To take the derivative of this equation, we can use the power rule. The power rule says that we lower the exponent of each variable by one and multiply that number by the original exponent.

Simplify.

Remember that anything to the zero power is equal to one.

To take the derivative of this equation, we can use the power rule. The power rule says that we lower the exponent of each variable by one and multiply that number by the original exponent.

We are going to treat  as  since anything to the zero power is one.

Notice that  since anything times zero is zero.

Simplify.

As stated before, anything to the zero power is one.

To find the first derivative, we can use the power rule. We lower the exponent on all the variables by one and multiply by the original variable.

Anything to the zero power is one.

To find the first derivative, we can use the power rule. We lower the exponent on all the variables by one and multiply by the original variable.

We're going to treat  as  since anything to the zero power is one.

For this problem that would look like this:

Notice that  since anything times zero is zero.

To find the first derivative, we can use the power rule. To do that, we lower the exponent on the variables by one and multiply by the original exponent.

We're going to treat  as  since anything to the zero power is one.

Notice that  since anything times zero is zero.

We use the power rule on each term of the function.

The first term

becomes

.

The second term

becomes

.

The final term, 7, is a constant, so its derivative is simply zero.

We are not going to evaluate this directly. Looking at the function, it seems very similar to the definition of a derivative of some kind of trigonometric function. We will look at the definition of a derivative to find a function that would have a derivative defined by this limit.

 In otherwords, we wish to identify a function  such that its' derivative  is the function . 

Let's find  such that: 

Compare corresponding terms in the numerators in the above expressions. 

By inspection, these terms clearly indicate that our function  must be of the form: 

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Side note

If your confused by the inclusion of the arbitrary constant , note that when we differentiate this function the constant term will vanish since the derivative of a constant is zero. You can also see that in applying the definition of a derivative, if I included the constant in the two terms in the numerator, 

the constant "C" would vanish when we subtract the latter from the former, . 

Therefore, even if you didn't consider the constant  when working out the function, it would not have changed the result

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Because we know that

 , 

Simply differentiate  to find , 

Therefore,

Or to put it another way, 

This limit can't be evaluated by conventional limit laws. To see why the answer is , we have to recognize that the limit looks like

, with .

This new limit is a conventional expression for , with  substituted in for 

We can find  with the power rule, and substituting  gives .

To summarize, since

, we have

.

There are two commonly used formulations of the difference quotient used to compute derviatives. Both definitions are equivalent and should always give the same derivative for a given function . 

The limit in this particular problem resembles the first difference quotient listed above. 

By inspection, it's clear that the  in our case must be . We are being asked to evaluate the limit by interpreting it as the definition of the derivative of a function. We must therefore identify the function, which is clearly ,  and then differentiate it using known rules of differentiation. 

First rewrite the function to apply the rule for :

This means 

The difference quotient of a function  is the expression

.

If , this expression is