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AP Physics 2 : Fluid Statics

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Example Questions

Example Question #4 : Archimedes' Principle

A ball of mass 4kg $\displaystyle 4kg$ is lightly dropped into a tub with a base of 1m^2 $\displaystyle 1m^2$. After it sinks to the bottom, the water rises by 2.5mm $\displaystyle 2.5mm$. Determine the density of the ball.

Possible Answers:

$.40\frac{kg}{L}$ $\displaystyle .40\frac{kg}{L}$

$1.6\frac{kg}{L}$ $\displaystyle 1.6\frac{kg}{L}$

$.25\frac{kg}{L}$ $\displaystyle .25\frac{kg}{L}$

$4.4\frac{kg}{L}$ $\displaystyle 4.4\frac{kg}{L}$

None of these

Correct answer:

$1.6\frac{kg}{L}$ $\displaystyle 1.6\frac{kg}{L}$

Explanation:

The volume displaced will equal the volume of the ball.

V=B*h $\displaystyle V=B*h$

$\displaystyle V=1*.0025$

$\displaystyle V=.0025m^3$

$\rho=\frac{m}{V}$ $\displaystyle \rho=\frac{m}{V}$

$\rho=\frac{4 kg}{.0025m^3}$ $\displaystyle \rho=\frac{4 kg}{.0025m^3}$

$\rho=\frac{1600kg}{m^3}$ $\displaystyle \rho=\frac{1600kg}{m^3}$

$\frac{1600kg}{m^3}*\frac{1m^3}{100^3cm^2}*\frac{1000cm^3}{1L}=1.6\frac{kg}{L}$ $\displaystyle \frac{1600kg}{m^3}*\frac{1m^3}{100^3cm^2}*\frac{1000cm^3}{1L}=1.6\frac{kg}{L}$

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Example Question #71 : Fluid Statics

How much of an iceberg is submerged below the water if the density of ice is $917 \frac{\textup{kg}}{\textup{m}^3}$ $\displaystyle 917 \frac{\textup{kg}}{\textup{m}^3}$ and the density of water is $1000 \frac{\textup{kg}}{\textup{m}^3}$ $\displaystyle 1000 \frac{\textup{kg}}{\textup{m}^3}$?

Possible Answers:

Cannot be determined without knowing the mass of the iceberg.

$91.7 \%$ $\displaystyle 91.7 \%$

$8.3\%$ $\displaystyle 8.3\%$

$9.3\%$ $\displaystyle 9.3\%$

$109\%$ $\displaystyle 109\%$

Correct answer:

$91.7 \%$ $\displaystyle 91.7 \%$

Explanation:

The volume of the submerged mass is the volume of the mass proportional to the density of the solid to the density of the fluid.

$V_{sub}= V_{solid}(\frac{\rho_{solid}}{\rho_{fluid}})$ $\displaystyle V_{sub}= V_{solid}(\frac{\rho_{solid}}{\rho_{fluid}})$

Determine the amount of ice that is submerged.

$\frac{V_{sub}}{V_{solid}}= \frac{\rho_{solid}}{\rho_{fluid}}= \frac{917}{1000} = 91.7 \%$ $\displaystyle \frac{V_{sub}}{V_{solid}}= \frac{\rho_{solid}}{\rho_{fluid}}= \frac{917}{1000} = 91.7 \%$

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AP Physics 2 : Fluid Statics

Study concepts, example questions & explanations for AP Physics 2

All AP Physics 2 Resources

Example Questions

Example Question #4 : Archimedes' Principle

Example Question #71 : Fluid Statics

All AP Physics 2 Resources

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