We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

ISEE Upper Level Math : How to find the missing part of a list

Study concepts, example questions & explanations for ISEE Upper Level Math

Create An Account

All ISEE Upper Level Math Resources

6 Diagnostic Tests 244 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #684 : Isee Upper Level (Grades 9 12) Mathematics Achievement

Define set $A = \left \{ 1, 2, 4, 8, 10, a, g, j, r, w \right \}$ . Which of the following sets could we define to be set so that $A \cap B = \varnothing$ ?

Possible Answers:

$B= \left \{ 3,5, 6,8,14,d,f,s,t,x\right \}$

$B =\left \{ 3, 5, 7, 10, 13, e, f, h, k, y \right \}$

$B = \left \{ 3, 6, 7, 9, 12, b, e, h, s, t\right \}$

$B = \left \{ 5,6,7,11,17, f,h,i,k,r\right \}$

$B = \left \{ 3, 5, 6, 7, 9, e, g, t, u, x\right \}$

Correct answer:

$B = \left \{ 3, 6, 7, 9, 12, b, e, h, s, t\right \}$

Explanation:

For $A \cap B = \varnothing$ to be a true statement, sets and cannot have any elements in common. We can eliminate four of these choices of by noting that in each, there is one element (underlined) also in :

$\left \{ 3,5, 6,\underline{8},14,d,f,s,t,x\right \}$

$\left \{ 3, 5, 7, \underline{10}, 13, e, f, h, k, y \right \}$

$\left \{ 3, 5, 6, 7, 9, e, \underline{g}, t, u, x\right \}$

$\left \{ 5,6,7,11,17, f,h,i,k,\underline{r}\right \}$

However, $B = \left \{ 3, 6, 7, 9, 12, b, e, h, s, t\right \}$ shares no elements with $A = \left \{ 1, 2, 4, 8, 10, a, g, j, r, w \right \}$ , so their intersection is $\varnothing$ by definition. This is the correct choice.

Report an Error

Example Question #685 : Isee Upper Level (Grades 9 12) Mathematics Achievement

Given a set $A = \left \{ 1,3, 6, 7, 8\right \}$ , which of the following sets could we assign to such that $A \cup B = \left \{ 1,2, 3, 4, 5, 6, 7, 8, 9, 10\right \}$ ?

Possible Answers:

$\left \{ 2, 4, 9, 10 \right \}$

$\left \{ 2, 9,5, 4, 10, 8\right \}$

$\left \{ 6,5,4, 9, 10\right \}$

None of the choices answer the question correctly.

$\left \{1, 2, 4, 5, 6, 9, 10, 12\right \}$

Correct answer:

$\left \{ 2, 9,5, 4, 10, 8\right \}$

Explanation:

$A \cup B$ is the union of the sets, i.e. the set of all elements in , , or both.

For $A \cup B = \left \{ 1,2, 3, 4, 5, 6, 7, 8, 9, 10\right \}$ , must include all elements in $\left \{ 1,2, 3, 4, 5, 6, 7, 8, 9, 10\right \}$ that are not in , or $\left \{ 2, 4, 5, 9, 10\right \}$ . This allows us to eliminate $\left \{ 2, 4, 9, 10 \right \}$ , which excludes 5, and $\left \{ 6,5,4, 9, 10\right \}$ , which excludes 2.

Also, cannot include any element not in $\left \{ 1,2, 3, 4, 5, 6, 7, 8, 9, 10\right \}$ . This allows us to eliminate $\left \{1, 2, 4, 5, 6, 9, 10, 12\right \}$ , which includes 12.

This leaves $\left \{ 2, 9,5, 4, 10, 8\right \}$ .

If $B = \left \{ 2, 9,5, 4, 10, 8\right \}$ , then

$A \cup B =\left \{ 1,3, 6, 7, 8\right \} \cup \left \{ 2, 9,5, 4, 10, 8\right \}$

$= \left \{ 1,2, 3, 4, 5, 6, 7, 8, 9, 10\right \}$ .

This is the correct choice.

Report an Error

Example Question #686 : Isee Upper Level (Grades 9 12) Mathematics Achievement

Examine the sequence:

$5, 6, 8, 11, 15, 20, 26, \square, \bigcirc,...$

What number goes into the circle?

Possible Answers:

Correct answer:

Explanation:

Each element is obtained by adding a number to the previous one; the number added increases by 1 each time:

5 + 1 = 6

6 + 2 = 8

8 + 3 = 11

11 + 4 = 15

15 + 5 = 20

20 + 6 = 26

26 + 7 = 33 - this number replaces the square

33 + 8 = 41 - this number replaces the circle

Report an Error

Example Question #1 : How To Find The Missing Part Of A List

A pair of fair dice are tossed. What is the probability that the product of the numbers of the faces is greater than or equal to ?

Possible Answers:

$\frac {5}{18}$

$\frac {1}{3}$

$\frac {1}{4}$

$\frac {1}{6}$

$\frac {2}{9}$

Correct answer:

$\frac {2}{9}$

Explanation:

Out of a possible thirty-six rolls, the following result in a product of twenty or greater:

$\left\{ (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 4), (6, 5), (6, 6) \right\}$

This is eight out of thirty-six, making the probability

$\frac{8}{36} = \frac {2}{9}$ .

Report an Error

Example Question #1 : Sets

Ten students are running for student council; each member of the student body will choose four.

Two of the candidates are Kevin's brothers, Mickey and Steve. Kevin wants to vote for one, but not both, of his brothers. How many ways can Kevin fill out his ballot so that he can vote for exactly one of his brothers?

Possible Answers:

672

224

336

112

Correct answer:

112

Explanation:

Kevin will choose three students from the eight who are not his brothers, and will do so without respect to order. This is the number of combinations of three from eight:

$C(8,3) = \frac{8!}{(8-3)!\; 3!} = \frac{8!}{5!\; 3!} = \frac{40,320}{120 \times 6} = 56$

Kevin will also choose one of his two brothers. By the multiplication principle, Kevin has $56 \times 2 = 112$ ways to fill out the ballot.

Report an Error

Example Question #2 : How To Find The Missing Part Of A List

Define $f (x) = \frac{1}{x ^{2}+ 9 }$

What is the natural domain of ?

Possible Answers:

$(3 , \infty)$

$(-\infty , 3) \cup (3 , \infty)$

$(-\infty ,3)$

$(-\infty , \infty)$

Correct answer:

$(-\infty , \infty)$

Explanation:

The only possible restriction of the domain here is the denominator $x ^{2}+ 9$ , which cannot be equal to 0. We can find any such values of as follows:

$x ^{2}+ 9 = 0$

$x ^{2}+ 9- 9 = 0 - 9$

$x ^{2} = - 9$

This has no real solution, so the domain is the set of all real numbers, $(-\infty , \infty)$ .

Report an Error

Example Question #5 : How To Find The Missing Part Of A List

Nine students are running for student council; each member of the student body will choose four.

The candidates include two of Eileen's sisters, Maureen and Colleen. Eileen wants to vote for one or both of them. How many ways can Eileen fill out her ballot so that one or both of her sisters is among her choices?

Possible Answers:

154

112

133

Correct answer:

133

Explanation:

If Eileen wants to choose both sisters, then she will choose two out of the other seven candidates. This is the number of combinations of two out of seven:

$C (7,2) = \frac{7!}{(7-2)!\; 2!} = \frac{7!}{5!\; 2!} = \frac{5,040}{120 \times 2} = 21$

If Eileen wants to choose one sister, then she will choose three out of the other eight candidates. This is the number of combinations of three out of eight:

$C (8,3) = \frac{8!}{(8-3)!\; 3!} = \frac{8!}{5!\; 3!} = \frac{40,320}{120 \times 6} = 56$

Since there are also two ways Eileen can choose one sister, by the multiplication principle, she can fill out the ballot $56\times 2 = 112$ ways that include one sister.

Add these two:

112 + 21 = 133

Report an Error

Example Question #1 : How To Find The Missing Part Of A List

Define $f (x) = \frac{1}{x ^{2}+ 9 }$

What is the range of ?

Possible Answers:

$\left [\frac{1}{9}, \infty \right )$

$\left ( \frac{1}{9}, \infty \right )$

$\left ( 0, \frac{1}{9}\right )$

$\left ( 0, \frac{1}{9}\right ]$

Correct answer:

$\left ( 0, \frac{1}{9}\right ]$

Explanation:

$x ^{2} \geq 0$ , so

$x ^{2} + 9 \geq 0+ 9$ , or

$x ^{2} + 9 \geq 9$

Since $x ^{2} + 9 \geq 9$ , then

$0 < \frac{1 }{x ^{2} + 9} \leq \frac{1}{9}$

The range is therefore

$\left ( 0, \frac{1}{9}\right ]$

Report an Error

Example Question #7 : How To Find The Missing Part Of A List

The Department of Motor Vehicles wants to make all of the state's license numbers conform to two rules:

Rule 1: The number must comprise two letters (A-Z) followed by four numerals (0-9).

Rule 2: Numerals can be repeated but not letters.

Which of the following expressions is equal to the number of possible license numbers that would conform to this rule?

Possible Answers:

$25 ^{2} \times 10 ^{4}$

$25 ^{2} \times P (10,4 )$

$26 \times 25 \times P (10,4 )$

$26 \times 25 \times 10 ^{4}$

Correct answer:

$26 \times 25 \times 10 ^{4}$

Explanation:

The first letter can be any one of the 26 letters, but after this choice is made, since the letter cannot be repeated, there are 25 choices for the second letter. Each of the next four characters can each be one of the 10 numerals, with repetition allowed. By the multiplication principle, the number of possible license numbers is

$26 \times 25 \times 10 \times 10 \times 10 \times 10 = 26\times 25 \times 10 ^{4}$

Report an Error

Example Question #6 : Sets

The Department of Motor Vehicles wants to make all of the state's license numbers conform to two rules:

Rule 1: The number must comprise two letters (A-Z) followed by four numerals (0-9).

Rule 2: Repeats are allowed, but neither of the letters can be an "O" or an "I".

Which of the following expressions is equal to the number of possible license numbers that would conform to this rule?

Possible Answers:

$24 \times 23 \times C (10,4 )$

$24 ^{2} \times C (10,4 )$

$24 \times 23 \times 10 ^{4}$

$24 ^{2} \times 10 ^{4}$

Correct answer:

$24 ^{2} \times 10 ^{4}$

Explanation:

Repeats are allowed, so the first character can be one of the 24 allowed letters (26 minus the "I" and the "O"), as can the second; each of the next four characters can each be one of the 10 numerals. By the multiplication principle, the number of possible license plate numbers is:

$24 \times 24 \times 10 \times 10 \times 10 \times 10 = 24^{2} \times 10 ^{4}$

Report an Error

View Tutors

Robert
Certified Tutor

University of North Carolina at Chapel Hill, Bachelor in Arts, English. North Carolina Central University, Master of Arts, En...

View Tutors

Gregory
Certified Tutor

Pennsylvania State University-Main Campus, Bachelor of Science, Chemical Engineering. Carnegie Mellon University, Doctor of P...

View Tutors

Crystal
Certified Tutor

SUNY at Binghamton, Bachelor of Science, Mechanical Engineering.

All ISEE Upper Level Math Resources

6 Diagnostic Tests 244 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Calculus Tutors in Philadelphia, Statistics Tutors in New York City, GMAT Tutors in New York City, Computer Science Tutors in Washington DC, French Tutors in Atlanta, SAT Tutors in Dallas Fort Worth, MCAT Tutors in Seattle, Physics Tutors in Denver, Chemistry Tutors in San Diego, Computer Science Tutors in Los Angeles

Popular Courses & Classes

GMAT Courses & Classes in Washington DC, SAT Courses & Classes in San Diego, SAT Courses & Classes in Los Angeles, ACT Courses & Classes in New York City, GMAT Courses & Classes in Seattle, SSAT Courses & Classes in San Diego, LSAT Courses & Classes in Phoenix, SSAT Courses & Classes in Boston, GMAT Courses & Classes in Denver, GMAT Courses & Classes in Philadelphia

Popular Test Prep

ACT Test Prep in New York City, SSAT Test Prep in Denver, ISEE Test Prep in Miami, GRE Test Prep in Denver, ACT Test Prep in San Francisco-Bay Area, SAT Test Prep in Chicago, GMAT Test Prep in Philadelphia, LSAT Test Prep in Los Angeles, GRE Test Prep in San Francisco-Bay Area, SAT Test Prep in Boston

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

ISEE Upper Level Math : How to find the missing part of a list

Study concepts, example questions & explanations for ISEE Upper Level Math

All ISEE Upper Level Math Resources

Example Questions

Example Question #684 : Isee Upper Level (Grades 9 12) Mathematics Achievement

Example Question #685 : Isee Upper Level (Grades 9 12) Mathematics Achievement

Example Question #686 : Isee Upper Level (Grades 9 12) Mathematics Achievement

Example Question #1 : How To Find The Missing Part Of A List

Example Question #1 : Sets

Example Question #2 : How To Find The Missing Part Of A List

Example Question #5 : How To Find The Missing Part Of A List

Example Question #1 : How To Find The Missing Part Of A List

Example Question #7 : How To Find The Missing Part Of A List

Example Question #6 : Sets

All ISEE Upper Level Math Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: