ACT Science : ACT Science

Study concepts, example questions & explanations for ACT Science

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Example Questions

Example Question #61 : Physics

Students are given an assignment to create a circuit from a given set of components. Four different students create circuits in unique manners and the professor measures the resistance of the circuit, the power output of the circuit and the heat given off by each circuit after each circuit was running for a certain amount of time. Circuits with resistors in parallel have a lower total resistance than those that have resistors in series.

Capture 3

What other important information should be noted by the professor? 

Possible Answers:

How the amount of time the circuit is running affects the measured parameters

All of the other options

None of the other options

The amount of space (for example square feet or square inches) that the circuit takes up

The duration of use for which the circuit can be run before the components fail

Correct answer:

All of the other options

Explanation:

If the circuit is run for a certain amount of time the heat given off may be different than for other times. In addition, if the circuit is run for longer times some of the components may burn out. Knowing the size of the circuit will allow for the determination of what the circuit can be used for or what it is compatible with in terms of spacing. Knowing how long the circuit can be run before the components fail would be very useful in knowing. It would be useful to know all of the information that is presented as options. 

Example Question #1181 : Act Science

Scientist 1: Scientist 1 believes that light displays particle behavior. This means that rays of light have their own associated momentum. Furthermore, Scientist 1 does not believe that light will exhibit wave behavior.

Scientist 2: Scientist 2 disagrees with Scientist 1 and believes that light can exhibit wave behavior, but does not display particle behavior. In other words, this scientist believes that light does not have any momentum.

Experiment: To settle their disagreement, the scientists setup the following experiment. The scientist take dark metallic material. This material is attached to pole and the metallic material can spin if it is subjected to a force; similar to a watermill or wind turbine. This setup is then placed outside and exposed to sunlight. 

What is a potential issue with this experiment?

Possible Answers:

The metallic surface may not be capable of rotating

All of the other answers

It is a cloudy day outside so no sunlight is seen

The metallic surface absorbs heat from the light and rotates due to temperature differences

Light particles can pass through the metallic surface

Correct answer:

The metallic surface absorbs heat from the light and rotates due to temperature differences

Explanation:

It can be assumed that the scientists will perform the experiment when it is sunny out and that the device is created properly. This indicates that light will not pass through the metallic surface, it can rotate correctly and it will be a sunny day. An issue that is difficult to correct is that sunlight gives off heat, which will be absorbed by a dark surface such as the metallic surface. This would increase the temperature of the surface causing it to rotate due to temperature differences. 

Example Question #35 : How To Find Experimental Design In Physics

A scientist observed that when low energy types of electromagnetic radiation (light), such as visible light or ultraviolet light, were shone onto a conductive copper wire incorporated into a circuit with a light bulb as shown in Figure 1, the light bulb did not come on. However, when electromagnetic radiation of a higher energy, such as x-rays or gamma rays, was shone onto the wire, the light bulb did come on, indicating a current (electricity) was produced in the wire. The scientist hypothesized that this effect was due to the fact that electromagnetic radiation of a certain energy was able to overcome the attraction between electrons and protons in the individual atoms of copper in the wire, and liberate an electron to produce the electric current. He called this the photoelectric effect, and did the following experiments to further study this effect.

Photoelectric effect wire bulb appartus

Figure 1

Experiment 1:

The scientist put a sample of copper in an instrument that can measure the energies of free-moving electrons. He shone a light source capable of producing specific energies of electromagnetic radiation on the metal and slowly increased the energy of the light. The instrument was used to measure the kinetic energies (energy due to motion) of any electrons that were liberated from the copper sample. The scientist recorded the energy of light used in frequency, where a low frequency corresponds to a low energy electromagnetic radiation, and a high frequency corresponds to a high frequency of electromagnetic radiation. He saw that no electrons could be detected at low frequencies, and that after a specific frequency he called the threshold frequency, the kinetic energy of liberated electrons increased linearly with increasing frequency of incident light as shown in Figure 2 below. The data was fitted with a line along which the data falls; the equation describing this line is shown in Figure 2.

Photoelectric effect figure 2

Figure 2

Experiment 2:

The scientist removed the light bulb from the circuit shown in Figure 1 and replaced it with an instrument that can measure electrical charge. He then directed his x-ray source at the wire and slowly increased the intensity of the X-ray light while the frequency was held constant at . He monitored the current produced in the wire as the intensity of light increased and recorded the results in Figure 3 below. Intensity of light is measured in photons (a discrete particle, the fundamental unit of light) and charge in Coulombs, and like in Experiment 1, a linear equation is fitted to the data and shown in Figure 3.

Photoelectric effect figure 3

Figure 3

The value corresponding to the binding energy of an electron to its positively charged nucleus is known as the work function, and corresponds to the y-intercept of the trend line produced when frequency of incident light is graphed against kinetic energy of liberated electrons. What is the work function for copper?

Possible Answers:

-1.3

-5.6

-4.7

2.2

Correct answer:

-4.7

Explanation:

Frequency is graphed against kinetic energy of liberated electrons in Figure 2 for a sample of copper as mentioned in the description for Experiment 1. The equation describing the line that best fits the scientist's data is shown. As a line is given by y = mx + b, where b is the y-intercept, the y-intercept is -4.7.

 

Example Question #1183 : Act Science

A scientist observed that when low energy types of electromagnetic radiation (light), such as visible light or ultraviolet light, were shone onto a conductive copper wire incorporated into a circuit with a light bulb as shown in Figure 1, the light bulb did not come on. However, when electromagnetic radiation of a higher energy, such as x-rays or gamma rays, was shone onto the wire, the light bulb did come on, indicating a current (electricity) was produced in the wire. The scientist hypothesized that this effect was due to the fact that electromagnetic radiation of a certain energy was able to overcome the attraction between electrons and protons in the individual atoms of copper in the wire, and liberate an electron to produce the electric current. He called this the photoelectric effect, and did the following experiments to further study this effect.

Photoelectric effect wire bulb appartus

Figure 1

Experiment 1:

The scientist put a sample of copper in an instrument that can measure the energies of free-moving electrons. He shone a light source capable of producing specific energies of electromagnetic radiation on the metal and slowly increased the energy of the light. The instrument was used to measure the kinetic energies (energy due to motion) of any electrons that were liberated from the copper sample. The scientist recorded the energy of light used in frequency, where a low frequency corresponds to a low energy electromagnetic radiation, and a high frequency corresponds to a high frequency of electromagnetic radiation. He saw that no electrons could be detected at low frequencies, and that after a specific frequency he called the threshold frequency, the kinetic energy of liberated electrons increased linearly with increasing frequency of incident light as shown in Figure 2 below. The data was fitted with a line along which the data falls; the equation describing this line is shown in Figure 2.

Photoelectric effect figure 2

Figure 2

Experiment 2:

The scientist removed the light bulb from the circuit shown in Figure 1 and replaced it with an instrument that can measure electrical charge. He then directed his x-ray source at the wire and slowly increased the intensity of the X-ray light while the frequency was held constant at . He monitored the current produced in the wire as the intensity of light increased and recorded the results in Figure 3 below. Intensity of light is measured in photons (a discrete particle, the fundamental unit of light) and charge in Coulombs, and like in Experiment 1, a linear equation is fitted to the data and shown in Figure 3.

Photoelectric effect figure 3

Figure 3

Figure 2 shows that the threshold frequency, in Hertz, for copper is most nearly:

Possible Answers:

Correct answer:

Explanation:

The description of Experiment 1 defines threshold frequency as the frequency at which electrons are liberated from the sample and have measurable kinetic energies. The first data point appears at roughly  as shown on the x-axis.

Example Question #1184 : Act Science

A scientist observed that when low energy types of electromagnetic radiation (light), such as visible light or ultraviolet light, were shone onto a conductive copper wire incorporated into a circuit with a light bulb as shown in Figure 1, the light bulb did not come on. However, when electromagnetic radiation of a higher energy, such as x-rays or gamma rays, was shone onto the wire, the light bulb did come on, indicating a current (electricity) was produced in the wire. The scientist hypothesized that this effect was due to the fact that electromagnetic radiation of a certain energy was able to overcome the attraction between electrons and protons in the individual atoms of copper in the wire, and liberate an electron to produce the electric current. He called this the photoelectric effect, and did the following experiments to further study this effect.

Photoelectric effect wire bulb appartus

Figure 1

Experiment 1:

The scientist put a sample of copper in an instrument that can measure the energies of free-moving electrons. He shone a light source capable of producing specific energies of electromagnetic radiation on the metal and slowly increased the energy of the light. The instrument was used to measure the kinetic energies (energy due to motion) of any electrons that were liberated from the copper sample. The scientist recorded the energy of light used in frequency, where a low frequency corresponds to a low energy electromagnetic radiation, and a high frequency corresponds to a high frequency of electromagnetic radiation. He saw that no electrons could be detected at low frequencies, and that after a specific frequency he called the threshold frequency, the kinetic energy of liberated electrons increased linearly with increasing frequency of incident light as shown in Figure 2 below. The data was fitted with a line along which the data falls; the equation describing this line is shown in Figure 2.

Photoelectric effect figure 2

Figure 2

Experiment 2:

The scientist removed the light bulb from the circuit shown in Figure 1 and replaced it with an instrument that can measure electrical charge. He then directed his x-ray source at the wire and slowly increased the intensity of the X-ray light while the frequency was held constant at . He monitored the current produced in the wire as the intensity of light increased and recorded the results in Figure 3 below. Intensity of light is measured in photons (a discrete particle, the fundamental unit of light) and charge in Coulombs, and like in Experiment 1, a linear equation is fitted to the data and shown in Figure 3.

Photoelectric effect figure 3

Figure 3

An electron has a negative electric charge of . How many electrons are produced per photon with the frequency stated in Experiment 2?

Possible Answers:

0.32

0.64

0.064

0.032

Correct answer:

0.032

Explanation:

According to Figure 3, one photon produces ~0.032units on the y-axis. Dimensional analysis shows that:

Example Question #61 : Physics

A scientist observed that when low energy types of electromagnetic radiation (light), such as visible light or ultraviolet light, were shone onto a conductive copper wire incorporated into a circuit with a light bulb as shown in Figure 1, the light bulb did not come on. However, when electromagnetic radiation of a higher energy, such as x-rays or gamma rays, was shone onto the wire, the light bulb did come on, indicating a current (electricity) was produced in the wire. The scientist hypothesized that this effect was due to the fact that electromagnetic radiation of a certain energy was able to overcome the attraction between electrons and protons in the individual atoms of copper in the wire, and liberate an electron to produce the electric current. He called this the photoelectric effect, and did the following experiments to further study this effect.

Photoelectric effect wire bulb appartus

Figure 1

Experiment 1:

The scientist put a sample of copper in an instrument that can measure the energies of free-moving electrons. He shone a light source capable of producing specific energies of electromagnetic radiation on the metal and slowly increased the energy of the light. The instrument was used to measure the kinetic energies (energy due to motion) of any electrons that were liberated from the copper sample. The scientist recorded the energy of light used in frequency, where a low frequency corresponds to a low energy electromagnetic radiation, and a high frequency corresponds to a high frequency of electromagnetic radiation. He saw that no electrons could be detected at low frequencies, and that after a specific frequency he called the threshold frequency, the kinetic energy of liberated electrons increased linearly with increasing frequency of incident light as shown in Figure 2 below. The data was fitted with a line along which the data falls; the equation describing this line is shown in Figure 2.

Photoelectric effect figure 2

Figure 2

Experiment 2:

The scientist removed the light bulb from the circuit shown in Figure 1 and replaced it with an instrument that can measure electrical charge. He then directed his x-ray source at the wire and slowly increased the intensity of the X-ray light while the frequency was held constant at . He monitored the current produced in the wire as the intensity of light increased and recorded the results in Figure 3 below. Intensity of light is measured in photons (a discrete particle, the fundamental unit of light) and charge in Coulombs, and like in Experiment 1, a linear equation is fitted to the data and shown in Figure 3.

Photoelectric effect figure 3

Figure 3

The circuit setup in Experiment 3 can be considered a solar cell as electricity is produced when the wire collects electromagnetic radiation. An important consideration in the development of solar cells is their efficiency, which can be defined as the ratio of electrons produced to photons incident on the material expressed as a percentage. What is the efficiency of the solar cell in Experiment 2? 

Possible Answers:

Correct answer:

Explanation:

Question 4 shows us that for every incident photon, 0.032 electrons are produced. Expressed as a percentage, that is:

 

Example Question #1185 : Act Science

A scientist observed that when low energy types of electromagnetic radiation (light), such as visible light or ultraviolet light, were shone onto a conductive copper wire incorporated into a circuit with a light bulb as shown in Figure 1, the light bulb did not come on. However, when electromagnetic radiation of a higher energy, such as x-rays or gamma rays, was shone onto the wire, the light bulb did come on, indicating a current (electricity) was produced in the wire. The scientist hypothesized that this effect was due to the fact that electromagnetic radiation of a certain energy was able to overcome the attraction between electrons and protons in the individual atoms of copper in the wire, and liberate an electron to produce the electric current. He called this the photoelectric effect, and did the following experiments to further study this effect.

Photoelectric effect wire bulb appartus

Figure 1

Experiment 1:

The scientist put a sample of copper in an instrument that can measure the energies of free-moving electrons. He shone a light source capable of producing specific energies of electromagnetic radiation on the metal and slowly increased the energy of the light. The instrument was used to measure the kinetic energies (energy due to motion) of any electrons that were liberated from the copper sample. The scientist recorded the energy of light used in frequency, where a low frequency corresponds to a low energy electromagnetic radiation, and a high frequency corresponds to a high frequency of electromagnetic radiation. He saw that no electrons could be detected at low frequencies, and that after a specific frequency he called the threshold frequency, the kinetic energy of liberated electrons increased linearly with increasing frequency of incident light as shown in Figure 2 below. The data was fitted with a line along which the data falls; the equation describing this line is shown in Figure 2.

Photoelectric effect figure 2

Figure 2

Experiment 2:

The scientist removed the light bulb from the circuit shown in Figure 1 and replaced it with an instrument that can measure electrical charge. He then directed his x-ray source at the wire and slowly increased the intensity of the X-ray light while the frequency was held constant at . He monitored the current produced in the wire as the intensity of light increased and recorded the results in Figure 3 below. Intensity of light is measured in photons (a discrete particle, the fundamental unit of light) and charge in Coulombs, and like in Experiment 1, a linear equation is fitted to the data and shown in Figure 3.

Photoelectric effect figure 3

Figure 3

Why did the scientist hold the frequency of x-rays at  in Experiment 2?

Possible Answers:

This was the only frequency the x-ray source was capable of producing.

X-rays of  were shown to produce electrons with a desirable kinetic energy for detection.

 

X-rays of  will not liberate electrons from copper, and thus, the scientist can avoid the danger of high-energy fast-moving electrons in his laboratory.

The scientist needed to hold one variable constant while changing the intensity of light, and this frequency had been shown to produce electrons in the copper.

Correct answer:

The scientist needed to hold one variable constant while changing the intensity of light, and this frequency had been shown to produce electrons in the copper.

Explanation:

The scientific method requires that only one variable must be changed at a time to be able to correlate a change in results with the change made in the manipulated variable. The point of Experiment 2 is to study the result when the intensity of light is changed. Thus, the frequency of light must be held constant, as described in the correct answer. Secondly, as he is detecting liberated electrons, a frequency known to liberate them from Experiment 1 is needed. As the threshold frequency was shown to be ,  will be sufficiently energetic.

Example Question #40 : How To Find Experimental Design In Physics

A scientist observed that when low energy types of electromagnetic radiation (light), such as visible light or ultraviolet light, were shone onto a conductive copper wire incorporated into a circuit with a light bulb as shown in Figure 1, the light bulb did not come on. However, when electromagnetic radiation of a higher energy, such as x-rays or gamma rays, was shone onto the wire, the light bulb did come on, indicating a current (electricity) was produced in the wire. The scientist hypothesized that this effect was due to the fact that electromagnetic radiation of a certain energy was able to overcome the attraction between electrons and protons in the individual atoms of copper in the wire, and liberate an electron to produce the electric current. He called this the photoelectric effect, and did the following experiments to further study this effect.

Photoelectric effect wire bulb appartus

Figure 1

Experiment 1:

The scientist put a sample of copper in an instrument that can measure the energies of free-moving electrons. He shone a light source capable of producing specific energies of electromagnetic radiation on the metal and slowly increased the energy of the light. The instrument was used to measure the kinetic energies (energy due to motion) of any electrons that were liberated from the copper sample. The scientist recorded the energy of light used in frequency, where a low frequency corresponds to a low energy electromagnetic radiation, and a high frequency corresponds to a high frequency of electromagnetic radiation. He saw that no electrons could be detected at low frequencies, and that after a specific frequency he called the threshold frequency, the kinetic energy of liberated electrons increased linearly with increasing frequency of incident light as shown in Figure 2 below. The data was fitted with a line along which the data falls; the equation describing this line is shown in Figure 2.

Photoelectric effect figure 2

Figure 2

Experiment 2:

The scientist removed the light bulb from the circuit shown in Figure 1 and replaced it with an instrument that can measure electrical charge. He then directed his x-ray source at the wire and slowly increased the intensity of the X-ray light while the frequency was held constant at . He monitored the current produced in the wire as the intensity of light increased and recorded the results in Figure 3 below. Intensity of light is measured in photons (a discrete particle, the fundamental unit of light) and charge in Coulombs, and like in Experiment 1, a linear equation is fitted to the data and shown in Figure 3.

Photoelectric effect figure 3

Figure 3

What is the meaning of the slope in the regression equation for the data shown in Figure 1?

Possible Answers:

For every increase of one unit of frequency (in ) there is an increase of 4.1357eV of kinetic energy in liberated electrons.

For every increase of one unit of kinetic energy (in eV) there is an increase in frequency of  in incident x-rays.

 

For every decrease of one unit of kinetic energy (in eV) there is an increase in frequency of  in incident x-rays.

For every increase of one unit of kinetic energy (in eV) there is an increase in frequency of  in incident x-rays.

 

Correct answer:

For every increase of one unit of frequency (in ) there is an increase of 4.1357eV of kinetic energy in liberated electrons.

Explanation:

Slope is defined as rise over run. Thus, the slope indicates a ratio of a 4.1357-unit-increase in the y-value to an increase of 1 in the x-value. Figure 2 shows that the y-values are kinetic energies, given in eV, and that x-values are frequencies, given in units of . Generally, it is a positive slope, and thus answer choices that refer to a decrease in one variable corresponding to an increase in the other variable must be incorrect.

Example Question #41 : How To Find Experimental Design In Physics

Experiment 1

A scientist develops the following setup, shown in Figure 1 below, to study the charges of radioactive particles. A radioactive sample is placed into a lead box that has an open column such that the particles can only exit from one direction. A detector is placed in front of the opening. A metric ruler (centimeters (cm)), is aligned on the detector such that zero is directly in front of the opening of the column, with the positive values extending to the left and the negative values to the right. On the left side of the experimental setup, there is a device that generates a magnetic field that attracts positively charged particles and repels negatively charged particles.

 

                 Radioactivity_fig_1

                                                    Figure 1.

 

The device detects particles in three different places: alpha, α; beta, β; and gamma, γ; as labeled in Figure 1. The paths these particles take from the source of radioactivity are shown.

 

Experiment 2

A different scientist finds the following data, shown in Table 1, about the energies of the α, β, and γ particles by observing what kinds of materials through which the particles can pass. This scientist assumes that the ability of particles to pass through thicker and denser barriers is indicative of higher energy. Table 1 summarizes whether or not each type of particle was detected when each of the following barriers is placed between the radioactivity source and the detector. The paper and aluminum foil are both 1 millimeters thick, and the concrete wall is 1 meter thick.

 

                              Radioactivity_table_1

Why did the scientist in Experiment 2 include a test with no barrier?

Possible Answers:

She wanted to see if air alone could stop the particles.

She forgot to use the barrier for the first data set.

She wanted to see if all the types of particles were dangerous.

She needed a data set with no barrier to use as a control, or standard of comparison, for the other three data sets.

Correct answer:

She needed a data set with no barrier to use as a control, or standard of comparison, for the other three data sets.

Explanation:

All experiments need a control to indicate that observations are indeed caused by the manipulated variable. The "no barrier" condition ensures that particles are observed without the use of any barrier, and that the barriers that are observed to deflect the particle are truly deflecting them. 

Example Question #1 : How To Find Synthesis Of Data In Physics

Laura is performing an experiment with a 5kg weight tied to a 3m rope tied to the ceiling as shown:
Screen_shot_2013-11-03_at_8.09.39_pm

Laura drops the weight and allows it to swing freely. She measures how long it takes for the weight to return to it's original position (assume no forces outside of gravity are acting upon the pendulum). This is also called one oscillation.


Experiment 1:

Laura created the following table for her first measurement of the pendulum's oscillations.

Screen_shot_2013-11-03_at_8.19.19_pm

Experiment 2:

Laura performed the experiment again, this time using a 6kg weight.

Screen_shot_2013-11-03_at_8.19.19_pm

 Experiment 3:

Laura performed the experiment again, this time using a 3kg weight and a 5m rope.Screen_shot_2013-11-04_at_8.30.58_am

How long would 4 oscillations be, using the 3m rope and the 6kg weight?

Possible Answers:

53.828

2.565

13.896

12.566

Correct answer:

13.896

Explanation:

Based on experiment 2, each oscillation is approximately 3.474 seconds long. 4 oscillations would therefore last approximately 13.896 seconds

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