Algebra II : Mathematical Relationships and Basic Graphs

Study concepts, example questions & explanations for Algebra II

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Example Questions

Example Question #311 : Exponents

Sheila wants to double her initial investment into a compounded interest account, with an interest rate of 4%. How long will this take, if the interest is compounded annually?

Possible Answers:

0.52 years

1.923 years

0.0565 years

17.67 years

Correct answer:

17.67 years

Explanation:

To determine the amount of time needed to double the initial investment - P - into a compound interest account, we simply plug in our given information into the formula:

where B is the balance, P is the initial investment, r is the interest rate (as a decimal), n is the number of times the interest is compounded, and t is the time elapsed.

Now, because we are doubling P, our balance B becomes two times P:

Now, we can solve for P:

To bring the time variable down from being an exponent, we take the logarithm of both sides (common or natural):

Example Question #312 : Exponents

If a person deposits 300 dollars to a savings account, which earns one percent interest that is compounded annually, what is the balance after 60 years?

Possible Answers:

Correct answer:

Explanation:

Write the formula for compound interest.

Substitute all the known values into the formula.

The answer is:  

Example Question #313 : Exponents

Suppose Billy's has , invests the money at a bank at , compounded monthly.  About how much will Billy have after 36 months?

Possible Answers:

Correct answer:

Explanation:

Write the compound interest formula.

where  is the total,  is the principal,  is the rate,  is the number of times compounded annually, and  is the time in years.

Substitute all into the equation.

The answer is:  

Example Question #314 : Exponents

Peter opens a savings account on his t birthday. He makes a deposit of . The account earns  percent interest, compounded annually.  Peter plans to take the money out when he is  years old.  If he doesn't make any deposits or withdrawals until then, how much money will be in the account?

Possible Answers:

Correct answer:

Explanation:

The formula for calculating compount interest is as follows:

where

= future value

= present value

= interest rate

= number of times the interest is compounded

In this problem, the present value of the money is $5000, and the interest rate is 7%. If Peter takes the money out when he is 50, it would have been compounded 29 times (once per year).  Therefore:

Example Question #1 : Radioactive Decay Equations

Over the past few years, the number of students enrolled at a certain university has been decreasing.  Each year there is a 12% decrease in student enrollement.  Currently, 14,286 students are enrolled.  If this trend continues, how many students will be enrolled in 5 years?

Possible Answers:

Correct answer:

Explanation:

This is an exponential decay problem.  The formula for exponential decay is:

Where

= future value

= present value

= rate of decay

= number of periods

This problem requests the number of students five years in the future.  The rate of decay is twelve percent.  Therefore:

Example Question #2 : Radioactive Decay Equations

Sceintists recently discovered a new type of metal compound. They have roughly 15 grams of this compound, which has a half life of 16 hours. Approximately how much of this substance will the scientists have in 24 hours?

Possible Answers:

 grams

grams

grams

grams

grams

Correct answer:

grams

Explanation:

 

Recall the radioactive decay formula:

The half life formula is:

, where  is the half life.

Plug in the given half life:

Plug this value into the radioactive decay formula:

grams

 

Example Question #1 : Radioactive Decay Equations

The equation for radioactive decay is,

 .

Where  is the original amount of a radioactive substance,  is the final amount,  is the half life of the substance, and  is time.

The half life of Carbon-14 is about  years. If a fossile contains  grams of Carbon-14 at time , how much Carbon-14 remains at time  years?

Possible Answers:

None of the other answers.

Correct answer:

Explanation:

Using the equation for radioactive decay, we get:

 

Example Question #3 : Radioactive Decay Equations

The number of fish in an aquarium is decreasing with exponential decay. The population of fish is decreasing by  each year. There are  fish in the aquarium today. If the decay continues how many fish will be in the aquarium in  years?

Possible Answers:

None of these answers are correct

Correct answer:

Explanation:

Every year the population of fish losses 7%. In other words, every year 93% of the fish remain from the previous year. Knowing this, we can use the original number of fish to find the number of fish for the next year. Since we want to know the number of fish 4 years from now, we multiply 1500 by 93% four times. 

Example Question #319 : Exponents

The population of a city is decreasing. The city has a population of , people today, but the population decreases by  every year. What will be the population of the city in  years if this continues?

Possible Answers:

Correct answer:

Explanation:

Because the population of the city is decreasing every year at 10.5% we can find the population after each year by using

Because this decrease will continue every year for the 6 years, we can continue to multiply the population by the decay for every year.

 

Example Question #4 : Radioactive Decay Equations

There is water leaking out of a cup.  of the water is leaking out every minute. How many kilograms of water will be left in  minutes and  seconds, if there are  kilograms of water ,, in the cup right now?

Possible Answers:

None of these answers are correct

 kilograms

 kilograms

 kilograms

Correct answer:

 kilograms

Explanation:

Because the water is leaking at a continuous rate, we can use the exponential decay equation.

 is the decay of the problem, 12% or 0.12.  is equal to how many times the water will have a 12% decay. This can be calculated as

To calculate this we must first convert both time to seconds

Our equation is then

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