You can quickly eliminate V as a possible answer, because since V must go in week 3 - and the car model that goes in week 3 cannot be put on sale during a second week - it goes on sale during week 3 and only during week 3.

You can eliminate N, because it can never be put on sale during week 2. If it was put on sale during week 2, that would force Q into week 3 with V. This would leave nowhere for M to pair up with either Q or V. So N cannot go in any of the four weeks.

You can eliminate Q, because it can never go on sale during week 1. If it was in week 1, you cannot meet the requirement that N be put on sale during the week preceding Q.

You can eliminate P, because it can never go on sale during week 3. If it was in week 3, that means it cannot be repeated in any of the other weeks; however, the final global rule tells us it must be put on sale during either week 1 or 2. So P cannot go in any of the four weeks.

The correct answer is Y. You can draw up hypothetical outcomes to prove that it can in fact fit into any of the four weeks.

To start this problem off, you'll want to fill in as many of the spots as you can deduce.

You know that V must go on sale during week 3. Since Y is going to be put on sale twice, you know one of those weeks must be week 4, based off of the third global rule.

Week 1: __, __; Week 2: __, __; Week 3: V, __; Week 4: Y, __

Next, you can turn to the N-Q order that you will need to create, based off of the first global rule. This sequence cannot go during weeks 3 and 4, because you will not be able to repeat Q or V to meet the requirement of one of those two needing to pair with M. This sequence cannot go during weeks 2 and 3, because again V and Q will unable to be repeated (since both are in week 3) to meet the requirement of one of those two needing to pair with M.

This means N must go in week 1 and Q must go in week 2:

Week 1: N, __; Week 2: Q, __; Week 3: V, __; Week 4: Y, __

For the two open spots in weeks 1 and 2, one must be used for the second apperance of Y and the other must be used for P, to meet the final global rule. This tells you that N and Q could be put on sale during the same week as Y, but it is not a must outcome - it is not necessarily always true. So N and Q are incorrect answers. We also see that there is no way for P to be put on sale during the same week as Y, so it is incorrect.

No matter where you arrange Y and P between weeks 1 and 2, that means M must go in week 3, so that it can be paired with V (M must be paired with either Q or V). This leaves only one possible car model that can go on sale during week 4: R. That is your correct answer. In every single possible outcome, R will always go on sale with Y.

This question calls upon you to attach a day of the week to the sequence.  So, if E is attached to Tuesday, then Guy will be attached to a day that is three days later.  This is so because GC (Guy and Claire together) are three slots over from E, and Friday is three days past Tuesday.  So Friday is the answer.

The correct answer involves an assignment that must be true, which means all the other options must be or could be false.  The answer choices involve two options, and the correct answer must be true as to both options.

A or B must occupy slot 4 because they must be separated by a single slot (i.e., there must be a restaurant between them).  This can only happen if slot 4 is occupied by either A or B.  Note:  A or B could occupy slot 2, but it isn't mandated.  The question here is calling upon us to find what is mandated, not what is possible.

Because only C and E can occupy slot 1, C and E cannot be in juxtaposition in slots 4 through 6.  That means C and E can only be in juxtaposition in slots 1 and 2.  But neither C nor E can be in slot 2.  Why? E cannot go into slot 2, because if that were the case, we could not fit the other restuarants into slots 4, 5, and 6.  In other words, with E in slot 2, C must occupy slot 1.  That leaves A, B, and D for slots 4, 5, and 6.  But notice:  A cannot be next to D, according to the rules.  Since A and B must be separated by one slot, this arrangement would force A to be next to D, which is not permissible.  The exact same analysis applies if C occupies slot 2.

Each of the incorrect answers violates one or more of the rules.  Carefully apply the rules to eliminate the incorrect answers.

For this question, you will need to eliminate wrong answers using the rules given in the stimulus.

The first global rule tells you that Jipp must be listed before Hack. With this deduction, you can eliminate the following sequence as a wrong answer: Fisk, Hack, Jipp, Lux, Mort, Gourd.

The second global rule tells you that Lux must be listed before Gourd. With this deduction, you can eliminate the following sequence as a wrong answer: Fisk, Jipp, Gourd, Hack, Lux, Mort.

The third global rule tells you that Hack must be in either the first, second, third, or fourth space. With this deduction, you can eliminate the following sequence as a wrong answer: Mort, Fisk, Jipp, Lux, Hack, Gourd.

The fourth global rule tells you that Fisk must be listed before Jipp. With this deduction, you can eliminate the following sequence as a wrong answer: Jipp, Lux, Mort, Hack, Fisk, Gourd.

The correct answer is: Lux, Fisk, Jipp, Hack, Gourd, Mort. This sequence conforms to all four global rules.

To determine an acceptable schedule of cars on sale, you can eliminate the wrong answers by checking each global rule against the answer choices.

The first global rule tells you that N must always be in the week immediately preceding Q. So you can eliminate two answers: the sequence that has Q in week 1 and N in week 4 AND the sequence that has N and Q together in week 2.

The second global rule tells you that M must always be with either Q or V. So you can eliminate the answer that has M in week 4 with R.

The fifth global rule tells you that P must be put on sale either on week 1 or week 2. So you can eliminate the answer that has P in week 4 only.

This leaves you with the correct answer, which is a sequence that meets all conditions: Week 1: N, P; Week 2: Q, M; Week 3: V, Y; Week 4: R, P

You can quickly eliminate M and N as a possible pair, because you know from the global rules that M must always be paired with either Q or V.

You can eliminate N and Q. The pair cannot be put in week 1, because there's no room for a second N to precede Q (required by the global rules). The pair cannot be put in week 2, because that would force N to precede Q in week 1; however, the car model that is put on sale twice must have one of those two apperances be in week 4 - with this case, N is appearing in weeks 1 and 2. The pair cannot be put in week 3 because V already occupies one of the two spaces. The pair cannot be put in week 4, because that would force N to precede Q in week 3; however, this would break the global rule of the car model put on sale twice not appearing in week 3.

You can eliminate N and V. Since this would be the only week in which N shows up, it would require that Q go during week 4. Because Q cannot appear a second time (you won't be able to put another N preceding it), M must also go in week 4 - it's the only way to meet the requirement of M pairing up with N or Q. However, this arrangement will not allow us to meet the requirement of the car model put on sale twice occurring during week 4: neither M nor Q can be put on sale twice.

You can eliminate P and V. This would require P to go with V during week 3, meaning it cannot be put on sale twice according to the third global rule. However, this would keep P from showing up in either week 1 or 2, which is required by the final global rule.

R and V is the correct answer. A possible outcome in which R and V are put on sale together is as follows:

Week 1: P, N; Week 2: M, Q; Week 3: V, R; Week 4: P, Y

With this problem, you are looking for a given piece of information that will restrict all other companies to only one possible store space - thereby resulting in only one possible full outcome.

You can eliminate Gourd selecting store space 5 as a possible answer. If Gourd chooses 5, a few of the companies have more than one option. Lux, for instance, can still select either store space 1 or 4.

You can eliminate Hack selecting store space 4 as a possible answer. If Hack chooses 4, a few of the companies have more than one option. Jipp, for instance, can still select store space 2 or 3.

You can eliminate Jipp selecting store space 2 as a possible answer. If Jipp chooses 2, Hack can still select store space 3 or 4.

You can eliminate Lux selecting store space 1 as a possible answer. If Lux chooses 1, Gourd and Mort must select spaces 5 and 6, but each can choose 5 or 6 and it still be a valid outcome.

The correct answer is Mort selecting store space 3. Only one possible outcome results if Mort chooses 3:

Fisk--Jipp--Mort--Hack--Lux--Gourd