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Algebra 1 : Algebra 1

Study concepts, example questions & explanations for Algebra 1

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10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #2 : Simplifying And Expanding Quadratics

Multiply: $(x^{2} + 3) (4x - 1)$

Possible Answers:

$4x^{3} +x^{2} -12x - 3$

$4x^{3} + 3$

$4x^{3} -x^{2} +12x - 3$

$4x^{3} - 3$

$4x^{3} -x^{2} -12x + 3$

Correct answer:

$4x^{3} -x^{2} +12x - 3$

Explanation:

$(x^{2} + 3) (4x - 1)$

$= x^{2} (4x - 1) + 3(4x - 1)$

$= x^{2} \cdot 4x - x^{2} \cdot 1 + 3 \cdot 4x - 3 \cdot 1$

$= 4x^{3} - x^{2} + 12x - 3$

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Example Question #2 : Simplifying And Expanding Quadratics

Multiply: $(x + 4) (x^{2} -4x + 16)$

Possible Answers:

$x^{3}- 12x - 64$

$x^{3}- 20x + 64$

$x^{3}- 12x + 64$

$x^{3} - 64$

$x^{3} + 64$

Correct answer:

$x^{3} + 64$

Explanation:

$(x + 4) (x^{2} -4x + 16)$

$= x (x^{2} -4x + 16)+ 4 (x^{2} -4x + 16)$

$= x \cdot x^{2} -x \cdot 4x + x \cdot 16+ 4 \cdot x^{2} -4 \cdot 4x + 4 \cdot 16$

$= x^{3} -4x^{2} + 16x+ 4 x^{2} -16x + 64$

$= x^{3} -4x^{2} + 4 x^{2} + 16x -16x + 64$

$= x^{3} + 64$

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Example Question #127 : Basic Single Variable Algebra

Multiply: $(x -5) (x^{2} +5x + 25)$

Possible Answers:

$x^{3} -20x +125$

$x^{3} +125$

$x^{3} -20x -125$

$x^{3} -125$

$x^{3} -20x^{2} -125$

Correct answer:

$x^{3} -125$

Explanation:

$(x -5) (x^{2} +5x + 16)$

$= x (x^{2} +5x + 25)-5 (x^{2} +5x + 25)$

$= x \cdot x^{2} +x \cdot 5x + x \cdot 25-5 \cdot x^{2} -5 \cdot 5x -5 \cdot 25$

$= x^{3} +5x^{2} +25x-5 x^{2} -25x -125$

$= x^{3} +5x^{2} -5 x^{2} +25x -25x -125$

$= x^{3} -125$

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Example Question #22 : Intermediate Single Variable Algebra

Write as a polynomial in standard form: $(3x - 2y)^{3}$

Possible Answers:

$27x^{3} - 18 x^{2} y + 12 xy^{2} - 8y^{3}$

$27x^{3} - 54 x^{2} y + 36 xy^{2} - 8y^{3}$

$27x^{3} - 8y^{3}$

$27x^{3} + 18 x^{2} y - 12 xy^{2} - 8y^{3}$

$27x^{3} + 54 x^{2} y - 36 xy^{2} - 8y^{3}$

Correct answer:

$27x^{3} - 54 x^{2} y + 36 xy^{2} - 8y^{3}$

Explanation:

$(A -B)^{3} = A^{3} - 3A^{2} B + 3AB^{2} - B^{3}$

Replace: A = 3x, B = 2y :

$(3x -2y)^{3}$

$= (3x)^{3} - 3 (3x) ^{2} (2y) + 3 (3x) (2y)^{2} - (2y)^{3}$

$= 3^{3}x^{3} - 3 \cdot 3^{2} \cdot 2 \cdot x^{2} y + 3 \cdot 3 \cdot 2^{2} \cdot xy^{2} - 2^{3}y^{3}$

$= 27x^{3} - 54 x^{2} y + 36 xy^{2} - 8y^{3}$

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Example Question #101 : Polynomials

Multiply: (x - 4)(x+ 4) (x -7)

Possible Answers:

$x^{3} + 112$

$x^{3} - 7x^{2} - 16x + 112$

$x^{3} -23x^{2} + 112$

$x^{3} + 7x^{2} - 16x - 112$

$x^{3} -23x + 112$

Correct answer:

$x^{3} - 7x^{2} - 16x + 112$

Explanation:

The first two factors are the product of the sum and the difference of the same two terms, so we can use the difference of squares:

(x - 4)(x+ 4) (x -7)

$= (x^{2} - 4^{2}) (x -7)$

$= (x^{2} - 16) (x -7)$

Now use the FOIL method:

$= x^{2}\cdot x - x^{2} \cdot 7 - 16 \cdot x + 16 \cdot7$

$= x^{3} - 7x^{2} - 16x + 112$

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Example Question #345 : Exponents

Simplify the expression.

y^2z^3y^4z^5y^6

Possible Answers:

$y^{15}z^3$

$y^9z^{11}$

$y^{10}z^8$

$y^{12}z^{10}$

$y^{12}z^8$

Correct answer:

$y^{12}z^8$

Explanation:

y^2z^3y^4z^5y^6

Rearrange the expression so that the $\small y$ and $\small z$ variables of different powers are right next to each other.

y^2y^4y^6z^3z^5

When multiplying the same variable with different exponents, it is the same as adding the exponents: $a^ba^c=a^{b+c}$ . Taking advantage of this rule, the problem can be rewritten.

$y^{2+4+6}z^{3+5}$

$y^{6+6}z^8$

$y^{12}z^8$

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Example Question #41 : Polynomial Operations

Rewrite as a single radical expression, assuming is positive:

$\sqrt[4]{x} \cdot \sqrt[3]{x}$

Possible Answers:

$\dpi{150} x\; \sqrt[7]{x ^{5}}$

$\dpi{150} \sqrt[12]{x}$

$\dpi{150} \sqrt[12]{x ^{7}}$

$\dpi{150} \sqrt[7]{x}$

$\dpi{150} \sqrt[7]{x ^{12}}$

Correct answer:

$\dpi{150} \sqrt[12]{x ^{7}}$

Explanation:

Rewrite each radical as an exponential expression, apply the product of powers property, and rewrite the product as a radical:

$\sqrt[4]{x} \cdot \sqrt[3]{x}$

$=x^{ \frac{1}{4}} \cdot x^{ \frac{1}{3}}$

$=x^{ \frac{1}{4}+ \frac{1}{3}}$

$=x^{ \frac{3}{12}+ \frac{4}{12}}$

$=x^{ \frac{7}{12}}$

$=\sqrt[12]{x ^{7}}$

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Example Question #13 : How To Multiply Polynomials

Evaluate: (x-2-x^2)(4-x+3x^2)

Possible Answers:

-3x^4+4x^3-9x^2+6x-8

-3x^4+4x^3-9x^2-6x-8

-3x^4+4x^3+11x^2-6x-8

-3x^4+4x^3-11x^2+6x-8

-3x^4+3x^3+11x^2+6x-8

Correct answer:

-3x^4+4x^3-11x^2+6x-8

Explanation:

This set is out of order, and it may be best to reorganize the terms. To solve, this is very similar to the FOIL method.

(x-2-x^2)(4-x+3x^2)= (-x^2+x-2)(3x^2-x+4)

Follow the procedure to distribute each term.

(a+b+c)(e+f+g)

= (ae+af+ag)+(be+bf+bg)+(ce+cf+cg)

=a(e+f+g)+b(e+f+g)+c(e+f+g)

Follow suit to solve the problem.

(-x^2+x-2)(3x^2-x+4)

=(-x^2)(3x^2-x+4)+(x)(3x^2-x+4)+(-2)(3x^2-x+4)

=(-3x^4+x^3-4x^2)+(3x^3-x^2+4x)-6x^2+2x-8

Combine like terms.

The correct answer is: -3x^4+4x^3-11x^2+6x-8

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Example Question #14 : How To Multiply Polynomials

Multiply and simplify the expression
$\frac{3a^2b^4c}{4ab^2c^3} X \frac{12a^5b^2c}{3a^2bc^2}$ .

Possible Answers:

$\frac{4b^2c}{2a^2}$

$\frac{36a^3c^2}{b^2}$

$\frac{3a^2b^2}{c^5}$

3a^3b^2c

$\frac{3a^4b^3}{c^3}$

Correct answer:

$\frac{3a^4b^3}{c^3}$

Explanation:

The question is asking for the simplified version of this expression:

$\frac{3a^2b^4c}{4ab^2c^3} X \frac{12a^5b^2c}{3a^2bc^2}$

First, combine like terms in the numerator and denominator according to multiplication and exponent rules. When you are multiplying like bases together you add their exponents.

$\frac{3*12*a^2*a^5*b^4*b^2*c*c}{4*3*a*a^2*b^2*b*c^3*c^2}$

When you divide like bases you subtract the bottom exponent from the top exponent.

$\frac{36a^7b^6c^2}{12a^3b^3c^5} = (36/12)a^{7-3}b^{6-3}c^{2-5}$

Finally, simplify the expression by cancelling out terms using GCFs.

$3a^{4}b^{3}c^{-3}$

$\frac{3a^4b^3}{c^3}$

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Example Question #15 : How To Multiply Polynomials

Multiply the polynomials and simplify: $(4x^3+2x^2-8)(x-\frac{1}{4})$

Possible Answers:

$4x^4+x^3-\frac{1}{2}x^2-8x-2$

$4x^4+3x^3-\frac{1}{2}x^2-8x+2$

$4x^4-x^3-\frac{1}{2}x^2-8x-2$

$4x^4+x^3-\frac{1}{2}x^2-8x+2$

$4x^4+x^3-\frac{1}{4}x^2-8x+2$

Correct answer:

$4x^4+x^3-\frac{1}{2}x^2-8x+2$

Explanation:

The key to multiplying polynomials is to keep track of signs and be absolutely sure that you multiply every term in one polynomial (choose the first one) by every term in the other polynomial. For example if polynomial A has 3 terms and polynomial B has two, then then start with the first term in polynomial A and multiply it by both terms in polynomial B. Then choose the second term in polynomial A and repeat. Continue like so until you have gone through all iterations.

First term:

$({\color{Red} 4x^3}+2x^2-8)({\color{Red} x-\frac{1}{4}})$

4x^4-x^3

Second term:

$(4x^3+{\color{Green} 2x^2}-8)({\color{Green} x-\frac{1}{4}})$

$4x^4-x^3+2x^3-\frac{1}{2}x^2$

Third term:

$(4x^3+2x^2-{\color{DarkBlue} 8})({\color{DarkBlue} x-\frac{1}{4}})$

$4x^4-x^3+2x^3-\frac{1}{2}x^2-8x+2$

Now combine terms where able for the final answer:

$4x^4+x^3-\frac{1}{2}x^2-8x+2$

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Algebra 1 : Algebra 1

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #2 : Simplifying And Expanding Quadratics

Example Question #2 : Simplifying And Expanding Quadratics

Example Question #127 : Basic Single Variable Algebra

Example Question #22 : Intermediate Single Variable Algebra

Example Question #101 : Polynomials

Example Question #345 : Exponents

Example Question #41 : Polynomial Operations

Example Question #13 : How To Multiply Polynomials

Example Question #14 : How To Multiply Polynomials

Example Question #15 : How To Multiply Polynomials

All Algebra 1 Resources

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