The median is the "middle number" in a sorted list of number; therefore, reorder the numbers in numerical order: 7, 8, 12, 15, 19, 20. Since x is the middle number, it must come between 12 and 15, leaving 14 as the only viable choice.

The median is the coin which has an equal number of coins of lesser or equal value and greater or equal value on either side of it.  The median therefore falls to one of the nickels (62 quarters, dimes and nickels above it and 62 nickels and pennies below it).  The value of a nickel is 5 cents.

We first remove any 94%+ scores.  For tests scored out of 50, a 94% is a 47.  Thus anything 47 or greater will be removed.  We see that this leaves us with:

For the second half, we have tests scored out of 40.  94% of 40 gives us 37.6, thus we will only remove tests that were a 38 or better.  This leaves us with:

Now we have to convert them to percentiles.  We end up with the lists as follows. The raw scores are in parentheses:

We then order it by percentile (removing raw scores, as they are unnecessary):

We notice that the median must be between the 78 and the 87.5 percentile scores. 31 out of 40 gives us 77.5%, which is below the score associated with an earlier test.  Thus this cannot be the answer.  The remaining 4 scores are all higher than 78%, and the largest of them is equal to 87.5 (the highest bound). 

To find the median, sort the numbers from smallest to largest:

59, 65, 67, 73, 73, 73, 76, 80, 80, 83, 85, 94, 98

The median is the middle value in a list of numbers, it is the number separating the higher half of a data sample or a list of numbers from the lower half.

The median of the grades is 76.

The mode is the value occurring most often. The most occurring value in the list of numbers given is 73. So, the mode is 73.

In order to solve this problem, the tests need to be organized from smallest to largest. 

The median is the middle number in the set of data. From here the smallest and the largest numbers can be "crossed off" until one number remains. This gives the correct answer of 88. 

Reorder all the numbers from smallest to largest.

Since there are four numbers in this set, we will average the second and third number in the set to find the median.

The median is .

The median of a set of numbers is the number that falls in the middle of the set. 

If we reorder the numbers from least to greatest, we get:

The number that falls in the middle of this set is the fourth number, which is . 

To solve, simply find the middle number. Since the numbers are already ordered from smallest to largest, we can easily do this. 7 numbers means the 4th one from either end will be the middle. Thus, our answer is 17.

The median is the number that falls in the middle of a set of numbers when they are placed in order from least to greatest. 

With an odd number of numbers in this set, you always have one of the values in the set as your median (as opposed to the average of the two middle values when you have an even number of numbers in a set). Therefore, because all of the numbers in this set are integers, you cannot have 24.5 as the median 

The mean is the sum of the data values divided by the number of values or as a formula we have:

Where:

is the mean of a data set, indicates the sum of the data values and is the number of data values. So we can write:

In order to find the median, the data must first be ordered:

Since the number of values is even, the median is the mean of the two middle values. So we get: