Algebra 1 : Algebra 1

Study concepts, example questions & explanations for Algebra 1

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Example Questions

Example Question #49 : How To Multiply Integers

Multiply the following numbers: \(\displaystyle 59\times 9\)

Possible Answers:

\(\displaystyle 158\)

\(\displaystyle 531\)

\(\displaystyle 551\)

\(\displaystyle 451\)

\(\displaystyle 468\)

Correct answer:

\(\displaystyle 531\)

Explanation:

Multiply the ones digits.

\(\displaystyle 9\times 9 =81\)

The tens digit is eight, which is the carryover.

Multiply the tens digit of the first number with the ones digit of the second number.

\(\displaystyle 5\times 9 +8 = 45+8 =53\)

Combine the numbers with the ones digit of the first calculation.

The answer is: \(\displaystyle 531\)

Example Question #51 : How To Multiply Integers

Multiply fifteen with eight.

Possible Answers:

\(\displaystyle 120\) 

\(\displaystyle 90\)

\(\displaystyle 160\)

\(\displaystyle 80\)

\(\displaystyle 140\)

Correct answer:

\(\displaystyle 120\) 

Explanation:

Write the expression to express the question.

\(\displaystyle 15 \times 8\)

Multiply the ones digits.

\(\displaystyle 5\times 8=40\)

Since this number has a tens digit, it will be used as a carryover.

Multiply the tens digits and add the carryover.

\(\displaystyle 1\times 8 +4 = 12\)

Combine the numbers.

The answer is:  \(\displaystyle 120\)

Example Question #121 : Integer Operations

Multiply the following integers: \(\displaystyle [9,3,11]\)

Possible Answers:

\(\displaystyle 297\)

\(\displaystyle 278\)

\(\displaystyle 397\)

\(\displaystyle 307\)

\(\displaystyle 287\)

Correct answer:

\(\displaystyle 297\)

Explanation:

The order of multiplication does not matter. We can choose to multiply eleven by three or nine to save work.

Multiply eleven with three.

\(\displaystyle 11\times 3 = 33\)

Multiply thirty-three with nine.

\(\displaystyle 33 \times 9\)

Multiply the ones digits.

\(\displaystyle 3\times 9= 27\)

The carryover is the tens place. Multiply the ones digit with the tens digit and add the carryover.

\(\displaystyle 3\times 9 +2 = 29\)

Combine the numbers. The answer is \(\displaystyle 297\).

Example Question #122 : Integer Operations

Multiply the numbers:  \(\displaystyle 29 \times 8\)

Possible Answers:

\(\displaystyle 722\)

\(\displaystyle 242\)

\(\displaystyle 242\)

\(\displaystyle 232\)

\(\displaystyle 1672\)

Correct answer:

\(\displaystyle 232\)

Explanation:

Multiply the ones digits.

\(\displaystyle 9 \times 8=72\)

The tens place will be the carryover for the next calculation.

Multiply the tens digit of 29 with the eight and add the carryover.

\(\displaystyle 2\times 8 +7 = 16+7 = 23\)

Combine this number with the ones digit of the first calculation.

The answer is:  \(\displaystyle 232\)

Example Question #123 : Integer Operations

Multiply:  \(\displaystyle 587 \times 8\)

Possible Answers:

\(\displaystyle 4766\)

\(\displaystyle 4596\)

\(\displaystyle 4066\)

\(\displaystyle 4696\)

\(\displaystyle 4686\)

Correct answer:

\(\displaystyle 4696\)

Explanation:

Multiply the ones digit of 587 with the eight.

\(\displaystyle 7 \times 8 = 56\)

The tens place is the carryover.

Multiply the tens digit of 587 with the eight and add the carryover.

\(\displaystyle 8\times 8+5 = 69\)

The tens place is the carryover.

Multiply the hundreds digit of 587 with the eight and add the carryover.

\(\displaystyle 5\times 8+6 = 46\)

Combine this number with the ones digits in the other calculations.

The answer is:  \(\displaystyle 4696\)

Example Question #124 : Integer Operations

Multiply:  \(\displaystyle 26\times 8\)

Possible Answers:

\(\displaystyle 228\)

\(\displaystyle 248\)

\(\displaystyle 208\)

\(\displaystyle 168\)

\(\displaystyle 148\)

Correct answer:

\(\displaystyle 208\)

Explanation:

Multiply the ones digit of 26 with eight.

\(\displaystyle 6\times8=48\)

The tens place is the carryover.

Multiply the tens digit of 26 with eight and add the carryover.

\(\displaystyle 2\times 8 +4 = 16+4 =20\)

Combine this number with the ones digit of the first calculation.

The answer is: \(\displaystyle 208\)

Example Question #125 : Integer Operations

Solve:  \(\displaystyle 91\times 31\)

Possible Answers:

\(\displaystyle 2721\)

\(\displaystyle 2781\)

\(\displaystyle 2711\)

\(\displaystyle 2821\)

\(\displaystyle 2701\)

Correct answer:

\(\displaystyle 2821\)

Explanation:

Multiply 91 with the ones digit.

\(\displaystyle 91\times 1 =91\)

Skip a line and multiply 91 with the tens digit.

\(\displaystyle 91 \times 3 = 273\)

Add a zero at the end of this number.

\(\displaystyle 2730\)

Sum this number with the first number we have calculated.

\(\displaystyle 2730+91 =2821\)

The answer is:   \(\displaystyle 2821\)

Example Question #126 : Integer Operations

Multiply the integers:  \(\displaystyle 15\times 48\)

Possible Answers:

\(\displaystyle 460\)

\(\displaystyle 780\)

\(\displaystyle 720\)

\(\displaystyle 660\)

\(\displaystyle 280\)

Correct answer:

\(\displaystyle 720\)

Explanation:

Multiply the first number with the ones digit of the second number.

\(\displaystyle 15\times 8 = 120\)

Skip a line, and multiply the first number with the tens digit of the second number.

\(\displaystyle 15\times 4= 60\)

We will need to add a zero to the right of this number.

\(\displaystyle 600\)

Add this number with the first number.

\(\displaystyle 600+120 = 720\)

The answer is:  \(\displaystyle 720\)

Example Question #2581 : Algebra 1

Solve the expression  \(\displaystyle 13+(-3)\).

Possible Answers:

\(\displaystyle 13\)

\(\displaystyle 16\)

\(\displaystyle 39\)

\(\displaystyle 10\)

\(\displaystyle -39\)

Correct answer:

\(\displaystyle 10\)

Explanation:

Adding a negative is the same as subtraction.

\(\displaystyle 13+(-3)=13-3=10\)

Example Question #2 : How To Add Integers

What is the sum of all of the even integers from 2 to 2,000, inclusive?

Possible Answers:

\(\displaystyle 1,010,000\)

\(\displaystyle 1,000,000\)

\(\displaystyle 999,000\)

\(\displaystyle 1,001,000\)

\(\displaystyle 990,000\)

Correct answer:

\(\displaystyle 1,001,000\)

Explanation:

Pair the numbers as follows:

\(\displaystyle 2+2000=2,002\)

\(\displaystyle 4+1998=2,002\)

\(\displaystyle 6+1996=2,002\)

...

\(\displaystyle 1,000+1,002=2,002\)

There are 500 such pairs, so adding all of the even integers from 2 to 2,000 is the same as taking 2,002 as an addend 500 times. This can be rewritten as a multiplication.

\(\displaystyle 2,002* 500 = 1,001,000\)

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