To find the midpoint, use the midpoint formula: $\displaystyle (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$. Plug in the two ordered pairs to the formula to get: $\displaystyle (\frac{-10+4}{2},\frac{14+2}{2})$. Doing this will give you a solution of $\displaystyle (-3,8)$.

The $\displaystyle x$-coordinate of the midpoint is 

$\displaystyle \frac{-5 + (-3) }{2} = -4$,

which is negative.

The $\displaystyle y$-coordinate of the midpoint is 

$\displaystyle \frac{-4+10}{2} =3$,

which is positive.

Since the midpoint has a negative $\displaystyle x$-coordinate and a positive $\displaystyle y$-coordinate, the midpoint is in Quadrant II.

The $\displaystyle x$-coordinate of the midpoint is 

$\displaystyle \frac{5 + (-3) }{2} = 1$,

which is positive.

The $\displaystyle y$-coordinate of the midpoint is 

$\displaystyle \frac{-4+7}{2} = \frac{3}{2}$,

which is positive.

Since both coordinates are positive, the midpoint is in Quadrant I.

To find the midpoint you are actually finding the average of the two $\displaystyle x$ values and the average of the two $\displaystyle y$ values. 

Midpoint formula: $\displaystyle (\frac{x_{1}+x_{2}}{2}), (\frac{y_{1}+y_{2}}{2})$

$\displaystyle (-1, 5)$, $\displaystyle (-7, 3)$ so we plug our points in to the equation, 

$\displaystyle (\frac{-1+(-7)}{2}, \frac{5+3}{2})$

Simplify and divide

$\displaystyle (\frac{-8}{2},\frac{8}{2})$

Midpoint: $\displaystyle (-4,4)$

Use the midpoint formula:

 $\displaystyle \left ( \frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}} \right )$

Substitute:

$\displaystyle \frac{x_{1}+x_{2}}{2} =\frac{1.6+(-1.4)}{2} = \frac{0.2}{2} = 0.1$

$\displaystyle \frac{y_{1}+y_{2}}{2}} \right = \frac{7.3+4.7)}{2}} = \frac{12}{2} = 6$

The midpoint is $\displaystyle (0.1, 6)$

Use the midpoint formula:

 $\displaystyle \left ( \frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}} \right )$

Substitute:

$\displaystyle \frac{x_{1}+x_{2}}{2} = \frac{ \frac{1}{3} + \left (-\frac{5}{6} \right )}{2}= \frac{ \frac{2}{6} - \frac{5}{6} }{2}= \frac{-\frac{3}{6}}{2}= \frac{-\frac{1}{2}}{2} = -\frac{1}{2} \div 2 = -\frac{1}{2} \cdot\frac{1}{2} =-\frac{1}{4}$

$\displaystyle \frac{y_{1}+y_{2}}{2} = \frac{ \frac{5}{6} + \frac{2}{3}}{2} = \frac{ \frac{5}{6} + \frac{4}{6}}{2} = \frac{ \frac{9}{6} }{2}= \frac{ \frac{3}{2} }{2} = \frac{3}{2} \div 2 = \frac{3}{2} \cdot \frac{1}{2} = \frac{3}{4}$

The midpoint is $\displaystyle \left ( -\frac{1 }{4}, \frac{3 }{4} \right )$.

To find the midpoint, you can use the midpoint formula: $\displaystyle (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$.

Plug in $\displaystyle (9,-3)$ and $\displaystyle (-1, 5)$ into the formula: $\displaystyle (\frac{9+-1}{2},\frac{-3+5}{2})$ to get $\displaystyle (4,1)$.

Use the midpoint formula:

 $\displaystyle \left ( \frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}} \right )$

Substitute:

$\displaystyle \frac{x_{1}+x_{2}}{2} =\frac{3.6+7.2}{2} = \frac{10.8}{2} = 5.4$

$\displaystyle \frac{y_{1}+y_{2}}{2}} \right = \frac{9.1+(-1.5)}{2}} = \frac{7.6}{2} = 3.8$

The midpoint is $\displaystyle (5.4, 3.8)$

To find the midpoint of the line, plug the endpoints into the distance formula: $\displaystyle (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$. This will give you $\displaystyle (\frac{2+18}{2},\frac{5+-9}{2})$, or a midpoint of $\displaystyle (10,-2)$.

To find the midpoint of a line, plug the endpoints into the midpoint formula: 

$\displaystyle \left(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2}\right)$

This gives you 

$\displaystyle \left(\frac{12+28}{2},\frac{3+9}{2}\right)$

or 

$\displaystyle (20,6)$