg)(5\frac{m}{s^2})=250N$ $\displaystyle w_{u}=mg_{u}=(50kg)(5\frac{m}{s^2})=250N$

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AP Physics C: Mechanics : Calculating Weight

Study concepts, example questions & explanations for AP Physics C: Mechanics

All AP Physics C: Mechanics Resources

Example Questions

Example Question #1 : Calculating Weight

Example Question #101 : Ap Physics C

Example Question #103 : Ap Physics C

All AP Physics C: Mechanics Resources

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