AP Physics 1 : AP Physics 1

Study concepts, example questions & explanations for AP Physics 1

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Example Questions

Example Question #91 : Work, Energy, And Power

A spaceship of mass  is motionless in space. The rocket is turned on and provides a constant force of . Assume the loss of mass due to spent fuel is negligible.

Determine the kinetic energy of the ship after .

Possible Answers:

None of these

Correct answer:

Explanation:

Plugging in values

Using

Using

Example Question #93 : Newtonian Mechanics

Moment of inertia of a ring: 

A bicycle wheel has a mass of  and a radius of . Determine the total kinetic energy of the wheel if the bicycle is moving at . The wheel may be approximated as a hollow ring.

Possible Answers:

None of these

Correct answer:

Explanation:

Combining equations

Plugging in values:

 

Example Question #133 : Ap Physics 1

An object of mass  moves with velocity . How fast must an object of mass  move in order to have the same kinetic energy of the object of mass ?

Possible Answers:

Correct answer:

Explanation:

Kinetic energy is equal to . The object of mass  and velocity  therefore has kinetic energy equal to . Let's let the object of mass  have velocity . Therefore, its kinetic energy is . We want to find  such that the two objects to have the same kinetic energy, so we can equate their two kinetic energies. 

Example Question #91 : Work, Energy, And Power

If the velocity of an objects is halved, what is the resulting change in the kinetic energy?

Possible Answers:

No change.

Doubles

Quadrupled

Squared

Quartered

Correct answer:

Quartered

Explanation:

The equation for kinetic energy is:

, where  is the velocity of the object. Therefore, if we halve the velocity, we can substitute that into our equation, and see what will change in the kinetic energy equation:

Thus, the kinetic energy is quartered.

Example Question #92 : Newtonian Mechanics

What is the kinetic energy of an object of mass  traveling at ?

Possible Answers:

Correct answer:

Explanation:

To answer this question, we'll need to use the formula for kinetic energy.

Plugging in the values given to us, we can solve for our answer.

Example Question #92 : Work, Energy, And Power

An object has a mass, M, and a velocity, V.

What happens to the object's kinetic energy if its mass is doubled?

Possible Answers:

The object's kinetic energy is doubled.

The object's kinetic energy remains the same.

The object's kinetic energy is quadrupled.

The object's kinetic energy is halved.

The object's kinetic energy goes to zero.

Correct answer:

The object's kinetic energy is doubled.

Explanation:

The equation for kinetic energy is:

Where  is the object's kinetic energy,  is the object's, and  is the object's velocity.

We can see that the relationship between kinetic energy and mass is linear, so when the velocity is doubled, the kinetic energy is also doubled.

Example Question #93 : Work, Energy, And Power

An object has a mass, M, and a velocity, V.

What happens to the object's kinetic energy if its velocity is doubled?

Possible Answers:

The object's momentum remains the same.

The object's momentum is one fourth of its original momentum.

The object's momentum is doubled.

The object's momentum is halved.

The object's momentum is quadrupled.

Correct answer:

The object's momentum is quadrupled.

Explanation:

The equation for kinetic energy is:

Where  is the object's kinetic energy,  is the object's, and  is the object's velocity.

We can see that the relationship between kinetic energy and velocity is quadratic, so when the velocity is doubled, the kinetic energy is quadrupled.

Example Question #94 : Work, Energy, And Power

A ball with a mass of 3 kilograms is uniformly accelerated from rest and travels 110 meters in 6 seconds. What is its final kinetic energy in Joules after 6 seconds?

Possible Answers:

2012 Joules

1888 Joules

2300 Joules

1500 Joules

2017 Joules

Correct answer:

2017 Joules

Explanation:

Find the final velocity by multiplying the average velocity by 2. Then substitute into the equation for kinetic energy.

Example Question #1 : Gravitational Potential Energy

A lazy contractor of mass 80kg who is bricking a building figured out that a seesaw makes his life much easier. He needs to deliver bricks to his coworker who is 10 meters above him. The contractor puts bricks on one side of the seesaw and jumps on the other side to fling the bricks upward. If the contractor jumps onto the seesaw from a height of 1.5 meters, what is the maximum mass of bricks he can put on the seesaw that will reach his coworker?

Possible Answers:

Correct answer:

Explanation:

This problem can either be very simple or very complex.

You could convert the contractor's potential energy into kinetic energy, and then find the velocity at which he hits the seesaw. Then, use that to calculate the kinetic energy of the bricks and the height at which the bricks will fly. Although some may find that fun to do, it's unnecessary.

If we assume that all of the energy of the man is transferred to the bricks, we can use the conservation of energy equation:

We need to make a few clarifying statements for our initial and final states. In the initial state, the contractor is at a height of 1.5m and not moving. The bricks are not moving at this point either. In the final state, the man is on the ground not moving, and the bricks are at a height of 10m and not moving. Therefore, we can rewrite the above equation as the following:

Rearranging for the mass of the bricks:

Example Question #2 : Gravitational Potential Energy

A basketball player goes for a 3-point shot, but misses. The basketball has a mass of  and is traveling at  as it reaches its maximum height of . If the ball loses 15% of its total energy and half its horizontal velocity as it bounces off the rim of the hoop, what is the total velocity of the ball as it hits the ground?

Possible Answers:

Correct answer:

Explanation:

Using the equation for conservation of energy, we get:

Let's clarify that our initital state is when the ball is at its maximum height and the final state is when it reaches the ground. Plugging in our expressions and removing initial kinetic and final potential energy, we get:

Note that we removed initial kinetic energy despite the ball moving. At the initial state, all of the ball's velocity is horizontal. Since there is no vertical velocity, we can ignore it for now, coming back to it later.

We multiply the initial energy by 0.85 because the problem statement says that we lose 15% of the ball's total energy after hitting the rim. Rearranging for final velocity:

This is only the y-component of the final velocity. We need to combine this with the x-component to get the total velocity. The problem statement tells us that the final horizontal velocity is , therefore we can write:

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