We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

Algebra 1 : Algebra 1

Study concepts, example questions & explanations for Algebra 1

Create An Account

All Algebra 1 Resources

10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #11 : How To Find The Slope Of Perpendicular Lines

What is the slope of a line which is perpendicular to the following line?

$y=\frac{5}{9}x+8$

Possible Answers:

$\frac{5}{9}$

$\frac{9}{5}$

$-\frac{9}{5}$

Correct answer:

$-\frac{9}{5}$

Explanation:

Given that our equation is in slop-intercept form

y=mx+b

$y=\frac{5}{9}x+8$

where is the slope, we see that for this line the slope is $\frac{5}{9}$ .

Find the negative reciprocal of the slope to find the perpendicular line's slope.

Flip the fraction and make it negative.

$\frac{5}{9}\rightarrow -\frac{9}{5}$ .

Report an Error

Example Question #11 : How To Find The Slope Of Perpendicular Lines

What is the slope of a line perpendicular to $y=-\frac{1}{2}x-5$ ?

Possible Answers:

$-\frac{1}{2}$

$\frac{1}{2}$

$\frac{1}{5}$

Correct answer:

Explanation:

Perpendicular lines are lines that intersect each other at a ninety degree angle. The slope of a line that is perpendicular to another has the opposite sign and is the reciprocal. The slope of a line perpendicular to the one given would be .

Report an Error

Example Question #43 : Perpendicular Lines

$\\ \textup{The slope of a side of a square is 3.}\\\textup{Which of these values cannot be the slope of one of the other three sides?}$

Possible Answers:

$\frac{1}{3}$

$\textup{None of the above.}$

$\textup{All of the above.}$

$-\frac{1}{3}$

Correct answer:

$\frac{1}{3}$

Explanation:

$\textup{Of the other three sides, the opposite side lays on a parallel line,}\\\textup{ so its slope is 3 as well. The two adjacent sides lay on perpendicular lines,}\\\textup{ so their slope is the inverse reciprocal of 3; that is, } -\frac{1}{3}.$

Report an Error

Example Question #11 : How To Find The Slope Of Perpendicular Lines

$\\\textup{Two opposite vertices of a square are the points (0,0) and (-2,4).}\\\textup{Which can be one of the other two vertices?}$

Possible Answers:

(1,3)

(1,2)

(-2,-1)

(1,4)

(-2,0)

Correct answer:

(1,3)

Explanation:

$\textup{The segment between the two opposite vertices (0,0) and (-2,4) is one }\\\textup{diagonal of the square with slope}\frac{4}{-2}=-2 \textup{ and midpoint } \left(\frac{0+(-2)}{2},\frac{0+4}{2} \right)=(-1,2). \textup{ The other diagonal lays on the line } y=\frac{1}{2}x+p \textup{ since it is perpendicular}\\\textup{ and has as a slope of the inverse reciprocal. Substituting the midpoint into the }\\\textup{ parametric equation we obtain } p=\frac{5}{2}\textup{ and the line equation } y=\frac{1}{2}c+\frac{5}{2}.$

$\textup{ Only point } (1,3) \textup{ among the possible answers lays on this line.}$ .

$\textup{ Alternatively, one can check for every possible answer if the two segments}\\\textup{between the candidate point and the two opposite vertices are perpendicular.}$

Report an Error

Example Question #16 : How To Find The Slope Of Perpendicular Lines

Find the slope of the line perpendicular to y=3x+4 .

Possible Answers:

1/3

-1/3

Correct answer:

-1/3

Explanation:

The slope of a perpendicular line is always the negative reciprocal of the original slope.

Our original equation is y=3x+4 which is in the form y=mx+b where is the slope. Therefore, the original slope is m=3 .

To find the slope of a line perpendicular we want to use the following formula,

$m_p=-\frac{1}{m}$

$m_p=-\frac{1}{3}$ .

Report an Error

Example Question #14 : How To Find The Slope Of Perpendicular Lines

Find the slope of the line that is perpendicular to a line with the equation:

$y=\frac{1}{3}x-9$

Possible Answers:

$\frac{1}{3}$

$-\frac{1}{3}$

Correct answer:

Explanation:

Lines can be written in the slope-intercept form:

y=mx+b

In this equation, is the slope and is the y-intercept.

Lines that are perpendicular to each other have slopes that are negative reciprocals of each other. This means that you need to flip the numerator and denominator of the given slope and then change the sign.

First, find the reciprocal of $\frac{1}{3}$ .

$\frac{1}{3}\rightarrow \frac{3}{1}=3$

Next, change the sign.

$3\rightarrow-3$

Report an Error

Example Question #44 : Perpendicular Lines

Find the slope of the line that is perpendicular to a line with the equation:

y=2x-2

Possible Answers:

$\frac{1}{2}$

$-\frac{1}{2}$

Correct answer:

$-\frac{1}{2}$

Explanation:

Lines can be written in the slope-intercept form:

y=mx+b

In this equation, is the slope and is the y-intercept.

First, find the reciprocal of :

$2=\frac{2}{1}$

Flip the numerator and the denominator.

$\frac{2}{1}\rightarrow \frac{1}{2}$

Next, change the sign.

$\frac{1}{2}\rightarrow-\frac{1}{2}$

Report an Error

Example Question #45 : Perpendicular Lines

Find the slope of the line that is perpendicular to a line with the equation:

$y=-\frac{2}{3}x+2$

Possible Answers:

$\frac{2}{3}$

$-\frac{2}{3}$

$-\frac{3}{2}$

$\frac{3}{2}$

Correct answer:

$\frac{3}{2}$

Explanation:

Lines can be written in the slope-intercept form:

y=mx+b

In this equation, is the slope and is the y-intercept.

First, find the reciprocal of $-\frac{2}{3}$ .

$-\frac{2}{3}\rightarrow-\frac{3}{2}$

Next, change the sign.

$-\frac{3}{2}\rightarrow\frac{3}{2}$

Report an Error

Example Question #15 : How To Find The Slope Of Perpendicular Lines

Find the slope of a line that is perpendicular to a line with the equation:

y=-10x+9

Possible Answers:

$-\frac{1}{10}$

$\frac{1}{10}$

Correct answer:

$\frac{1}{10}$

Explanation:

Lines can be written in the slope-intercept form:

y=mx+b

In this equation, is the slope and is the y-intercept.

First, find the reciprocal of .

$-10=-\frac{10}{1}$

Flip the numerator and the denominator.

$-\frac{10}{1}=-\frac{1}{10}$

Next, change the sign.

$-\frac{1}{10}\rightarrow\frac{1}{10}$

Report an Error

Example Question #21 : How To Find The Slope Of Perpendicular Lines

Find the slope of a line that is perpendicular to a line with the equation:

$y=\frac{1}{4}x-2$

Possible Answers:

$-\frac{1}{4}$

$\frac{1}{4}$

Correct answer:

Explanation:

Lines can be written in the slope-intercept form:

y=mx+b

In this equation, is the slope and is the y-intercept.

First, find the reciprocal of $\frac{1}{4}$ .

$\frac{1}{4}\rightarrow \frac{4}{1}=4$

Next, change the sign.

$4\rightarrow-4$

Report an Error

View Algebra Tutors

Shrikar
Certified Tutor

University of South Florida-Main Campus, Bachelor of Science, Biomedical Sciences.

View Algebra Tutors

Ian
Certified Tutor

Lipscomb University, Bachelor of Science, Biology, General.

View Algebra Tutors

Scott
Certified Tutor

Albright College, Bachelor of Science, Mathematics. Immaculata University, Master of Arts, Urban Education and Leadership.

All Algebra 1 Resources

10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Biology Tutors in Miami, French Tutors in Washington DC, Chemistry Tutors in San Francisco-Bay Area, GMAT Tutors in Miami, Algebra Tutors in Atlanta, Calculus Tutors in Philadelphia, Physics Tutors in Philadelphia, English Tutors in Los Angeles, Calculus Tutors in Boston, GRE Tutors in San Diego

Popular Courses & Classes

SAT Courses & Classes in New York City, ACT Courses & Classes in Philadelphia, SSAT Courses & Classes in Boston, ACT Courses & Classes in Chicago, SSAT Courses & Classes in Miami, Spanish Courses & Classes in San Francisco-Bay Area, LSAT Courses & Classes in Phoenix, ACT Courses & Classes in Denver, ACT Courses & Classes in Dallas Fort Worth, SAT Courses & Classes in San Diego

Popular Test Prep

ACT Test Prep in Denver, LSAT Test Prep in Houston, GRE Test Prep in Dallas Fort Worth, SSAT Test Prep in Washington DC, LSAT Test Prep in Boston, ISEE Test Prep in Dallas Fort Worth, MCAT Test Prep in San Diego, MCAT Test Prep in Houston, SAT Test Prep in San Diego, GRE Test Prep in Los Angeles

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Algebra 1 : Algebra 1

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #11 : How To Find The Slope Of Perpendicular Lines

Example Question #11 : How To Find The Slope Of Perpendicular Lines

Example Question #43 : Perpendicular Lines

Example Question #11 : How To Find The Slope Of Perpendicular Lines

Example Question #16 : How To Find The Slope Of Perpendicular Lines

Example Question #14 : How To Find The Slope Of Perpendicular Lines

Example Question #44 : Perpendicular Lines

Example Question #45 : Perpendicular Lines

Example Question #15 : How To Find The Slope Of Perpendicular Lines

Example Question #21 : How To Find The Slope Of Perpendicular Lines

All Algebra 1 Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: