All Algebra II Resources
Example Questions
Example Question #11 : Setting Up Equations
If Bob's age is years old and Jack is more than times Bob's age, then express Jack's age in terms of .
Take every word and translate into math.
more than means that you need to add to something.
times something means that you need to multiply to Bob's age which is .
Now we can combine them to have an expression of .
Example Question #12 : Setting Up Equations
There are marbles in a jar. There are types of color: red, blue, green and yellow. There are red marbles, blue marbles, green marbles. Find an equation to represent the number of yellow marbles.
We have known values and unknown value. We have a total and that these colors add up to .
Let's represent the colors with variables corresponding to the first letter of the color. .
Now, plug in the values that are known. Final answer is .
To simplify we add the constants which results in:
Example Question #361 : Basic Single Variable Algebra
Express as an equation.
Difference between times and the quotient of and is more than times .
Take every word and translate into math. What a difference means, is that is the first number subtracting .
The part is times something means that you need to multiply to something which is .
The part is quotient.
Anytime you take a quotient of and , is the in the numerator and is in the denominator. Therefore the expression is .
Anytime you see "is" means equal.
more than means that you need to add to something.
That something is multipled by or .
Let's just combine them to have an expression of .
Example Question #14 : Setting Up Equations
Jon needs to make four monthly deposits. The first month, he deposits dollars. Each month after he adds dollars to the previous month's deposit. Find an equation to solve for if the total amount of money deposited for the four months is
Let's translate into math equations.
First month is Then for the next month, he adds to the previous month or Then, for the next month, he adds another to the previous month which was By adding another , this month becomes For the fourth month, it's just another added to the previous month which was The fourth month becomes .
With the total given, lets combine the expressions to get .
Simplifying this we get:
Example Question #15 : Setting Up Equations
Express as an equation.
The sum of and is .
Take every word and translate into math. The sum of something means adding. So that would be . Is means equals something. Putting it all together, we get .
Example Question #16 : Setting Up Equations
Express as an equation.
The difference between and is
Take every word and translate into math. Difference means subtracting. So we are subtracting and . Is means equal something. Putting it all together, we have .
Example Question #17 : Setting Up Equations
Express as an equation. The product of and is the sum of and .
Take every word and translate into math. The product of something means multiplying. So we have . The sum of something means adding. So that would be . Is means equals something. Putting it together, we have .
Example Question #361 : Basic Single Variable Algebra
Express as an equation. The quotient of and is the difference of and times sum of and .
Take every word and translate into math. Quotient means dividing, so we have . When it's and , will always be at the numerator of the fraction. Is means equal something. Difference is subtracting and we are subtracting with times sum of and . Times means multiplying and sum means addition. We are multiplying with . There must be parentheses as the sum of and is an expression. Putting it all together, we get .
Example Question #19 : Setting Up Equations
Express as an equation.
The square root of is the sum of and squared.
Take every word and translate into math. Square root means using a radical sign. So we have . Is means equal something. Next, sum is addition so we have . Since it's squared, we have the whole thing in parentheses raised to the second power like so: . It is tempting to think it's but if it was, then it should say sum of and square. So final answer is .
Example Question #363 : Basic Single Variable Algebra
Solve for in the following equation:
Starting with the equation , you want to collect like terms.
Put all of the numbers on one side, and leave only the variable on the other side.
The first step is to subtract from both sides.
You get .
The next step is to divide both sides by to get the final answer, .
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