All ACT Math Resources
Example Questions
Example Question #1 : How To Add Complex Fractions
Simplify:
.
With a complex fraction like this, begin by simplifying the numerator of the first fraction:
Next, find the common denominator of the numerator's fractions:
Next, simplify the left division by multiplying by the reciprocal:
Finally, combine the fractions:
Simplifying, this is:
Example Question #1 : How To Add Complex Fractions
Susan is training to run a race. The week before the race she ran four times. The first time she ran miles, her second run was miles, her third run was miles and her final run was miles. How many miles did Susan run this week?
In this problem we are adding complex fractions. The first step is to add the whole numbers preceding the fractions. . Next we need to find a common denominator to add the fractions. This should be the smallest number that has all of the other denominators as a factor. The least common denominator in this case is 30. Now we need to multiply the top and bottom of each fraction by the number that will make the denominator 30. From here we can add and divide the top and bottom by two to simplify.
From here we have an improper fraction so we must subtract the value of the denominator from the numerator to make a complex fraction. After subtracting once we get a proper fraction.
.
Since we subtracted once, that means we have a 1 attached to the fraction and can be added to the other 10 to make 11. Then to get the final answer we combine the whole numbers and the fraction to get .
Example Question #1 : How To Multiply Complex Fractions
What is ?
Simplify both sides first. simplifies to 6. simplifies to . Finally 6 = .
Example Question #1 : How To Multiply Complex Fractions
What is equal to?
When multiplying fractions, we can simply multiply the numerators and then multiply the denominators. Therefore, is equal to
We then do the same thing again, giving us .
Now we must find the least common denominator, which is .
We multiply the top by and the bottom by . After we do this we can multiply our numerator by the reciprocal of the denominator.
Therefore our answer becomes,
.
Example Question #1 : How To Multiply Complex Fractions
Simplify:
Begin by simplifying the denominator:
Then, you perform the division by multiplying the numerator by the reciprocal of the denominator:
Do your simplifying now:
Finally, multiply everything:
Example Question #1 : How To Multiply Complex Fractions
Simplify:
Generally, when you multiply fractions, it is a very easy affair. This does not change for complex fractions like this. You can begin by simply multiplying the numerators and denominators directly. Thus, you know:
Now, simplify this to:
or
Now, remember that when you divide fractions, you multiply the numerator by the reciprocal of the denominator:
Now, cancel your terms immediately:
, which is easy to finish:
Example Question #1 : Proportion / Ratio / Rate
A rectangular container holds a liquid. The dimensions of the container are 5 cm by 5 cm by 4 cm. If the container is half full, how much liquid is in the container (1 cm3 = 1mL)?
150 mL
20 mL
25 mL
100 mL
50 mL
50 mL
The total volume is 5 * 5 * 4 = 100 cm3 . Half of this is 50 cm3 which is 50 mL.
Example Question #1 : How To Find The Volume Of A Solution
A dog eats treats in days. At this rate, how many treats does the dog eat in days?
This is a rate problem. We need to first find out how many treats a day the dog eats. Then to find the number of treats the dog eats in days, we multiply the number of days by the number of treats a day the dog eats.
From the given information, we know that the dog eats treats a day.
Then we multiply that number by the number of days.
Now simplify.
Example Question #1 : Proportion / Ratio / Rate
One serving of party drink is comprised of of syrup, of water, and of apple juice. If a large bowl of the drink contains of apple juice, how much of the total drink is in the bowl?
The total drink is made up of . Therefore, for a problem like this, you can set up a ratio:
First, simplify the right side of the equation:
Next, solve for :
. Therefore, the total amount of drink is .
Example Question #1 : Proportion / Ratio / Rate
There is a coffee drink made of of coffee, of milk, of cream, and of flavoring. If you have an unlimited amount of flavoring and milk but only of cream and of coffee, how many ounces of drink can you make? (Presume that you cannot make partial servings.)
To begin with, you need to compute what is going to be your limiting factor. For the cream, you can make:
servings.
For the coffee, you can make:
servings.
Therefore, this second value is your total number of servings. (You must choose the minimum, for it will be what limits your beverage-making.)
So, you know that each drink is . If you can make servings (remember, no partial servings!), you can make a total of .