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AP Physics 2 : Optics

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Example Questions

Example Question #421 : Ap Physics 2

An object is set near a mirror like below.

Mirror2

At which point would the image be?

Possible Answers:

Correct answer:

Explanation:

If you were to draw a line from an object to its image on a flat mirror, the line would be perpendicular to the plane of the mirror. The distance from the image to the mirror would be the same distance from the mirror to the object. Only point A fits both criteria, as all other points aren't perpendicular with the mirror, and point E isn't the same distance either.

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Example Question #1 : Mirrors

You place a candle 4.12m away from a concave mirror with a radius of curvature of 0.53m . What is the image distance?

Possible Answers:

0.30m

1.34m

0.61m

1.61m

0.98m

Correct answer:

0.61m

Explanation:

For this problem, we use the mirror equation, rearraged to find .

$\frac{1}{f}&=\frac{1}{o}+\frac{1}{i}$

$\frac{1}{i}&=\frac{1}{f}-\frac{1}{o}$

$i&=(\frac{1}{f}-\frac{1}{o})^{-1}$

is the image location, is the object location, and is the focal point which is equal to the radius of curvature. Plugging in our known values:

$i&=(\frac{1}{f}-\frac{1}{o})^{-1}$

$i= (\frac{1}{0.53}-\frac{1}{4.12})^{-1}$

i= 0.61

Therefore, the image distance is 0.61m from the mirror. Remember, for concave mirrors, the image is on the same side as the object, and has a flipped orientation.

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Example Question #2 : Mirrors

An object is 42.1cm from a convex mirror with a radius of 11.3cm . What is the image distance?

Possible Answers:

-14.23cm

11.98cm

14.23cm

-8.91cm

8.91cm

Correct answer:

-8.91cm

Explanation:

For convex mirrors, the mirror equation is slightly different than for concave mirrors.

$\frac{1}{o}+\frac{1}{i}=-\frac{1}{f}$

Note the negative sign in front of the focal point. This is because a convex mirror is the same as a concave mirror pointing in the opposite direction.

Now, we rearrange the equation to solve for .

$-\frac{1}{f}&=\frac{1}{o}+\frac{1}{i}$

$\frac{1}{i}&=-\frac{1}{f}-\frac{1}{o}$

$i&=(-\frac{1}{f}-\frac{1}{o})^{-1}$

Now, we can plug in our numbers.

$i=(-\frac{1}{f}-\frac{1}{o})^{-1}$

$i= (-\frac{1}{0.113}-\frac{1}{0.421})^{-1}$

i= -0.0891m

Therefore, the image is at -8.91cm , which is on the concave side of the mirror.

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Example Question #2 : Mirrors

An object of height 5 cm is placed 10 cm in front of a convex mirror that has a radius of curvature of 45.0 cm .

Determine the size of the image.

Possible Answers:

h_i=12cm

h_i=9cm

h_i=18cm

h_i=3cm

h_i=6cm

Correct answer:

h_i=9cm

Explanation:

Use the mirror/lens equation:

$\frac{1}{p}+\frac{1}{i}=\frac{1}{f}=-\frac{2}{r}$

Where:

is the object distance from the mirror, which is taken to be negative number

is the image distance from the mirror

is the focal length of the mirror, which for convex mirrors is taken to be negative number

is the radius of curvature of the mirror

Plug in values:

$\frac{1}{-10}+\frac{1}{i}=\frac{1}{f}=-\frac{2}{45}$

Solve for :

$i=\frac{1}{-\frac{2}{45}+\frac{1}{10}}$

i=18cm

Use the equation for magnification:

$M=\frac{h_i}{h_p}=-\frac{i}{p}$

In this equation:

is magnification

h_i is image height

h_p is object height

Plug in values and solve for h_i :

$\frac{h_i}{5}=-\frac{18}{-10}$

h_i=9cm

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Example Question #2 : Mirrors

An object of height 7 cm is placed 4 cm in front of a concave mirror that has a radius of curvature of 25 cm . Determine the focal length of the mirror.

Possible Answers:

20cm

18cm

12.5cm

14.5cm

10cm

Correct answer:

12.5cm

Explanation:

Use the relationship for concave mirrors:

$\frac{1}{p}+\frac{1}{i}=\frac{1}{f}=\frac{2}{r}$

Where:

is the object distance from the mirror

is the image distance from the mirror

is the focal length of the mirror

is the radius of curvature of the mirror

Plug in values:

$\frac{1}{f}=\frac{2}{25}$

Solve for :

f=12.5cm

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Example Question #8 : Mirrors

An object of height 5 cm is placed 10 cm in front of a convex mirror that has a radius of curvature of 45.0 cm .

Determine the distance of the image.

Possible Answers:

i=28cm

i=18cm

i=5cm

i=11cm

i=9cm

Correct answer:

i=18cm

Explanation:

Use the mirror/lens equation:

$\frac{1}{p}+\frac{1}{i}=\frac{1}{f}=-\frac{2}{r}$

Where:

is the object distance from the mirror, which is taken to be negative

is the image distance from the mirror

is the focal length of the mirror, which is taken to be negative for convex mirrors

is the radius of curvature of the mirror

Plug in values:

$\frac{1}{-10}+\frac{1}{i}=\frac{1}{f}=-\frac{2}{45}$

Solve for the image distance:

$i=\frac{1}{-\frac{2}{45}+\frac{1}{10}}$

i=18cm

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Example Question #1 : Mirrors

An object of height 5 cm is placed 10 cm in front of a convex mirror that has a radius of curvature of 45.0 cm .

Determine the focal length of the mirror.

Possible Answers:

f=-18.5cm

f=-22.5cm

f=22.5cm

f=18.5cm

f=-26.5cm

Correct answer:

f=-22.5cm

Explanation:

Use the mirror/lens equation:

$\frac{1}{p}+\frac{1}{i}=\frac{1}{f}=-\frac{2}{r}$

Where:

is the object distance from the mirror, which is taken to be negative

is the image distance from the mirror

is the focal length of the mirror, which is taken to be negative for convex mirrors

is the radius of curvature of the mirror

Plug in values:

$\frac{1}{-10}+\frac{1}{i}=\frac{1}{f}=-\frac{2}{45}$

Solve for the focal length:

f=-22.5cm

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Example Question #1 : Mirrors

An object of height 5 cm is placed 10 cm in front of a concave mirror that has a radius of curvature of 37 cm .

Determine the magnification of the image.

Possible Answers:

M=2.5

M=3.75

M=5.25

M=6.5

M=1.75

Correct answer:

M=6.5

Explanation:

Use the mirror/lens equation:

$\frac{1}{p}+\frac{1}{i}=\frac{1}{f}=\frac{2}{r}$

Where:

is the object distance from the mirror, which is taken to be negative

is the image distance from the mirror

is the focal length of the mirror, which for concave mirrors is taken to be positive

is the radius of curvature of the mirror

Plug in values:

$\frac{1}{-10}+\frac{1}{i}=\frac{1}{f}=\frac{2}{37}$

Solve for the image distance:

$i=\frac{1}{-\frac{2}{37}+\frac{1}{10}}$

i=6.5cm

Use the magnification equation:

$M=\frac{h_i}{h_p}=-\frac{i}{p}$

Where

is magnification

h_i is image height

h_p is object height

Plug in values and solve for magnification:

$M=-\frac{6.5}{-10}$

M=6.5

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Example Question #431 : Ap Physics 2

An object of height 5 cm is placed 10 cm in front of a concave mirror that has a radius of curvature of 37 cm .

Determine the focal length of the mirror.

Possible Answers:

f=18.5cm

f=-10cm

f=-4cm

f=10cm

f=4cm

Correct answer:

f=18.5cm

Explanation:

Use the mirror/lens equation:

$\frac{1}{p}+\frac{1}{i}=\frac{1}{f}=\frac{2}{r}$

Where:

is the object distance from the mirror, which is taken to be negative

is the image distance from the mirror

is the focal length of the mirror, which for concave mirrors is taken to be positive

is the radius of curvature of the mirror

Plug in values and solve for the focal point:

$\frac{1}{-10}+\frac{1}{i}=\frac{1}{f}=\frac{2}{37}$

f=18.5cm

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Example Question #11 : Optics

An object of height 5 cm is placed 10 cm in front of a concave mirror that has a radius of curvature of 37 cm .

Determine the distance of the image.

Possible Answers:

i=8cm

i=1.5cm

i=6.5cm

i=4cm

i=10cm

Correct answer:

i=6.5cm

Explanation:

Use the mirror/lens equation:

$\frac{1}{p}+\frac{1}{i}=\frac{1}{f}=\frac{2}{r}$

Where:

is the object distance from the mirror, which is taken to be negative

is the image distance from the mirror

is the focal length of the mirror, which for concave mirrors is taken to be positive

is the radius of curvature of the mirror

Plug in values and solve for the image distance:

$\frac{1}{-10}+\frac{1}{i}=\frac{1}{f}=\frac{2}{37}$

$i=\frac{1}{-\frac{2}{37}+\frac{1}{10}}$

i=6.5cm

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AP Physics 2 : Optics

Study concepts, example questions & explanations for AP Physics 2

All AP Physics 2 Resources

Example Questions

Example Question #421 : Ap Physics 2

Example Question #1 : Mirrors

Example Question #2 : Mirrors

Example Question #2 : Mirrors

Example Question #2 : Mirrors

Example Question #8 : Mirrors

Example Question #1 : Mirrors

Example Question #1 : Mirrors

Example Question #431 : Ap Physics 2

Example Question #11 : Optics

All AP Physics 2 Resources

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