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Algebra 1 : How to solve absolute value equations

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Example Question #1 : How To Solve Absolute Value Equations

Solve the absolute value equation:

$\left | \frac{x-4}{3} \right| = \left | x +2 \right|$

Possible Answers:

$\small \left \{-5, -1 \right\}$

$\left \{-5, -\frac{1}{2} \right \}$

$\small \varnothing$ (no solution)

$\left \{-5 \right \}$

Correct answer:

$\left \{-5, -\frac{1}{2} \right \}$

Explanation:

An equation that equates two absolute value functions allows us to choose one of the absolute value functions and treat it as the constant. We then separate the equation into the "positive" version, $\tiny \small \frac{x-4}{3}=x+2$ , and the "negative" version, $\tiny \small \frac{x-4}{3} = -(x+2)$ . Solving each equation, we obtain the solutions, and $\tiny \tiny -\frac{1}{2}$ , respectively.

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Example Question #1 : How To Solve Absolute Value Equations

Solve for x.

|x+3|=4

Possible Answers:

x = –7, 1

x = –3, 4

x = 4, 7

x = 1, 7

No solution

Correct answer:

x = –7, 1

Explanation:

First, split into two possible scenarios according to the absolute value.

x+3=4

x+3=-4

Looking at , we can solve for x by subtracting 3 from both sides, so that we get x = 1.

Looking at x+3=-4 , we can solve for x by subtracting 3 from both sides, so that we get x = –7.

So therefore, the solution is x = –7, 1.

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Example Question #1 : How To Solve Absolute Value Equations

Find the solution to x for |x – 3| = 2.

Possible Answers:

2, 5

2, 4

1, 5

1, 4

Correct answer:

1, 5

Explanation:

|x – 3| = 2 means that it can be separated into x – 3 = 2 and x – 3 = –2.

So both x = 5 and x = 1 work.

x – 3 = 2 Add 3 to both sides to get x = 5

x – 3 = –2 Add 3 to both sides to get x = 1

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Example Question #1 : How To Solve Absolute Value Equations

Solve for x:

$\small \left | x+2 \right |=12$

Possible Answers:

$\small x=-10$

$\small x=14$ or $\small x=-10$

$\small x=-14$ or $\small x=10$

$\small x=10$

Correct answer:

$\small x=-14$ or $\small x=10$

Explanation:

Because of the absolute value signs,

$\small x+2=12$ or $\small x+2=-12$

Subtract 2 from both sides of both equations:

$\small x+2-2=12-2$ or $\small x+2-2=-12-2$

$\small x=10$ or $\small x=-14$

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Example Question #5 : How To Solve Absolute Value Equations

Solve for :

$|x-4|=\frac{5}{8}$

Possible Answers:

$x=4\frac{5}{8}, -3\frac{5}{8}$

$x=4\frac{3}{8}, -3\frac{3}{8}$

$x=4\frac{5}{8}$

$x=4\frac{5}{8}, -4\frac{3}{8}$

$x=4\frac{5}{8}, -3\frac{3}{8}$

Correct answer:

$x=4\frac{5}{8}, -3\frac{3}{8}$

Explanation:

$|x-4|=\frac{5}{8}$

There are two answers to this problem:

$x-4=\frac{5}{8}$

$x=\frac{5}{8}+4=4\frac{5}{8}$

and

$-(x-4)=\frac{5}{8}$

$4-x=\frac{5}{8}$

$-x=\frac{5}{8}-4=-3\frac{3}{8}$

$x=-3\frac{3}{8}$

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Example Question #6 : How To Solve Absolute Value Equations

If x = 2 , evaluate $\left | -4x + 3\right | \left | 3x-14\right |$ .

Possible Answers:

220

Correct answer:

Explanation:

An absolute value expression differs from a normal expression only in its sign. Instead of being a positive or negative quantity, an absolute value represents a scalar distance from zero, so it does not have a sign. For example, $\left | -2\right |$ is the same as $\left | 2\right |$ because both represent a value 2 units away from zero. In this problem, $\left | -4x + 3\right |$ equals $\left | -5 \right |$ , or 5. $\left | 3x - 14\right |$ equals 8. The final answer is (5)(8) or 40.

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Example Question #7 : How To Solve Absolute Value Equations

$\textup{If }\left | 2a-4\right |=8\,\textup{, what are all possible values of }a\textup{?}$

Possible Answers:

2, 6

-2, 6

-6, 6

0, 16

-6, 2

Correct answer:

-2, 6

Explanation:

$\textup{Set up two equations for absolute value equations:}$

$2a-4=8\; \; \; \; \; \; \; \; \; \; \; \; 2a-4=-8$

$2a=12\;\;\;\;\;\;\;\;\;\;\; \; \; \; \; \; \; 2a=-4$

$a=6\; \; \; \;\;\:\;\;\;\;\;\;\;\;\;\;\;\;\;\;a=-2$

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Example Question #8 : How To Solve Absolute Value Equations

What is the solution set of this equation?

$\left | 3x-7\right |+7 = -6$

Possible Answers:

$\O$

$\left \{ -6\tfrac{2}{3},2 \right \}$

$\left \{ -2, 6\tfrac{2}{3}\right \}$

$\left \{ 2, 6\tfrac{2}{3}\right \}$

$\mathbb{R}$

Correct answer:

$\O$

Explanation:

$\left | 3x-7\right |+7 = -6$

To find a solution, subtract first to isolate the absolute value expression.

$\left | 3x-7\right | = -13$

There is no value of that makes this true, as no number has a negative absolute value. The equation has no solution.

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Example Question #3 : How To Solve Absolute Value Equations

$Find \; all \;solutions\; for\;x \; in \;\left | 5x+3\right |-3=0$

Possible Answers:

$0,3,\, \frac{-6}{5}$

$\frac{-6}{5}$

$0,\, \frac{-6}{5}$

Correct answer:

$0,\, \frac{-6}{5}$

Explanation:

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Example Question #1 : How To Solve Absolute Value Equations

Solve for :

$\left | 4x+19 \right | = 31$

Possible Answers:

x = -3

x = -3 or x=3

x = 3

x = 3 or x = 12.5

x = -12.5 or x = 3

Correct answer:

x = -12.5 or x = 3

Explanation:

$\left | 4x+19 \right | = 31$ can be rewritten as the compound statement:

4x+19= - 31 or 4x+19= 31

Solve each separately to obtain the solution set:

4x+19= - 31

4x+19 - 19 = -31- 19

4x = -50

$4x \div 4= -50 \div 4$

x = -12.5

4x+19= 31

4x+19 - 19 = 31- 19

4x = 12

$4x \div 4= 12 \div 4$

x = 3

So either x = -12.5 or x = 3

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Algebra 1 : How to solve absolute value equations

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #1 : How To Solve Absolute Value Equations

Example Question #1 : How To Solve Absolute Value Equations

Example Question #1 : How To Solve Absolute Value Equations

Example Question #1 : How To Solve Absolute Value Equations

Example Question #5 : How To Solve Absolute Value Equations

Example Question #6 : How To Solve Absolute Value Equations

Example Question #7 : How To Solve Absolute Value Equations

Example Question #8 : How To Solve Absolute Value Equations

Example Question #3 : How To Solve Absolute Value Equations

Example Question #1 : How To Solve Absolute Value Equations

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