ACT Math : Algebra

Study concepts, example questions & explanations for ACT Math

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Example Questions

Example Question #104 : Expressions

  The expression

 

 

can be rewritten as:

Possible Answers:

Correct answer:

Explanation:

To simplify this problem, let’s look at each term individually. ; ; . Thus B is the correct answer.

Example Question #105 : Expressions

The product of two consecutive odd negative integers is . What is the smaller of the two integers?

Possible Answers:

Correct answer:

Explanation:

The problem gives us the product of two consecutive odd negative integers, so we know that one number is  less than the other one. Thus, we can set our two numbers as  and .

At this point, the more algebraically inclined student might recognize that if , then the equation can be remade to say , and use the quadratic formula to solve.

But this is the ACT, and the faster method by far is to simply recognize that if the product of our two integers is , then  must be evenly divisible by our two integers. The only two choices we have that divide evenly into  are  and , making  the smaller number and our answer.

Example Question #102 : Expressions

Suzanne is at the grocery store. She has $5.00 to spend on produce. Oranges are $2.50 per pound, apples cost $1.50 per pound and bananas are $0.50 per pound. Which combination of fruit will fit her budget?

Possible Answers:

1.5 pounds of oranges and 4 pounds of bananas

3 pounds of apples and 2 pounds of bananas

2 pounds of oranges and 1 pound of apples

1 pound of oranges, 1 pound of apples and 2 pounds of bananas

1 pound of oranges, 1.5 pounds of apples and 1.5 pounds of bananas

Correct answer:

1 pound of oranges, 1 pound of apples and 2 pounds of bananas

Explanation:

Make a simple algebra equation and test it against each combination:

Total Cost = $2.50 * (# Oranges) +  $1.50 * (# Apples) +  $0.50 * (# Bananas)

Example Question #1011 : Algebra

Change to a mixed number 

Possible Answers:

Correct answer:

Explanation:

To convert from a fraction to a mixed number we must find out how many times the denominator goes into the numerator using division and the remainder becomes the new fraction. 

 

Example Question #4 : Algebraic Fractions

What is the average of and ?

Possible Answers:

Correct answer:

Explanation:

To average, we have to add the values and divide by two. To do this we need to find a common denomenator of 6. We then add and divide by 2, yielding 4.5/6. This reduces to 3/4.

Example Question #5 : Algebraic Fractions

Which of the following is equivalent to  ?

Possible Answers:

 

None of the answers are correct

Correct answer:

Explanation:

This problem is solved the same way ½ + 1/3 is solved.  For example,  ½ + 1/3 = 3/6 + 2/6 = 5/6.  Find a common denominator then convert each fraction into an equivalent fraction using that common denominator.  The final step is to add the two new fractions and simplify.

Example Question #1012 : Algebra

A train travels at a constant rate of  meters per second. How many kilometers does it travel in  minutes?

 

Possible Answers:

Correct answer:

Explanation:

Set up the conversions as fractions and solve:

\dpi{100} \small \frac{20m}{1sec}\times \frac{60sec^}{1min}\times \frac{1km}{1000m}\times \frac{10min}{1}

Example Question #1013 : Algebra

Simplify.  \frac{4x^{4}z^{3}}{2xz^{2}}

Possible Answers:

\frac{2x^{4}z^{3}}{xz}

Can't be simplified

2x^{3}z

2x^{4}z^{3}

4x^{3}z

Correct answer:

2x^{3}z

Explanation:

To simplify exponents which are being divided, subtract the exponents on the bottom from exponents on the top.  Remember that only exponents with the same bases can be simplified

Example Question #1014 : Algebra

Simplify:

 

 

Possible Answers:

Correct answer:

Explanation:

x2 – y2 can be also expressed as (x + y)(x – y).

Therefore, the fraction now can be re-written as (x + y)(x – y)/(x + y).

This simplifies to (x – y).

Example Question #1015 : Algebra

Simplify:

Possible Answers:

Correct answer:

Explanation:

Notice that the term appears frequently. Let's try to factor that out:

Now multiply both the numerator and denominator by the conjugate of the denominator:

 

 

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