Algebra 1 : Integer Operations

Study concepts, example questions & explanations for Algebra 1

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Example Questions

Example Question #61 : Real Numbers

Subtract fifty four from thirty one.

Possible Answers:

Correct answer:

Explanation:

Write an expression to express this question.  

This can be solved by taking a  out as a common factor and rearrange the terms inside the parentheses.

Simplify the terms inside the parentheses.

The answer is:  

Example Question #62 : Real Numbers

Subtract 154 from 233.

Possible Answers:

Correct answer:

Explanation:

Rewrite this as an expression.

Borrow a one from the tens digit of 233 and subtract the ones digits.

The tens digit of 233 is a two.

Borrow a one from the hundreds digit of 233 and subtract the tens digits.

The hundreds digit of 233 is now a one.

Subtract the hundreds digits.

Combine the digits from the calculations:  

The answer is:  

Example Question #63 : Real Numbers

Subtract: 

Possible Answers:

Correct answer:

Explanation:

Borrow a one from the tens digit of  to subtract the ones digits.

Subtract the ones digits.

Borrow a one from the hundreds digit of  to subtract the tens digits. The hundreds digit of  becomes a two.

Remember that the tens place of  is zero since we borrowed a one earlier to subtract the ones digits.

Subtract the tens digits.

Subtract the hundreds digits. The hundreds digit of  is two, and the hundreds digit of  is zero.

Combine the digits. 

The answer is:

Example Question #64 : Real Numbers

Subtract:  

Possible Answers:

Correct answer:

Explanation:

Borrow a one from the tens place of 78.

Subtract the ones digits.

Since we borrowed a one, the tens digit of 78 becomes a six.

Subtract the tens digits.

Combine the numbers.

The answer is:  

Example Question #65 : Real Numbers

Subtract the two numbers:  

Possible Answers:

 

Correct answer:

 

Explanation:

Borrow a one from the tens digit of 98, since we cannot subtract the ones digits.

The tens digit of 98 becomes an eight.

Subtract the ones digits.

Subtract the tens digits.  

Combine the digits.

The answer is:  

Example Question #66 : Real Numbers

Subtract the integers:  

Possible Answers:

Correct answer:

Explanation:

Subtract the ones digits.

Subtract the tens digits.

Subtract the hundreds digits.  The hundreds digit for 52 is zero.

Combine the numbers from the previous calculations.

The answer is:  

Example Question #61 : Integer Operations

Subtract the following integers:  

Possible Answers:

Correct answer:

Explanation:

Subtract the ones digits. There is no need to borrow a one from the tens digit.

Borrow a one from the hundreds digit to subtract the tens digits.

Subtract the tens digits.

Combine the numbers.

The answer is:  

Example Question #68 : Real Numbers

Subtract the numbers:  

Possible Answers:

Correct answer:

Explanation:

Subtract the ones digits.

Subtract the tens digits.

Borrow a one from the thousands place in order to subtract the hundreds digits.  The thousands digit will become zero.

Combine the numbers in order from hundreds place, tens place, and ones place.

The answer is:  

Example Question #69 : Real Numbers

Subtract the numbers:  

Possible Answers:

Correct answer:

Explanation:

Borrow a one from the tens place to subtract the ones digits.  The tens digit of 1093 is now eight.

We cannot borrow a one from the hundreds place to subtract eight with nine, so we will need to borrow a one from the thousands place instead.  The thousands place of 1093 is now zero, and the hundreds place becomes a nine.

Subtract the tens places.

Subtract the hundreds places.

Combine the hundreds, tens, and ones digits.

The answer is:  

Example Question #1 : How To Multiply Integers

Evaluate 5x + 3y when x = 7 and y = 9.

Possible Answers:

–62

62

–66

8

66

Correct answer:

62

Explanation:

Plug in 7 for x and 5 for y, giving you 5(7) + 3(9). This is equal to 35 + 27, which equals 62.

5x + 3y

5(7) + 3(9)

35 + 27 = 62

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