The common portion of this Venn diagram represents the percentage of respondents that were classified into both groups. In order to calculate the percentage that represents the amount of respondents classified into both groups, first find the sum of group $\displaystyle A$ and group $\displaystyle B$. Then subtract that quantity from $\displaystyle 100$ percent. 

The solution is: 

$\displaystyle 62+9=71$

$\displaystyle 100-71=29$ 

The common portion of this Venn diagram represents the percentage of Mr. Robinson's students that stated they planned on both swimming and traveling during the summer. In order to calculate the percentage that represents the amount of students classified into both groups, first find the sum of the swimming group and traveling group. Then subtract that sum from $\displaystyle 100\%$. 

The solution is:

$\displaystyle 54+23=77$

$\displaystyle 100-77=23$

In order to find the ratio of friends that Kelly and Antonio have in common compared to the group members who are only friends with one or the other first find the percentage value of the common portion of the Venn diagram. To calculate this value, find the sum of the two exclusive groups and then subtract that sum from $\displaystyle 100\%$. 

$\displaystyle 27+33=60$

$\displaystyle 100-60=40$

This means that $\displaystyle 40\%$ of the group members are common friends of Kelly and Antonio. To convert this percentage to a ratio, first write $\displaystyle 40\%$ as a fraction, and then simplify as a ratio. 

$\displaystyle 40\%$ is equal to: $\displaystyle \frac{40}{100}=40:100=4:10=2:5$

This means that $\displaystyle 2$ out of every $\displaystyle 5$ group members are mutual friends of Kelly and Antonio. 

To find the ratio of Kelly and Antonio's exclusive friendships to their mutual friendships--find the sum of the two exclusive groups in the Venn diagram: 

$\displaystyle 27+33=60$

This means that $\displaystyle 60\%$ of the members in the group are not friends with both Kelly and Antonio. To convert this percent to a ratio, first write $\displaystyle 60\%$ as a fraction, and then simplify as a ratio. 

$\displaystyle 60\%$ is equal to: $\displaystyle \frac{60}{100}=60:100=6:10=3:5$

This means that $\displaystyle 3$ out of every $\displaystyle 5$ group members are not mutual friends of Kelly and Antonio. 

To solve this problem first find the sum of the two exclusive groups shown in the Venn diagram: 

$\displaystyle 46+46=92$

This means that $\displaystyle 92\%$ of respondents have exclusively voted for presidential candidates from only one political party. 

To find the value of the common portion of the Venn diagram, calculate the difference between $\displaystyle 100$ and $\displaystyle 92$:

$\displaystyle 100-92=8$

This means that $\displaystyle 8\%$ of the respondents have voted for both Democratic and Republican presidential candidates. 

Since the information provided in the Venn diagram represents percentages, convert the quantity in category $\displaystyle B$ from a percentage to a fraction. To convert a percentage to a fraction, divide the percent by a divisor of $\displaystyle 100$, then simplify the fraction if applicable; however, in this case the fraction can't be reduced. 

The solution is: 

Group $\displaystyle B=9\%$

Thus:
 $\displaystyle B=9\div100=\frac{9}{100}$

Since the information provided in the Venn diagram represents percentages, convert the quantity in the common portion of the diagram from a percentage to a fraction. To convert a percentage to a fraction, divide the percentage by a divisor of $\displaystyle 100$, then simplify the fraction if possible. 

Common portion is equal to $\displaystyle 12\%$. Therefore, the solution is:

 

$\displaystyle 12\div100=\frac{12}{100}=\frac{12\div 2}{100\div 2}=\frac{6}{50}=\frac{6\div 2}{50\div 2}=\frac{3}{25}$

The common portion of this Venn diagram represents the percentage of respondents that were classified into both groups. In order to calculate the percentage that represents how many students have visted both NYC and Texas, first find the sum of group $\displaystyle NYC$ and group $\displaystyle TX$. Then subtract that quantity from $\displaystyle 100\%$.

The solution is: 

$\displaystyle 46+32=78$

$\displaystyle 100-78=22$

Since $\displaystyle 46\%$ of Ms. Dunn's class have visited only NYC, $\displaystyle 46$ out of every $\displaystyle 100$ students must have only visited NYC. This can be represented by the ratio $\displaystyle 46:100$; however, this ratio does not appear as an answer choice, so we must reduce this ratio by dividing each part by their greatest common divisor. 

The solution is:

$\displaystyle 46:100=46\div2:100\div2=23:50$

In order to calculate the fraction of Kayla's friends who only play sport, first find the sum of the common portion and video game portion of the Venn diagram. Then subtract that sum from $\displaystyle 1$ whole. 

The solution is: 

$\displaystyle \frac{3}{10}+\frac{2}{10}=\frac{5}{10}$

Note: $\displaystyle \frac{10}{10}=1$

Thus, $\displaystyle \frac{10}{10}-\frac{5}{10}=\frac{5}{10}=\frac{5\div 5}{10\div 5}=\frac{1}{2}$

This means that half of Kayla's friends only play sports.