Call Now to Set Up Tutoring:

(888) 888-0446

AP Physics 2 : Quantum and Nuclear Physics

Study concepts, example questions & explanations for AP Physics 2

Create An Account

All AP Physics 2 Resources

6 Diagnostic Tests 149 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #31 : Radioactive Nuclear Decay

A new element is discovered named Banfordium. A test is run on a sample and finds it has an activity of $4.28*10^{13} Bq$ . Three years later, the same sample has an activity of $8.78*10^{12} Bq$ .

Determine the half-life of Banfordium.

Possible Answers:

$t_{\frac{1}{2}}=30yr$

$t_{\frac{1}{2}}=7.8yr$

$t_{\frac{1}{2}}=1.32yr$

$t_{\frac{1}{2}}=2.72yr$

$t_{\frac{1}{2}}=10yr$

Correct answer:

$t_{\frac{1}{2}}=1.32yr$

Explanation:

Calculate the decay constant:

$A=A_0e^{-\lambda t}$

Solve for $\lambda$

$\lambda=-ln{\frac{A}{A_0}}*\frac{1}{t}$

Plug in values:

$\lambda=-ln{\frac{8.7*10^{12}}{4.2*10^{13}}}*\frac{1}{3}$

$\lambda=\frac{.525}{year}$

Use the following relationship:

$t_{\frac{1}{2}}=\frac{ln2}{\lambda}$

Plugging in values

$t_{\frac{1}{2}}=\frac{ln2}{.525}$

$t_{\frac{1}{2}}=1.32yr$

Report an Error

Example Question #61 : Quantum And Nuclear Physics

A new element is discovered named Banfordium. A test is run on a sample and finds it has an activity of $4.28*10^{13} Bq$ . Three years later, the same sample has an activity of $8.78*10^{12} Bq$ .

Determine the number of Banfordium nuclei in a sample of activity $3.1*10^{13}Bq$

Possible Answers:

$1.15*10^{20}nuclei=N$

$6.72*10^{18}nuclei=N$

$8.55*10^{19}nuclei=N$

$3.41*10^{18}nuclei=N$

$7.77*10^{19}nuclei=N$

Correct answer:

$7.77*10^{19}nuclei=N$

Explanation:

Calculate the decay constant:

$A=A_0e^{-\lambda t}$

Solve for $\lambda$

$\lambda=-ln{\frac{A}{A_0}}*\frac{1}{t}$

Plug in values

$\lambda=-ln{\frac{8.7*10^{12}}{4.2*10^{13}}}*\frac{1}{3}$

$\lambda=\frac{.525}{year}$

Convert to $s^{-1}$

$\frac{.525}{year}*\frac{1 year}{365.25days}*\frac{1 day}{3600 s}=\frac{3.99*10^{-7}}{s}$

Use the following relationship:

$A=\lambda*N$

Plug in values and solve:

$3.1*10^{13}=3.99*10^{-7}*N$

$7.77*10^{19}nuclei=N$

Report an Error

Example Question #41 : Atomic And Nuclear Physics

A new element is discovered named Banfordium. A test is run on a sample and finds it has an activity of $4.28*10^{13} Bq$ . Three years later, the same sample has an activity of $8.78*10^{12} Bq$ .

Determine the activity of the sample 10 years after the initial test.

Possible Answers:

$2.2*10^{11}Bq$

$5.1*10^{11}Bq$

$4.3*10^{11}Bq$

$1.7*10^{11}Bq$

$8.5*10^{11}Bq$

Correct answer:

$2.2*10^{11}Bq$

Explanation:

Calculate the decay constant

Using

$A=A_0e^{-\lambda t}$

Solve for $\lambda$

$\lambda=-ln{\frac{A}{A_0}}*\frac{1}{t}$

Plug in values:

$\lambda=-ln{\frac{8.7*10^{12}}{4.2*10^{13}}}*\frac{1}{3}$

$\lambda=\frac{.525}{year}$

Use the following relationship:

$A=A_0e^{-\lambda t}$

Plug in values:

$A=4.2*10^{13}e^{-.525*10}$

$A=2.2*10^{11}Bq$

Report an Error

Example Question #62 : Quantum And Nuclear Physics

A sample of radioactive iodine is found to have decreased over time. After days, $18\:mg$ of radioactive iodine is found. Given that the half-life of radioactive iodine is 8.05 days, how much radioactive iodine was there initially?

Possible Answers:

$32.2\:mg$

$25.4\:mg$

$48.3\:mg$

$71.8\:mg$

$97.4\:mg$

Correct answer:

$25.4\:mg$

Explanation:

In this question, we're presented with a case in which a certain amount of radioactive iodine has decayed in a given amount of time. Based on the half-life, the amount of time that has passed, and the current amount of radioactive iodine, we're asked to solve for the initial amount of iodine.

First off, it's important to realize that this is a radioactive decay problem. All radioactive decay processes occur by a first-order reaction mechanism. Thus, we can go ahead and use the equation for first-order reactions:

$A_{t}=A_{0}e^{-kt}$

Rearranging to isolate the $A_{0}$ term, we obtain:

$A_{0}=A_{t}e^{kt}$

But before we start plugging in values, we'll need to calculate the term, which is the reaction rate constant. We can do this because we know that the reaction is first-order, and we're also provided with the half-life. Using the rate constant equation for a first-order reaction:

$k=-\frac{ln(\frac{1}{2})}{t_{\frac{1}{2}}}=\frac{0.693}{8.05\: days}=0.086\:days^{-1}$

Next, we can plug in the values given to us in order to solve for our answer:

$A_{0}=(18\: mg)e^{(0.086\: days^{-1})(4\: days)}$

$A_{0}=25.4\:mg$

Report an Error

Example Question #61 : Quantum And Nuclear Physics

The half life of $P^{238}$ is 88 years . Determine the radioactive decay constant.

Possible Answers:

$\frac{.458}{year}$

$\frac{.00115}{year}$

$\frac{.712}{year}$

$\frac{.00765}{year}$

$\frac{.00785}{year}$

Correct answer:

$\frac{.00785}{year}$

Explanation:

Use the following formula:

$t_{1/2}=\frac{ln(2))}{\lambda}$

Plug in values:

$88years=\frac{.693}{\lambda}$

$\lambda=\frac{.00785}{year}$

Report an Error

Example Question #41 : Atomic And Nuclear Physics

The half life of $P^{238}$ is 88 years . Determine the number of radioactive nuclei in a sample with an activity of 750Bq .

Possible Answers:

$1.26*10^{11}$

$5.55*10^{11}$

$7.23*10^{11}$

$3.91*10^{11}$

$3.33*10^{11}$

Correct answer:

$1.26*10^{11}$

Explanation:

Use the following formula:

$t_{1/2}=\frac{ln(2))}{\lambda}$

Plug in values:

$88years=\frac{.693}{\lambda}$

$\lambda=\frac{.00785}{year}$

Covert to $s^{-1}$

$\frac{.00785}{year}*\frac{1 year}{365.25 days}*\frac{1 day}{3600 s}=\frac{5.97*10^{-9}}{s}$

Use the relationship:

$A=\lambda N$

Plug in values:

$750=5.97*10^{-9} *N$

$N=1.26*10^{11}$

Report an Error

Example Question #41 : Atomic And Nuclear Physics

A sample is taken of a radioactive element. It has an activity of 1991 Bq . Two hours later, it has an activity of 28 Bq .

Determine the nuclear decay constant in terms of $min^{-1}$ .

Possible Answers:

$\frac{.0671}{min}$

None of these

$\frac{.0355}{min}$

$\frac{.0539}{min}$

$\frac{.0222}{min}$

Correct answer:

$\frac{.0355}{min}$

Explanation:

Determination of decay constant:

$A=A_0e^{-\lambda t}$

Solving for $\lambda$

$-ln(\frac{A}{A_0})*\frac{1}{t}=\lambda$

Converting hours to minutes and plugging in values:

$-ln(\frac{28}{1991})*\frac{1}{120}=\lambda$

$\frac{.0355}{min}=\lambda$

Report an Error

Example Question #42 : Atomic And Nuclear Physics

A sample is taken of a radioactive element. It has an activity of 1991 Bq . Two hours later, it has an activity of 28 Bq .

Determine the half life.

Possible Answers:

19.5min

None of these

32.4min

27.5min

12.3min

Correct answer:

19.5min

Explanation:

Determination of decay constant:

$A=A_0e^{-\lambda t}$

Solving for $\lambda$

$-ln(\frac{A}{A_0})*\frac{1}{t}=\lambda$

Converting hours to minutes and plugging in values:

$-ln(\frac{28}{1991})*\frac{1}{120}=\lambda$

$\frac{.0355}{min}=\lambda$

Using $t_{1/2}=\frac{ln(2)}{\lambda}$

$t_{1/2}=\frac{ln(2)}{.0355}$

$t_{1/2}=19.5min$

Report an Error

Example Question #39 : Radioactive Nuclear Decay

A sample is taken of a radioactive element. It has an activity of 1991 Bq . Two hours later, it has an activity of 28 Bq .

Determine the activity 30 minutes after the initial reading.

Possible Answers:

686Bq

711Bq

822Bq

305Bq

None of these

Correct answer:

686Bq

Explanation:

Determination of decay constant:

$A=A_0e^{-\lambda t}$

Solving for $\lambda$

$-ln(\frac{A}{A_0})*\frac{1}{t}=\lambda$

Converting hours to minutes and plugging in values:

$-ln(\frac{28}{1991})*\frac{1}{120}=\lambda$

$\frac{.0355}{min}=\lambda$

Again using

$A=A_0e^{-\lambda t}$

$A=1991e^{-.0355*30}$

A=686Bq

Report an Error

Example Question #401 : Ap Physics 2

A sample is taken of a radioactive element. It has an activity of 1991 Bq . Two hours later, it has an activity of 28 Bq .

Determine the number of radioactive atoms in the initial sample.

Possible Answers:

None of these

75000atoms

88000atoms

$3.36*10^{6}atoms$

196000atoms

Correct answer:

$3.36*10^{6}atoms$

Explanation:

Determination of decay constant:

$A=A_0e^{-\lambda t}$

Solving for $\lambda$

$-ln(\frac{A}{A_0})*\frac{1}{t}=\lambda$

Converting hours to seconds and plugging in values:

$-ln(\frac{28}{1991})*\frac{1}{7200}=\lambda$

$\frac{5.92*10^{-4}}{s}=\lambda$

Using $A=\lambda N$

Plugging in values:

$1991=5.92*10^{-4} N$

$N=3.36*10^{6}atoms$

Report an Error

View Tutors

Alex
Certified Tutor

Vanderbilt University, Bachelor of Science, Psychology. Boston University, Master of Science, Speech-Language Pathology.

View Tutors

Brandy
Certified Tutor

Southern State Community College, Associate in Science, Electromechanical Engineering. DeVry Institute of Technology, Bachelo...

View Tutors

Brandon
Certified Tutor

Ohio State University-Main Campus, Bachelor of Science, Chemistry. Ohio State University-Main Campus, Bachelor of Science, Bi...

All AP Physics 2 Resources

6 Diagnostic Tests 149 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Statistics Tutors in Los Angeles, French Tutors in Seattle, Calculus Tutors in Los Angeles, GRE Tutors in Philadelphia, Physics Tutors in Atlanta, GRE Tutors in Washington DC, LSAT Tutors in Philadelphia, Calculus Tutors in Atlanta, ISEE Tutors in Miami, MCAT Tutors in Philadelphia

Popular Courses & Classes

MCAT Courses & Classes in New York City, SAT Courses & Classes in Los Angeles, MCAT Courses & Classes in Seattle, ISEE Courses & Classes in Los Angeles, SSAT Courses & Classes in Houston, GMAT Courses & Classes in Boston, Spanish Courses & Classes in Los Angeles, SAT Courses & Classes in San Francisco-Bay Area, MCAT Courses & Classes in Atlanta, GRE Courses & Classes in New York City

Popular Test Prep

SAT Test Prep in Phoenix, ISEE Test Prep in Philadelphia, GMAT Test Prep in Seattle, ISEE Test Prep in Seattle, MCAT Test Prep in Chicago, SAT Test Prep in Seattle, ISEE Test Prep in Houston, SSAT Test Prep in Washington DC, MCAT Test Prep in San Diego, GMAT Test Prep in Phoenix

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

AP Physics 2 : Quantum and Nuclear Physics

Study concepts, example questions & explanations for AP Physics 2

All AP Physics 2 Resources

Example Questions

Example Question #31 : Radioactive Nuclear Decay

Example Question #61 : Quantum And Nuclear Physics

Example Question #41 : Atomic And Nuclear Physics

Example Question #62 : Quantum And Nuclear Physics

Example Question #61 : Quantum And Nuclear Physics

Example Question #41 : Atomic And Nuclear Physics

Example Question #41 : Atomic And Nuclear Physics

Example Question #42 : Atomic And Nuclear Physics

Example Question #39 : Radioactive Nuclear Decay

Example Question #401 : Ap Physics 2

All AP Physics 2 Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: