Call Now to Set Up Tutoring:

(888) 888-0446

Algebra 1 : How to find the midpoint of a line segment

Study concepts, example questions & explanations for Algebra 1

Create An Account

All Algebra 1 Resources

10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #12 : Midpoint Formula

What is the midpoint of a line with endpoints of (-10,14) and (4,2) ?

Possible Answers:

(-3,8)

(-7,-6)

(7,6)

None of the other answers

(3,-8)

Correct answer:

(-3,8)

Explanation:

To find the midpoint, use the midpoint formula: $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$ . Plug in the two ordered pairs to the formula to get: $(\frac{-10+4}{2},\frac{14+2}{2})$ . Doing this will give you a solution of (-3,8) .

Report an Error

Example Question #841 : Functions And Lines

A line segment on the coordinate plane has endpoints (-5,-4) and (-3,10) . Which quadrant or axis contains its midpoint?

Possible Answers:

Quadrant IV

Quadrant II

The -axis

Quadrant III

Quadrant I

Correct answer:

Quadrant II

Explanation:

The -coordinate of the midpoint is

$\frac{-5 + (-3) }{2} = -4$ ,

which is negative.

The -coordinate of the midpoint is

$\frac{-4+10}{2} =3$ ,

which is positive.

Since the midpoint has a negative -coordinate and a positive -coordinate, the midpoint is in Quadrant II.

Report an Error

Example Question #11 : How To Find The Midpoint Of A Line Segment

A line segment on the coordinate plane has endpoints (5,-4) and (-3,7) . Which quadrant or axis contains its midpoint?

Possible Answers:

Quadrant IV

Quadrant I

Quadrant II

The -axis

Quadrant III

Correct answer:

Quadrant I

Explanation:

The -coordinate of the midpoint is

$\frac{5 + (-3) }{2} = 1$ ,

which is positive.

The -coordinate of the midpoint is

$\frac{-4+7}{2} = \frac{3}{2}$ ,

which is positive.

Since both coordinates are positive, the midpoint is in Quadrant I.

Report an Error

Example Question #843 : Functions And Lines

Determine the midpoint between the points (-1, 5) and (-7, 3)

Possible Answers:

(-8, 8)

(-4, 4)

(-5, 4)

(-2, 4)

(4, -4)

Correct answer:

(-4, 4)

Explanation:

To find the midpoint you are actually finding the average of the two values and the average of the two values.

Midpoint formula: $(\frac{x_{1}+x_{2}}{2}), (\frac{y_{1}+y_{2}}{2})$

(-1, 5) , (-7, 3) so we plug our points in to the equation,

$(\frac{-1+(-7)}{2}, \frac{5+3}{2})$

Simplify and divide

$(\frac{-8}{2},\frac{8}{2})$

Midpoint: (-4,4)

Report an Error

Example Question #851 : Functions And Lines

Find the midpoint of the line segment with endpoints (1.6, 7.3) and ( -1.4, 4.7) .

Possible Answers:

(0.1, 6)

(1.5, 6)

$\left ( 4.45, 1.65\right )$

$\left ( 6, 0.1\right )$

(-1.5,-6)

Correct answer:

(0.1, 6)

Explanation:

Use the midpoint formula:

$\left ( \frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}} \right )$

Substitute:

$\frac{x_{1}+x_{2}}{2} =\frac{1.6+(-1.4)}{2} = \frac{0.2}{2} = 0.1$

$\frac{y_{1}+y_{2}}{2}} \right = \frac{7.3+4.7)}{2}} = \frac{12}{2} = 6$

The midpoint is (0.1, 6)

Report an Error

Example Question #852 : Functions And Lines

Find the midpoint of the line segment with endpoints $\left ( \frac{1}{3}, \frac{5}{6} \right )$ and $\left ( -\frac{5}{6},\frac{2}{3} \right )$ .

Possible Answers:

$\left ( \frac{7 }{12}, -\frac{1 }{12} \right )$

$\left ( -\frac{1 }{4}, \frac{3 }{4} \right )$

$\left ( -\frac{1 }{2}, \frac{3 }{2} \right )$

$\left ( \frac{1 }{4}, \frac{3 }{4} \right )$

$\left ( -\frac{7 }{12}, \frac{1 }{12} \right )$

Correct answer:

$\left ( -\frac{1 }{4}, \frac{3 }{4} \right )$

Explanation:

Use the midpoint formula:

$\left ( \frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}} \right )$

Substitute:

$\frac{x_{1}+x_{2}}{2} = \frac{ \frac{1}{3} + \left (-\frac{5}{6} \right )}{2}= \frac{ \frac{2}{6} - \frac{5}{6} }{2}= \frac{-\frac{3}{6}}{2}= \frac{-\frac{1}{2}}{2} = -\frac{1}{2} \div 2 = -\frac{1}{2} \cdot\frac{1}{2} =-\frac{1}{4}$

$\frac{y_{1}+y_{2}}{2} = \frac{ \frac{5}{6} + \frac{2}{3}}{2} = \frac{ \frac{5}{6} + \frac{4}{6}}{2} = \frac{ \frac{9}{6} }{2}= \frac{ \frac{3}{2} }{2} = \frac{3}{2} \div 2 = \frac{3}{2} \cdot \frac{1}{2} = \frac{3}{4}$

The midpoint is $\left ( -\frac{1 }{4}, \frac{3 }{4} \right )$ .

Report an Error

Example Question #11 : How To Find The Midpoint Of A Line Segment

What is the midpoint of a line with endpoints of (9,-3) and (-1,5) ?

Possible Answers:

(4,1)

(1,4)

(-1,4)

(-4,-1)

(4,-1)

Correct answer:

(4,1)

Explanation:

To find the midpoint, you can use the midpoint formula: $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$ .

Plug in (9,-3) and (-1, 5) into the formula: $(\frac{9+-1}{2},\frac{-3+5}{2})$ to get (4,1) .

Report an Error

Example Question #2 : Midpoint Formula

Find the midpoint of the line segment with endpoints (3.6, 9.1) and (7.2, -1.5) .

Possible Answers:

$\left (1.8, -5.3 \right )$

$\left (-1.8, 5.3 \right )$

(3.8, 5.4)

(5.4, 3.8)

$\left (6.35, 2.85 \right )$

$\left (-1.8, 5.3 \right )$

$\left (1.8, -5.3 \right )$

$\left (6.35, 2.85 \right )$

Correct answer:

(5.4, 3.8)

Explanation:

Use the midpoint formula:

$\left ( \frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}} \right )$

Substitute:

$\frac{x_{1}+x_{2}}{2} =\frac{3.6+7.2}{2} = \frac{10.8}{2} = 5.4$

$\frac{y_{1}+y_{2}}{2}} \right = \frac{9.1+(-1.5)}{2}} = \frac{7.6}{2} = 3.8$

The midpoint is (5.4, 3.8)

Report an Error

Example Question #12 : How To Find The Midpoint Of A Line Segment

What is the midpoint of a line with endpoints (2,5) and (18,-9)?

Possible Answers:

(6,0)

(-2,10)

(-4,20)

(20,-4)

(10,-2)

Correct answer:

(10,-2)

Explanation:

To find the midpoint of the line, plug the endpoints into the distance formula: $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$ . This will give you $(\frac{2+18}{2},\frac{5+-9}{2})$ , or a midpoint of (10,-2) .

Report an Error

Example Question #4141 : Algebra 1

What is the midpoint of a line with endpoints of (12,3) and (28,9)?

Possible Answers:

(20,6)

(8,3)

(8,6)

(20,3)

(12, 8)

Correct answer:

(20,6)

Explanation:

To find the midpoint of a line, plug the endpoints into the midpoint formula:

$\left(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2}\right)$

This gives you

$\left(\frac{12+28}{2},\frac{3+9}{2}\right)$

(20,6)

Report an Error

View Algebra Tutors

Tajrin
Certified Tutor

CUNY Brooklyn College, Bachelor of Science, Computer Science.

View Algebra Tutors

Kansiyochukwu
Certified Tutor

University of Calgary, Bachelor of Science, Electromechanical Engineering.

View Algebra Tutors

Abhisek
Certified Tutor

University of Florida, Bachelor of Engineering, Computer Science.

All Algebra 1 Resources

10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

LSAT Tutors in Dallas Fort Worth, GMAT Tutors in Los Angeles, French Tutors in Washington DC, French Tutors in Dallas Fort Worth, Spanish Tutors in Chicago, Spanish Tutors in Washington DC, Physics Tutors in Houston, ISEE Tutors in Miami, GRE Tutors in Miami, French Tutors in Boston

Popular Courses & Classes

MCAT Courses & Classes in Boston, GMAT Courses & Classes in Philadelphia, ISEE Courses & Classes in Boston, GRE Courses & Classes in Denver, GRE Courses & Classes in Seattle, LSAT Courses & Classes in Los Angeles, GRE Courses & Classes in Houston, LSAT Courses & Classes in San Diego, Spanish Courses & Classes in Philadelphia, GMAT Courses & Classes in Phoenix

Popular Test Prep

LSAT Test Prep in Washington DC, GMAT Test Prep in Miami, SAT Test Prep in Philadelphia, SSAT Test Prep in Washington DC, ISEE Test Prep in Washington DC, ISEE Test Prep in San Francisco-Bay Area, GMAT Test Prep in Phoenix, GRE Test Prep in Phoenix, GRE Test Prep in Denver, GMAT Test Prep in Chicago

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Algebra 1 : How to find the midpoint of a line segment

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #12 : Midpoint Formula

Example Question #841 : Functions And Lines

Example Question #11 : How To Find The Midpoint Of A Line Segment

Example Question #843 : Functions And Lines

Example Question #851 : Functions And Lines

Example Question #852 : Functions And Lines

Example Question #11 : How To Find The Midpoint Of A Line Segment

Example Question #2 : Midpoint Formula

Example Question #12 : How To Find The Midpoint Of A Line Segment

Example Question #4141 : Algebra 1

All Algebra 1 Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: