This question gives us specific new information, so we can go ahead and diagram all possibilities to see which of the answers could be true, and which one cannot. If Oscar is first, we immediately put Nick third because of the conditional. Since Oscar is in the first spot Patricia must be sixth. We know now that Patricia and Nick are juniors, due to the rules. We also know that Oscar is a junior - since  every senior must be preceeded by a junior, the first spot cannot be a senior. Since Nick and Larissa have to come before Quinn and Melinda respectively, We have to put Larissa in the second spot. Melinda and Quinn can rotate between the fourth and fifth spots. We still need to assign the two seniors and one more junior. In order to abide by the rules, there are only two ways this can pan out. The first is : Junior, Senior, Junior, Senior, Junior, Junior. The second is: Junior, Senior, Junior, Junior, Senior, Junior. Therefore the only spots that are undetermined as far as whether they are a junior or a senior are the fourth and fifth spots. Therefore, the only possibility here that could never work is that Larissa is in the second spot and is a junior, since we know that spot must be a senior.

This question can be answered by eliminating incorrect answers based on rule violations. Any answer in which Zack appears anywhere but first is elminated. Any answer that includes Alan without Belle is eliminated. Any answer that features Yardley performing before Belle is eliminated. Any answer that includes Xue without Ernest (or vice versa) is eliminated, leaving only the correct answer.

If Xue is not chosen, Ernest also must not be chosen. This means our group consists of Zack, Charlie, Alan, Belle and Yardley. If Zack is in a group, he must be first. If Charlie and Alan are both chosen, Charlie must come before Alan. In this case the first available spot is second, so Alan cannot go second. Similarly, because of the rule about Belle and Yardley, Yardley cannot go second either. Since Yardley has to come after Belle, Belle cannot go last. The only possibility within these answers is Alan reading third. The order in this case would be: Zack, Charlie, Alan, Belle, Yardley.

This is a typical "grab a rule" type question; we can eliminate each wrong answer choice by going through each of the rules. Any answer in which Patricia is not first or last can be eliminated. Then any answer that does not feature Larissa before Melinda and Nick before Quinn can be eliminated. Finally an answer that breaks the conditional and has Oscar in the first slot without Nick in the third slot is eliminated, leaving only the correct answer.

When we set this question up, placing Larissa and Nick in the third and fourth spots respectively, we can automatically make a couple of judgements. Oscar cannot be first, since Nick is not third. We also know that Melinda and Quinn must follow Larissa and Nick, respectively. Therefore, we must fill out the last two spots with those two though they can go in either order. Since Patricia cannot be last, she must go first. Oscar will fill the only spot left, which is the second spot. Patricia is always a junior, so we can label the first spot a junior, as well as the third spot which is always occupied by a junior. We are also given the information that Nick is a junior, so we can label the fourth spot as a junior as well. With this set up, we now move to placing our seniors. Knowing that seniors must be preceeded by juniors, we can fill in the last two spots with either "junior, senior" or "senior, junior". Either way, the second spot must be reserved for the other senior.

C must be served earlier in the week than B.  A key insight in this problem is that B can only be served on Thursday or Saturday.  This follows from the fact that if B is not served on Thursday, E and F must precede B.  But this particular condition precludes B from being served on Monday, Tuesday, or Wednesday because there are insufficient slots to accommodate E, F, and the free-wine meal (C or D).  These latter dinners must precede B if B is served on a day other than Thursday.  Therefore, the only non-Thursday slot available for B is Saturday (Friday is reserved strictly for D or E).  All this leads to the conclusion that C must be served earlier in the week than B.

Dinner E must be served on Friday because only Dinners D or E can be served on Friday and the stipulation in the question requires D to be served on either Tuesday or Wednesday.  That leaves dinner E as the only option for Friday.

We know that B or C must be second, based upon all of our deductions:

A . . . B/C

A . . . C . . . F/G

B . . . E . . . D/F

By combining the latter two sequences, we can establish that B or C must take the second slot. Since the question posits that B received more votes than C, we can quickly arrive at the correct answer: B must be second.

If Yardley reads first, Belle cannot be in the game because she cannot read before Yardley. If Belle is not in the game, Alan is not in the game either. And if Yardley is in the first spot, Zack cannot be in the game at all. This leaves only Charlie, Dorian, Ernest and Xue to fill the remaining four spots. Since Charlie and Dorian can never read together, this scenario can never happen.

The important thing to note here is that, under the new conditions, mushrooms cannot be on the first pizza but tomatoes could be.  If mushrooms are on the first pizza, sausage must be on the second, but peppers and sausage may not be on the same pizza.