ISEE Upper Level Math : Circles

Study concepts, example questions & explanations for ISEE Upper Level Math

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Example Questions

Example Question #12 : How To Find Circumference

Let \(\displaystyle \pi = 3.14\)

Find the circumference of a circle with a radius of 8in.

Possible Answers:

\(\displaystyle 25.12\text{in}\)

\(\displaystyle 43.96\text{in}\)

\(\displaystyle 200.96\text{in}\)

\(\displaystyle 50.24\text{in}\)

\(\displaystyle 56.52\text{in}\)

Correct answer:

\(\displaystyle 50.24\text{in}\)

Explanation:

To find the circumference of a circle, we will use the following formula:

\(\displaystyle C = 2\pi r\)

where r is the radius of the circle. 

 

Now, we know the radius of the circle is 8in.

We also know that\(\displaystyle \pi = 3.14\).

Knowing all of this, we can substitute into the formula.  We get

\(\displaystyle C = 2 \cdot 3.14 \cdot 8\text{in}\)

\(\displaystyle C = 16\text{in} \cdot 3.14\)

\(\displaystyle C = 50.24\text{in}\)

Example Question #12 : How To Find Circumference

You want to ice skate around the outer edge of a circular pond (the water is frozen, because it is January and you live in Wisconsin). If the pond has a radius of 35 meters, how far will you skate in one lap around the pond?

Possible Answers:

\(\displaystyle 70 \pi m\)

\(\displaystyle 450 m\)

Not enough information to complete.

\(\displaystyle 1,225 \pi m\)

Correct answer:

\(\displaystyle 70 \pi m\)

Explanation:

You want to ice skate around the outer edge of a circular pond (the water is frozen, because it is January and you live in Wisconsin). If the pond has a radius of 35 meters, how far will you skate in one lap around the pond?

Let's begin by realizing what we are being asked for. They want us to find the total distance we will travel in one lap around the pond. This sounds like circumference, because we are going one full distance around the outside of the circle.

The formula for circumference is as follows.

\(\displaystyle C=2 \pi r\)

Now, we have r, so just plug in and solve.

\(\displaystyle C=2 \pi (35m)=2*35 m \pi=70 \pi m\)

So, our answer is:

\(\displaystyle 70 \pi m\)

Example Question #43 : Radius

You are conducting fieldwork, when you find a tree whose radius at chest height is \(\displaystyle 1.5m\). What is the circumference of the tree at chest height?

Possible Answers:

\(\displaystyle 5.05 \pi m\)

\(\displaystyle 4.25 \pi m\)

\(\displaystyle 2.25 \pi m\)

\(\displaystyle 3.0 \pi m\)

Correct answer:

\(\displaystyle 3.0 \pi m\)

Explanation:

You are conducting fieldwork, when you find a tree whose radius at chest height is \(\displaystyle 1.5m\). What is the circumference of the tree at chest height?

The formula for circumference of a circle is:

\(\displaystyle C= 2 \pi r\)

We have r, so simply plug it in and solve:

\(\displaystyle C=2 \pi (1.5m)=3 \pi m\)

So, our answer is \(\displaystyle 3 \pi m\)

Example Question #71 : Circles

Find the circumference of a circle with a diameter of 18cm.

Possible Answers:

\(\displaystyle 36\pi \text{ cm}\)

\(\displaystyle 24\pi \text{ cm}\)

\(\displaystyle 18\pi \text{ cm}\)

\(\displaystyle 52\pi \text{ cm}\)

\(\displaystyle 9\pi \text{ cm}\)

Correct answer:

\(\displaystyle 18\pi \text{ cm}\)

Explanation:

To find the circumference of a circle, we will use the following formula:

\(\displaystyle C = \pi d\)

where d is the diameter of the circle.

Now, we know the diameter of the circle is 18cm.  So, we will substitute.  We get

\(\displaystyle C = \pi \cdot 18\text{cm}\)

\(\displaystyle C = 18\pi \text{ cm}\)

Example Question #45 : Radius

Find the circumference of a circle with a radius of 10in.

Possible Answers:

\(\displaystyle 100\pi \text{ in}\)

\(\displaystyle 75\pi \text{ in}\)

\(\displaystyle 20\pi \text{ in}\)

\(\displaystyle 50\pi \text{ in}\)

\(\displaystyle 25\pi \text{ in}\)

Correct answer:

\(\displaystyle 20\pi \text{ in}\)

Explanation:

To find the circumference of a circle, we will use the following formula:

\(\displaystyle C = 2\pi r\)

where r is the radius of the circle. 

Now, we know the radius of the circle is 10in.  

So, we get

\(\displaystyle C = 2 \cdot \pi \cdot 10\text{in}\)

\(\displaystyle C = 20\text{in} \cdot \pi\)

\(\displaystyle C = 20\pi \text{ in}\)

Example Question #202 : Plane Geometry

You are exploring the woods near your house, when you come across an impact crater. It is perfectly circular, and you estimate its area to be \(\displaystyle 169 \pi m^2\).

What is the circumference of the crater?

Possible Answers:

\(\displaystyle 26 m^2\)

\(\displaystyle 39 m\)

\(\displaystyle 26 \pi m\)

\(\displaystyle 26m\)

Correct answer:

\(\displaystyle 26 \pi m\)

Explanation:

You are exploring the woods near your house, when you come across an impact crater. It is perfectly circular, and you estimate its area to be \(\displaystyle 169 \pi m^2\).

What is the circumference of the crater?

To solve this, we need to recall the formula for the area of a circle.

\(\displaystyle A=\pi r^2\)

Now, we know A, so we just need to plug in and solve for r!

\(\displaystyle 169 \pi m^2=\pi r ^2\)

Begin by dividing out the pi

\(\displaystyle 169m^2=r^2\)

Then, square root both sides.

\(\displaystyle r=\sqrt{169m^2}=13m\)

Next, plug our answer into the circumference formula.

\(\displaystyle C=2 \pi r = 2 (13m) \pi =26 \pi m\)

Example Question #1 : How To Find The Angle For A Percentage Of A Circle

Sector TYP occupies 43% of a circle. Find the degree measure of angle TYP.

 

Possible Answers:

\(\displaystyle 154.8^{\circ}\)

\(\displaystyle 366^{\circ}\)

\(\displaystyle 430^{\circ}\)

\(\displaystyle 15.5^{\circ}\)

Correct answer:

\(\displaystyle 154.8^{\circ}\)

Explanation:

Sector TYP occupies 43% of a circle. Find the degree measure of angle TYP.

Use the following formula and solve for x:

\(\displaystyle \frac{x}{360^{\circ}}100=43\%\)

Begin by dividing over the 100

\(\displaystyle \frac{x}{360^{\circ}}=.43\)

Then multiply by 360

\(\displaystyle x=.43*360^{\circ}=154.8^{\circ}\)

Example Question #1 : How To Find The Angle For A Percentage Of A Circle

If sector AJL covers 45% of circle J, what is the measure of sector AJL's central angle?

Possible Answers:

\(\displaystyle 145^{\circ}\)

\(\displaystyle 162^{\circ}\)

\(\displaystyle 45^{\circ}\)

\(\displaystyle 262^{\circ}\)

Correct answer:

\(\displaystyle 162^{\circ}\)

Explanation:

If sector AJL covers 45% of circle J, what is the measure of sector AJL's central angle?

To find an angle measure from a percentage, simply convert the percentage to a decimal and then multiply it by 360 degrees.

\(\displaystyle 45\%\rightarrow 0.45\)

\(\displaystyle 0.45 * 360^{\circ}=162^{\circ}\)

So, our answer is 162 degrees.

Example Question #1 : How To Find The Area Of A Sector

Sector

Give the area of the white region of the above circle if \(\displaystyle \overarc{AB}\) has length \(\displaystyle 12 \pi\)

Possible Answers:

\(\displaystyle 243 \pi\)

\(\displaystyle 729 \pi\)

\(\displaystyle 81 \pi\)

\(\displaystyle 567 \pi\)

Correct answer:

\(\displaystyle 567 \pi\)

Explanation:

If we let \(\displaystyle C\) be the circumference of the circle, then the length of \(\displaystyle \overarc{AB}\) is \(\displaystyle \frac{80}{360} = \frac{2}{9 }\) of the circumference, so

\(\displaystyle \frac{2}{9 } C = 12 \pi\)

\(\displaystyle \frac{9 }{2}\cdot \frac{2}{9 } C =\frac{9 }{2}\cdot 12 \pi\)

\(\displaystyle C =54\pi\)

The radius is the circumference divided by \(\displaystyle 2 \pi\):

\(\displaystyle r= 54 \pi \div 2 \pi = 27\)

Use the formula to find the area of the entire circle:

\(\displaystyle A = \pi r ^{2} = \pi \left (27 \right )^{2} = 729 \pi\)

The area of the white region is \(\displaystyle 1 - \frac{2}{9} = \frac{7}{9}\) of that of the circle, or 

\(\displaystyle \frac{7}{9} \cdot 729 \pi = 567 \pi\)

 

Example Question #211 : Geometry

Sector

The circumference of the above circle is \(\displaystyle 30 \pi\). Give the area of the shaded region.

Possible Answers:

\(\displaystyle 50 \pi\)

\(\displaystyle 400 \pi\)

\(\displaystyle 25 \pi\)

\(\displaystyle 100 \pi\)

Correct answer:

\(\displaystyle 50 \pi\)

Explanation:

The radius of a circle is found by dividing the circumference \(\displaystyle C = 30 \pi\) by \(\displaystyle 2 \pi\):

\(\displaystyle r= \frac{C}{2 \pi}= \frac{30 \pi}{2 \pi} = 15\)

The area of the entire circle can be found by substituting for \(\displaystyle r\) in the formula:

\(\displaystyle A = \pi r ^{2} = \pi \cdot 15 ^{2} = 225 \pi\).

The area of the shaded \(\displaystyle 80 ^{\circ }\) sector is \(\displaystyle \frac{80 }{360 }\) of the total area:

\(\displaystyle \frac{80 }{360 } \times 225 \pi = \frac{2}{9} \times 225 \pi = 50 \pi\)

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