SAT Math : Rectangles

Study concepts, example questions & explanations for SAT Math

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Example Questions

Example Question #11 : Rectangles

The width of a rectangle is .  The length of the rectangle is .  What must be the area?

Possible Answers:

Correct answer:

Explanation:

The area of a rectangle is:

Substitute the variables into the formula.

Example Question #12 : Quadrilaterals

Find the area of a rectangle with side length 7 and 9.

Possible Answers:

Correct answer:

Explanation:

To solve, simply use the formula for the area of a rectangle.

Substitute in the side length of 7 and width of 9.

Thus,

Example Question #13 : Quadrilaterals

Find the area of a rectanlge given width is 2 and length is 3.

Possible Answers:

Correct answer:

Explanation:

To solve, simply use the formula for the area of a rectangle. Thus,

Example Question #11 : How To Find The Area Of A Rectangle

A parallelogram with right angles has side lengths of and . What is its area?

Possible Answers:

Cannot be determined

Correct answer:

Explanation:

Remember that a parallelogram with right angles is a rectangle. With that in mind, all you need to do is multiply those side lengths together, knowing that they are the length and width of a rectangle:

Example Question #12 : How To Find The Area Of A Rectangle

Find the area of a rectangle given width 6 and length 9.

Possible Answers:

Correct answer:

Explanation:

To solve, simply multiply the width by the length. Using the formula, you get the answer as follows:

Additionally, you can alternatively solve this problem by drawing out a rectangle, creating 6 horizontal lines and 9 vertical ones, and then adding up the squares to reach your answer.

Example Question #13 : How To Find The Area Of A Rectangle

You have a poster of one of your favorite bands that you are planning on putting up in your dorm room. If the poster is 3 feet tall by 1.5 feet wide, what is the area of the poster?

Possible Answers:

Correct answer:

Explanation:

You have a poster of one of your favorite bands that you are planning on putting up in your dorm room. If the poster is 3 feet tall by 1.5 feet wide, what is the area of the poster?

Area of a rectangle is found via:

Example Question #21 : Quadrilaterals

If the area Rectangle A is  larger than Rectangle B and the sides of Rectangle A are  and , what is the area of Rectangle B?

Possible Answers:

Correct answer:

Explanation:

Example Question #12 : How To Find The Area Of A Rectangle

Three of the vertices of a rectangle on the coordinate plane are located at the origin, , and . Give the area of the rectangle.

Possible Answers:

Correct answer:

Explanation:

The rectangle in question is below:

Rectangle 3

The lengths of the rectangle is 10, the distance from the origin to ; its width is 7, the distance from the origin to . The area of a rectangle is equal to the product of its length and its width, so multiply:

Example Question #551 : High School Math

What is the length of the diagonal of a rectangle that is 3 feet long and 4 feet wide?

Possible Answers:

8\ feet

7\ feet

5\ feet

6\ feet

4\ feet

Correct answer:

5\ feet

Explanation:

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem:

3^{2}+4^{2} = hypotenuse^{2}

25 = hypotenuse^{2}

hypotenuse = 5

Therefore the diagonal of the rectangle is 5 feet.

Example Question #552 : High School Math

The length and width of a rectangle are in the ratio of 3:4. If the rectangle has an area of 108 square centimeters, what is the length of the diagonal?

Possible Answers:

15 centimeters

9 centimeters

12 centimeters

18 centimeters

24 centimeters

Correct answer:

15 centimeters

Explanation:

The length and width of the rectangle are in a ratio of 3:4, so the sides can be written as 3x and 4x.

We also know the area, so we write an equation and solve for x:

(3x)(4x) = 12x= 108.

x2 = 9

x = 3

Now we can recalculate the length and the width:

length = 3x = 3(3) = 9 centimeters

width = 4x = 4(3) = 12 centimeters

Using the Pythagorean Theorem we can find the diagonal, c:

length2 + width2 = c2

92 + 12= c2 

81 + 144 = c2

225 = c2

= 15 centimeters

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