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Trigonometry : Angle Applications

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6 Diagnostic Tests 155 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1 : Area Of A Sector

If a circle has a sector with an angle of $\theta = 60$ and diameter of 4, what is the area of the sector?

Possible Answers:

$\frac{\pi}{6}$

$2\pi$

$\frac{2\pi}{3}$

$\frac{\pi}{3}$

Correct answer:

$\frac{2\pi}{3}$

Explanation:

It is always best to draw a picture in order to visualize the problem you are trying to solve. The figure below shows the sector we are trying to find the area of.

We know that the formula to find the area of a sector is $A = \frac{\theta}{2} r^2$ . From the information given above we know that the diameter is 4. Since we only need the radius for our formula we divide the diameter by 2 to get the radius length. The radius has a length of 2. We also know that we have our angle measure in degrees and must convert it to radians. We use the conversion formula $degrees \frac{\pi}{180} = radians$ .

$60 \frac{\pi}{180} = \frac{\pi}{3}$

Now we can plug everything into our formula and solve.

$A = \frac{\theta}{2}r^2$

$A = \frac{\pi}{3}\frac{1}{2} 2^2$

$A = \frac{\pi}{6}{4}$

$A = \frac{2\pi}{3}$

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Example Question #2 : Area Of A Sector

True or False: The formula to find the area of a sector only works for acute angles.

Possible Answers:

False

True

Correct answer:

True

Explanation:

This is not true. Even obtuse angles are less than $2\pi$ so this formula will still work. We can demonstrate this using the sector below. The radius of the circle is 6 and the obtuse angle is 330 degrees.

Converting 330 degrees to radians:

$330 \frac{\pi}{180} = \frac{11\pi}{6}$

We can now plug this into our formula

$A = \frac{\theta}{2} r^2$

$A = \frac{11\pi}{6}\frac{1}{2} 6^2$

$A = \frac{11\pi}{12} 36$

$A = \frac{396\pi}{12}$

$A = 33\pi$

Now we can confirm this to be true by computing the area of the sector formed by the

area leftover formed by the acute angle, 30 degrees. To do this we will first find the total

area of the circle and then subtract the area of the sector formed by the acute angle. This should be equal to the area of the larger vector if our formula works for all angles because the sum of both sectors should be the total area of the circle.

To find the area of the circle:

$\pi r^2$

$36\pi$

To find the area of the smaller sector (note, 30 degrees in radians is $\frac{\pi}{6}$ :

$A = \frac{\theta}{2} r^2$

$A = \frac{\pi}{6}\frac{1}{2} 6^2$

$A = \frac{\pi}{12} 36$

$A = 3\pi$

Clearly, the total area of the circle minus the area of the small sector is equal to the area

of the larger circle, therefore this formula works for all angles less than $2\pi$

$36\pi - 3\pi = 33\pi$

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Example Question #3 : Area Of A Sector

Knowing that the arc length of a sector $3\pi$ and the angle measure is $\theta = \frac{4\pi}{3}$ , what is the area of the sector?

Possible Answers:

$A = \frac{\pi}{3}$

$A = \frac{81\pi}{127}$

$A = \frac{\pi}{4}$

$A = \frac{27\pi}{8}$

Correct answer:

$A = \frac{27\pi}{8}$

Explanation:

To solve this problem we must know the formula for finding the arc length of a sector. This formula is $l_A = \theta r$ . With the given information we are able to solve for the radius which we can then use to solve for the area of the sector itself.

$l_A = \theta r$

$3\pi = \frac{4\pi}{3} r$

$\frac{9}{4} = r$

Now we can plug this radius into the formula to solve for the area of a sector.

$A = \frac{\theta}{2} r^2$

$A = (\frac{4\pi}{3})(\frac{1}{2})( \frac{9}{4})^2$

$A = (\frac{2\pi}{3})(\frac{81}{16})$

$A = \frac{162\pi}{48}$

$A = \frac{27\pi}{8}$

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Example Question #4 : Area Of A Sector

True or False: You have a sector of a circle and are given the radius of the circle and the total area of the circle. You are able to find the area of the sector.

Possible Answers:

True

False

Correct answer:

False

Explanation:

The formula for finding the area of a circle is $A = \pi r^2$ . If we know the radius and the area of the entire circle, we still do not know the angle that forms the sector or the arc length. Therefore we do not have enough information to solve for the sector area. In order to find the area of the sector we need to either know the angle of the sector and the radius, or have some means to solve for this information.

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Example Question #5 : Area Of A Sector

A circle has a sector formed by radii of length 3 and an angle of $\frac{5\pi}{4}$ . What is the area of the sector?

Possible Answers:

$A = \frac{9\pi}{4}$

$A = \frac{8\pi}{5}$

$A = \frac{45\pi}{8}$

$A = \frac{9\pi}{8}$

Correct answer:

$A = \frac{45\pi}{8}$

Explanation:

The formula to solve for the area of a sector is $A = \frac{\theta}{2} r^2$ . We have all the information needed to plug the values right into the formula and solve for the area.

$A = \frac{\theta}{2} r^2$

$A = (\frac{5\pi}{4})(\frac{1}{2})(3^2)$

$A = (\frac{5\pi}{8})(9)$

$A = \frac{45\pi}{8}$

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Example Question #6 : Area Of A Sector

You are given a circle with a sector that is formed by an arc length of $9\pi$ . The circle has a diameter of 20. What is the area of the sector?

Possible Answers:

$A = \frac{9\pi}{2}$

$A=\frac{9\pi}{4}$

$A=9\pi$

$A=\frac{9\pi}{20}$

Correct answer:

$A = \frac{9\pi}{2}$

Explanation:

First, if we have a diameter of 20, we know that the radius must be half of the diameter. We have a radius length of 10. Now, we know the arc length so we must use the arc length formula to solve for the angle measure. To find the length of an arc of a sector we use the formula $l_A = \theta r$ .

$l_A = \theta r$

$9\pi = \theta 10$

$\frac{9\pi}{10} = \theta$

By solving for the angle, we have enough information to solve for the sector area.

$A = \frac{\theta}{2} r^2$

$A = (\frac{9\pi}{10})(\frac{1}{2})(10^2)$

$A = (\frac{9\pi}{20}(100)$

$A = \frac{900\pi}{200}$

$A = \frac{9\pi}{2}$

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Example Question #1 : Arc Length

Which is true of the relationship between the arc measure and the central angle as shown below?

Screen shot 2020 08 27 at 4.09.48 pm

Possible Answers:

The central angle is half of the arc length

The central angle will always be a right angle

The arc length is half of the central angle

They are equal

Correct answer:

They are equal

Explanation:

Every arc has a measure that is equal to the measure of the central angle that creates the arc. This is because the measure of the angle determines the distance around the circumference that the arc makes.

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Example Question #12 : Angle Applications

Which of the following is the correct formula for finding arc length?

Possible Answers:

$l_A = \theta r^2$

$l_A = 2\theta r$

$l_A = 2\theta r^2$

$l_A = \theta r$

Correct answer:

$l_A = \theta r$

Explanation:

The circumference of an entire circle is $2\pi r$ . When considering the length of an arc, the angle is less than $2\pi$ denoted by angle $\theta$ . So the formula for finding the length of an arc is replacing the angle of an entire circle, $2\pi$ , with the angle that forms the arc, $\theta$ . This gives us the formula $l_A = \theta r$ .

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Example Question #13 : Angle Applications

Which of the following is the correct arc length formed by the angle $\frac{\pi}{3}$ of a circle whose radius is a length of 5?

Possible Answers:

$l_A = \frac{\pi}{5}$

$l_A = \frac{3\pi}{5}$

$l_A = \frac{\pi}{3}$

$l_A = \frac{5\pi}{3}$

Correct answer:

$l_A = \frac{5\pi}{3}$

Explanation:

We must use the formula for finding arc length $l_A = \theta r$ . We have been given all the information needed to just plug into the formula.

$l_A = \theta r$

$l_A = \frac{\pi}{3} 5$

$l_A = \frac{5\pi}{3}$

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Example Question #14 : Angle Applications

Which of the following is the correct arc length formed by an angle with measure 30 degrees of a circle whose radius is a length of 3?

Possible Answers:

$l_A = \frac{\pi}{6}$

$l_A = \frac{\pi}{2}$

$l_A = 2\pi$

$l_A = \frac{3\pi}{2}$

Correct answer:

$l_A = \frac{\pi}{2}$

Explanation:

First, we are given our angle measure in degrees and we must convert to radians to be able to use our arc length formula.

$30 \frac{\pi}{180} = \frac{\pi}{6}$

Now we are able to plug the radius length and the angle measure into our formula and solve for the arc length.

$l_A = \frac{\pi}{6} 3$

$l_A = \frac{3\pi}{6}$

$l_A = \frac{\pi}{2}$

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Trigonometry : Angle Applications

Study concepts, example questions & explanations for Trigonometry

All Trigonometry Resources

Example Questions

Example Question #1 : Area Of A Sector

Example Question #2 : Area Of A Sector

Example Question #3 : Area Of A Sector

Example Question #4 : Area Of A Sector

Example Question #5 : Area Of A Sector

Example Question #6 : Area Of A Sector

Example Question #1 : Arc Length

Example Question #12 : Angle Applications

Example Question #13 : Angle Applications

Example Question #14 : Angle Applications

All Trigonometry Resources

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