Call Now to Set Up Tutoring:

(888) 888-0446

AP Physics 1 : AP Physics 1

Study concepts, example questions & explanations for AP Physics 1

Create An Account

All AP Physics 1 Resources

7 Diagnostic Tests 170 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1 : Waves And Velocity

A major earthquake about 600km off the coast of California occurs at 9:28 AM. If you are 800km from the epicenter and feel the earthquake at 10:43 AM, how fast are the waves traveling?

Possible Answers:

$178\frac{m}{s}$

$334\frac{m}{s}$

$414\frac{m}{s}$

$586\frac{m}{s}$

$275\frac{m}{s}$

Correct answer:

$178\frac{m}{s}$

Explanation:

To determine the velocity of the created waves, we need to know how quickly they cover a certain distance. The problem statement tells us that the covered distance is 800km. From the given time differences, we know that it takes 1 hour and 15 minutes to cover that distance. We will need to convert this to seconds:

$t = 75 min \left ( \frac{60s}{min}\right ) = 4500 s$

Now we can calculate the speed of the waves:

$v = \frac{d}{t}=\frac{800,000m}{4500 s} = 178\frac{m}{s}$

Report an Error

Example Question #4 : Waves And Velocity

On a piano, the note known as "middle C" has a frequency of roughly 262 hertz.

The coldest temperature ever recorded on Earth was $-89^{\circ}C$ . At this temperature, sound travels at $272\frac{m}{s}$ in air.

If Carol plays middle C on a piano at this temperature, what will the sound's wavelength be?

Possible Answers:

1.28m

0.96 m

1.04 m

1.40m

1.72m

Correct answer:

1.04 m

Explanation:

For any wave,

$v=\lambda f$

We know that the frequency of middle C is 262 hertz, and we also know that the speed of sound is $272\frac{m}{s}$ . Therefore:

$272 \frac{m}{s}=\lambda(262s^{-1})$

Solving for wavelength yields

$\lambda = 1.04m$

Report an Error

Example Question #3 : Waves And Velocity

A light wave has a wavelength of 0.5m . What is its frequency?

$c=3\cdot10^8\frac{m}{s}$

Possible Answers:

10^7Hz

$1.5\cdot 10^4Hz$

$2\cdot 10^9Hz$

$1.5\cdot 10^8Hz$

$6\cdot 10^8Hz$

Correct answer:

$6\cdot 10^8Hz$

Explanation:

The equation relaing velocity, wavelength, and frequency is:

$v = \lambda f$ .

Solving for frequency,

$3\cdot10^8\frac{m}{s} = 0.5m\cdot f$

$f = 6\cdot10^8 Hz$

Report an Error

Example Question #6 : Waves And Velocity

If we wanted to double wave velocity, but could only change frequency and wavelength by the same factor, by what factor would we have to change both frequency and wavelength?

Possible Answers:

We would have to change both frequency and wavelength by a factor of $\frac{1}{2}$

We would have to change both frequency and wavelength by a factor of $\sqrt 2$

We would have to change both frequency and wavelength by a factor of

Correct answer:

We would have to change both frequency and wavelength by a factor of $\sqrt 2$

Explanation:

Wave speed is related to wavelength and frequency by:

$v=\lambda f$ , where $\lambda$ is wavelength and is frequency.

If we wanted to change by 2, and change both $\lambda$ and by the same factor , we could set this up as:

$2v=a\lambda *af$

If we isolated just the factors by which we're changing the wave speed,

2=a^2

$\sqrt 2=a$

We'd have to change both wavelength and frequency by $\sqrt 2$

Report an Error

Example Question #1 : Waves And Velocity

What is the speed of light when passed through glass with an index of refraction of 2?

$c=3*10^8\frac{m}{s}$

Possible Answers:

$1.0*10^8 \frac{m}{s}$

$6.0*10^7 \frac{m}{s}$

$1.5*10^8 \frac{m}{s}$

$3.0*10^8 \frac{m}{s}$

Correct answer:

$1.5*10^8 \frac{m}{s}$

Explanation:

The equation for the speed of light through materials of different indices of refraction is given by the following equation:

$n=\frac{c}{v}$

Solve for velocity:

$v= \frac{3*10^8\frac{m}{s}}{2}= 1.5*10^8\frac{m}{s}$

Report an Error

Example Question #53 : Waves

waves are hitting the side of the pier in a regular fashion. waves hit the pier during 60s , and the waves are between crests, calculate the velocity of the waves.

Possible Answers:

$1.2\frac{m}{s}$

$2.3 \frac{m}{s}$

$4 \frac{m}{s}$

$0.58 \frac{m}{s}$

Correct answer:

$2.3 \frac{m}{s}$

Explanation:

We can calculate the velocity of a wave if we know the wavelength $\lambda$ and the frequency of the wave by the following equation,

$v = \lambda f$

We are told $\lambda = 4m$ , and can calculate the frequency

$f = \frac{35}{60s}=0.583 \frac{1}{s}$

Therefore, we can find the velocity of the waves,

$v = \lambda f = (4m)0.583\frac{1}{s}=2.3 \frac{m}{s}$

Report an Error

Example Question #1 : Waves And Velocity

A wave emitter is set to a frequency of $2450\textup{ MHz}$ . It is found that there is $6.0\textup{ cm}$ between anti-nodes of the waves created by this instrument. What is the speed of the waves as measured by this experiment?

Possible Answers:

$4.08*10^{10}\ \frac{\textup{m}}{\textup{s}}$

$1.47*10^{8}\ \frac{\textup{m}}{\textup{s}}$

$8.17*10^{10}\ \frac{\textup{m}}{\textup{s}}$

$2.94*10^{8}\ \frac{\textup{m}}{\textup{s}}$

$3.00*10^{8}\ \frac{\textup{m}}{\textup{s}}$

Correct answer:

$2.94*10^{8}\ \frac{\textup{m}}{\textup{s}}$

Explanation:

The distance between each anti-node in a standing wave is only half a wavelength, so we need to multiply the distance measured between anti-nodes by 2. Multiply the wavelength by the frequency to get the speed of the wave.

$v=\lambda f$

We need to remember to convert our centimeters to meters and our megaHertz to Hertz so the units work out:

$v=(2.450*10^{9}Hz)(.12m)$

$v= 2.94x10^{8}\frac{m}{s}$

Report an Error

Example Question #1 : Waves And Velocity

Determine the wavelength of a wave traveling through a material with tension 10N, a linear mass density of $\mu= 35\frac{kg}{m}$ , and frequency 10Hz.

Possible Answers:

0.053m

None of these

0.53m

$\frac{1}{70}m$

Correct answer:

0.053m

Explanation:

We need to utilize two equations for this question. The first of which is:

$v=\sqrt{\frac{T}{\mu}}$

Here, is wave speed, is tension force of the material, and $\mu$ is linear density. The othe equation we need to use is:

$v=\lambda f$

Here, is wave speed, $\lambda$ is wavelength and is frequency.

In our case:

$T=10N, \mu=35 \frac{kg}{m}$

plug in known values and solve for wave speed.

$v=\sqrt{\frac{10N}{35\frac{kg}{m}}}=0.5345\frac{m}{s}$

Solve the second equation for $\lambda$ .

$\lambda=\frac{v}{f}$

Plug in known values and solve for wavelength.

$\lambda=\frac{0.5345\frac{m}{s}}{10s^{-1}}=0.053m$

Report an Error

Example Question #1 : Longitudinal And Transverse Waves

At a local concert, a speaker is set up to produce low-pitched base sounds with a frequency range of 20Hz to 200Hz, which can be modeled as sine waves. In a simplified model, the sound waves the speaker produces can be modeled as a cylindrical pipe with one end closed that travel through the air at a velocity of $v = 331 \frac{m}{s} + 0.6\frac{m}{s}(T)$ , where T is the temperature in °C.

What type of waves are sound waves?

Possible Answers:

Transverse

Electromagnetic

Gravitational

Longitudinal

Correct answer:

Longitudinal

Explanation:

Sound waves are longitudinal waves, meaning that the waves propagate by compression and rarefaction of their medium. They are termed longitudinal waves because the particles in the medium through which the wave travels (air molecules in our case) oscillate parallel to the direction of motion. Alternatively, transverse waves oscillate perpendicular to the direction of motion. Common examples of transverse waves include light and, to a basic approximation, waves on the ocean.

Report an Error

Example Question #1 : Longitudinal And Transverse Waves

Which of these is an example of a longitudinal wave?

Possible Answers:

A wave produced by a rope oscillating in a plane

X-rays

Visible light

Microwaves

A sound wave

Correct answer:

A sound wave

Explanation:

Longitudinal waves transmit energy by compressing and rarefacting the medium in the same direction as they are traveling. Sounds waves are longitudinal waves and travel by compressing the air through which they travel, causing vibration.

Light, X-rays, and microwaves are all examples of electromagnetic waves; even if you cannot recall if they are longitudinal or transverse, they are all members of the same phenomenon and will have the same type of wave transmission. Transverse waves are generated by oscillation within a plane perpendicular to the direction of motion. Oscillating a rope is a transverse wave, as it is not compressing in the direction of motion.

Report an Error

View AP Physics 1 Tutors

Tahir
Certified Tutor

Cleveland State University, Master of Science, Electrical Engineering.

View AP Physics 1 Tutors

Clarke
Certified Tutor

University of Pittsburgh-Pittsburgh Campus, Bachelor of Science, Biological and Physical Sciences.

View AP Physics 1 Tutors

Meriza
Certified Tutor

Stella Maris College, India, Bachelor of Science, Physics. Loyola College, India, Master of Science, Physics.

All AP Physics 1 Resources

7 Diagnostic Tests 170 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Chemistry Tutors in Denver, Biology Tutors in Miami, Math Tutors in Atlanta, Reading Tutors in Houston, ACT Tutors in Miami, Math Tutors in Denver, Algebra Tutors in Chicago, Chemistry Tutors in Boston, Statistics Tutors in Denver, French Tutors in Phoenix

Popular Courses & Classes

ACT Courses & Classes in Houston, Spanish Courses & Classes in Boston, SSAT Courses & Classes in San Diego, GMAT Courses & Classes in Phoenix, MCAT Courses & Classes in Atlanta, LSAT Courses & Classes in Philadelphia, SAT Courses & Classes in Chicago, ACT Courses & Classes in Atlanta, ACT Courses & Classes in Philadelphia, SSAT Courses & Classes in Miami

Popular Test Prep

LSAT Test Prep in Philadelphia, GMAT Test Prep in Seattle, SAT Test Prep in Philadelphia, ACT Test Prep in Atlanta, ACT Test Prep in Houston, MCAT Test Prep in San Diego, ACT Test Prep in Washington DC, SAT Test Prep in San Diego, SSAT Test Prep in Miami, GMAT Test Prep in Chicago

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

AP Physics 1 : AP Physics 1

Study concepts, example questions & explanations for AP Physics 1

All AP Physics 1 Resources

Example Questions

Example Question #1 : Waves And Velocity

Example Question #4 : Waves And Velocity

Example Question #3 : Waves And Velocity

Example Question #6 : Waves And Velocity

Example Question #1 : Waves And Velocity

Example Question #53 : Waves

Example Question #1 : Waves And Velocity

Example Question #1 : Waves And Velocity

Example Question #1 : Longitudinal And Transverse Waves

Example Question #1 : Longitudinal And Transverse Waves

All AP Physics 1 Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: