Algebra II : Summations and Sequences

Study concepts, example questions & explanations for Algebra II

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Example Questions

Example Question #21 : Summations And Sequences

A sequence begins as follows:

Which statement is true?

Possible Answers:

The sequence may be arithmetic and geometric.

None of these

The sequence may be arithmetic.

The sequence cannot be arithmetic or geometric.

The sequence may be geometric.

Correct answer:

The sequence may be geometric.

Explanation:

An arithmetic sequence is one in which each term is generated by adding the same number - the common difference - to the previous term. As can be seen here, the difference between each term and the previous term varies from term to term:

The sequence cannot be arithmetic.

A geometric sequence is one in which each term is generated by multiplying the previous term by the same number - the common ratio. As can be seen here, the ratio of each term to the previous one is the same:

The sequence could be geometric.

Example Question #2681 : Algebra Ii

Find the sum for the first 25 terms in the series 

Possible Answers:

Correct answer:

Explanation:

Before we add together the first 25 terms, we need to determine the structure of the series. We know the first term is 60. We can find the common ratio r by dividing the second term by the first:

We can use the formula where A is the first term.

The terms we are adding together are so we can plug in :

Common mistakes would involve order of operations - make sure you do exponents first, then subtract, then multiply/divide based on what is grouped together.

 

Example Question #1 : Sigma Notation

What is the sum of the series?

Possible Answers:

11

17

13

15

Correct answer:

15

Explanation:

The number on the bottom is the first value we plug in for n. We keep substituting higher and higher integer values of n until we get to the top number (in this case, 5).

Here's what it looks like:

Example Question #21 : Mathematical Relationships And Basic Graphs

What is the sum of the series?

Possible Answers:

Correct answer:

Explanation:

Recall the formula for the sum of an infinite geometric series:

Of course, this formula only works if the series is geometric with a common ratio between -1 and 1.

While the sigma notation calls for substituting an infinite number of values for n, let's just substitute a few to see if we can find a pattern:

From this, we can see that we have a geometric series with a common ratio of 1/2 and a first term of 1/2.

Example Question #1 : Sigma Notation

Solve for  if  for  to 

Possible Answers:

Correct answer:

Explanation:

For summations, we evaluate the expression at each value of , then add all of the results together.

For this problem, we are working from  to .

Then adding everything up, we get 

Example Question #1 : Sigma Notation

Evaluate the following summation:

Possible Answers:

Correct answer:

Explanation:

According to the notation in the problem, we are told to sum the results obtained by evaluating the equation at each integer between the numbers below and above the sigma. For the sigma notation of this problem in particular, this means we start by plugging 1 into our equation, and then add the results obtained from plugging in 2, and then 3, and then 4, stopping after we add the result obatined from plugging 5 into the equation, as this is the number on top of sigma at which we stop the summation. This process is worked out below:

Example Question #1 : Sigma Notation

Evaluate:  

Possible Answers:

Correct answer:

Explanation:

The summation starts from 1 and ends at 5.  This can be rewritten as:

Example Question #1 : Sigma Notation

Evaluate: 

Possible Answers:

Correct answer:

Explanation:

The summation starts from 1 and ends at 5.  Rewrite the summation sign:

Example Question #1 : Sigma Notation

Evaluate:  

Possible Answers:

Correct answer:

Explanation:

Rewrite the summation starting from 1 to 5 and add the terms.

Example Question #1 : Sigma Notation

Evaluate:  

Possible Answers:

Correct answer:

Explanation:

The natural log domain is only valid for values greater than zero.  Therefore, the solution does not exist.

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