All Algebra II Resources
Example Questions
Example Question #1993 : Algebra Ii
Simplify the expression:
Distribute the first term with the binomial.
Subtract the last term with this expression. Do not combine the terms as one unit. There are no like-terms, and the terms cannot simplified any further.
The answer is:
Example Question #151 : Basic Single Variable Algebra
Simplify the expression:
Multiply the first term with every term inside the parentheses.
Sum the terms.
Combine like-terms.
The answer is:
Example Question #61 : Simplifying Expressions
Simplify the following expression:
First, focus on the first term . By the rules for multiplying exponents,
.
Since , . Hence,
.
Now focus on the second term,. Since the exponent is negative, we must rewrite this expression as the reciprocal of the base to the positive power:
By the rules for multiplying exponents,
Since , . Hence,
.
Substituting these simplified terms into the original expression yields
.
Hence, is the correct answer.
Example Question #1994 : Algebra Ii
Simplify:
First, use the distributive property:
Now simplify by combining your like terms:
Therefore, your final answer is:
Example Question #61 : Simplifying Expressions
Simplify:
Distribute the outer term with both terms inside the parentheses.
When similar bases are multiplied, we can add the exponents of that base.
Simplify the terms.
Any term besides zero raised to the power of zero equals one.
The answer is:
Example Question #151 : Basic Single Variable Algebra
Given the expression , what must be the numerator of the simplified form?
To determine the number, we will need to find the least common denominator by multiplying all three denominators together.
Simplify the fractions.
The answer is:
Example Question #1995 : Algebra Ii
If and , what does equal?
Substitute the terms into the expression.
Simplify the terms by order of operation. Start with the inner parentheses.
The answer is:
Example Question #152 : Basic Single Variable Algebra
Simplify:
In order to simplified the expression, we will need to distribute the outer term through the terms inside the parentheses.
Distribute the terms.
The answer is:
Example Question #153 : Basic Single Variable Algebra
Simplify:
Simplify the complex fraction by parts.
Replace the terms.
Simplify the denominator. Convert the integer using the least common denominator, which is .
Replace this term in the denominator.
Rewrite this using a division sign.
Change the sign to multiplication and take the reciprocal of the second term.
Cancel the common terms.
The answer is:
Example Question #2001 : Algebra Ii
Evaluate if and .
The value of will need to be solved for. Subtract two from both sides given the following equation.
Divide by two on both sides.
Now that we know the value of a and b, we substitute both values in the expression .
The answer is:
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