All Algebra 1 Resources
Example Questions
Example Question #12 : Proportions
I have a bag full of blue and red marbles. If the ratio of blue to red marbles is 1:4 and if I have 16 blue ones, how many red marbles are in the bag.
First, translate the problem into a proportion equation. We have the ratio 1:4. Therefore, we have the fraction . Set that fraction equal to the number of blue (which is 16) marbles divide by the number of red marbles.
We need to find , the number of red marbles. Perform the cross multiplication
So there are 64 red marbles.
Example Question #13 : Proportions
If , what is the value of ?
For this problem, we can divide both sides of the original equation by to obtain our answer. Another way we can solve this problem, however, is by using a proportion,
Cross-multiplication yields the equation
Dividing both sides by gives us
an equation that can be easily solved to get
Example Question #14 : Proportions
Solve:
Multiply diagonally so that you get .
Isolate for and you get .
Simplify and you get .
Example Question #11 : Proportions
Cross-multiply and you get
Isolate for and you get .
Example Question #1141 : Algebra 1
A car uses up gallons of gas in miles. Which expression best represents the distance, in kilometers, that the car can travel on 15 gallons of gas?
(1 mile is equivalent to 1.6 kilometers.)
gallons will allow the car to travel miles, or kilometers.
Set up a proportion, where is the distance:
Solve for :
Example Question #17 : Proportions
Solve:
To solve the proportion, cross multiply.
The correct answer is since both numbers satisfy the original problem.
Example Question #13 : Proportions
Solve for .
Cross multiply.
We get
.
That's the answer.
Example Question #19 : Proportions
Solve for
Let's cross multiply.
We have
.
Divide both sides by .
.
Example Question #20 : Proportions
Solve for .
Let's cross multiply.
We have
.
Divide both sides by , we get
.
The answer is reduced and we do that by dividing top and bottom by .
Example Question #21 : Proportions
Solve for .
Let's cross multiply.
We have
.
Divide both sides by , we get
.
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