To solve, simply use the formula for volume of a cube. The volume of a cube is length times width times height. Since the height, width, and length are equal on a cube the formula becomes side cubed.

We are given the side length of 0.1 thus,

To solve, simply cube the side length. Thus,

The formula for the volume of a pyramid is:

We know that  and ; however, this still leaves us with two variables in the equation:  and . By definition, a square pyramid's base has sides of equal length, meaning that  and  are the same. Therefore, we can substitute  for , or .

This gives us a new equation of:

We then plug in the variables we know:

Multiply both sides by 3:

Divide both sides by 9:

Therefore, we now know that the length of the pyramid's base is . The question, however, asks for the perimeter of the pyramid's base. Since all of the sides of the base are the same, they must all be . So we multiply . Therefore, the perimeter of the pyramid's base is .

In this kind of a problem, it's helpful to draw out all information that's given. 

Because the triangular faces of a pyramid are isosceles triangles, the slant height can be seen to divide it into two right triangles. The goal is to find the measure of the edge of the square base. This quickly becomes a problem revolving around the use of the Pythagorean theorem. 

If we take the measures 12 and 8 to be the hypotenuse and one of the legs, respectively, we can use the Pythagoream theorem to solve for the "base leg." Then, realizing that this measure if only half of the the total length of the square base edge, that value must be multiplied by 2. 

 Therefore, 

The surface area of a square pyramid can be broken into the area of the square base and the areas of the four triangluar sides. The area of a square is given by:

The area of a triangle is:

The given height of 12 in is from the vertex to the center of the base. We need to calculate the slant height of the triangular face by using the Pythagorean Theorem: 

where   and   (half the base side) resulting in a slant height of 13 in.

So, the area of the triangle is:

There are four triangular sides totaling  for the sides.

The total surface area is thus , including all four sides and the base.

The surface area of this pyramid is equal to the area of the square base plus the areas of each of the four triangular sides.

We are given the base and height of the triangular faces.

We can use  and plug in 3 and 6, giving us .

Because the base of the triangular faces is equal to 3, we know the area of the square base is .

Therefore, our total surface area is equal to 

The equation for surface area of a rectangular pyramid is as follows:

Plug in the values for length, width and height:

To find surface area of a pyramid, simply find the surface area of each of the faces and add them together.

Since there are 4 trangular faces, we have to multiply that surface area by 4. Thus,

A square pyramid has one square base and four triangular sides.

Vertices (where two or more edges come together):  5. There are four vertices on the base (one at each corner of the square) and a fifth at the top of the pyramid.

Edges (where two faces come together):  8. There are four edges on the base (one along each side) and four more along the sides of the triangular faces extending from the corners of the base to the top vertex.

Faces (planar surfaces):  5. The base is one face, and there are four triangular faces that form the top of the pyramid.

Total

Volume of Pyramid = 1/3 * Area of Base * Height

12,000 ft³ = 1/3 * 30ft * 30ft * H

12,000  = 300 * H

H = 12,000  / 300 = 40

H = 40 ft