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ISEE Middle Level Quantitative : Whole Numbers

Study concepts, example questions & explanations for ISEE Middle Level Quantitative

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Example Questions

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Example Question #9 : Multiply Or Divide To Solve Word Problems Involving Multiplicative Comparison: Ccss.Math.Content.4.Oa.A.2

It takes Nancy $10\textup{ minutes}$ to get dressed in the morning. It takes her older sister, Jessica, times as long. How long does it take Jessica to get dressed?

Possible Answers:

$80\textup{ minutes}$

$70\textup{ minutes}$

$40\textup{ minutes}$

$60\textup{ minutes}$

$50\textup{ minutes}$

Correct answer:

$60\textup{ minutes}$

Explanation:

The phrase " times as long" tells you that we are going to multiply by .

Let's have represent how long it takes Jessica to get dressed.

$10\times6=t$

Think: minutes times would be how many minutes?

Screen shot 2015 10 06 at 9.36.02 am

$10\times6=60$

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Example Question #10 : Multiply Or Divide To Solve Word Problems Involving Multiplicative Comparison: Ccss.Math.Content.4.Oa.A.2

It takes David $4\textup{ minutes}$ to get dressed in the morning. It takes her older sister, Melissa, times as long. How long does it take Melissa to get dressed?

Possible Answers:

$25\textup{ minutes}$

$22\textup{ minutes}$

$26\textup{ minutes}$

$23\textup{ minutes}$

$24\textup{ minutes}$

Correct answer:

$24\textup{ minutes}$

Explanation:

The phrase " times as long" tells you that we are going to multiply by .

Let's have represent how long it takes Melissa to get dressed.

$4\times6=t$

Think: minutes times would be how many minutes?

Screen shot 2015 10 06 at 10.45.11 am

$4\times6=24$

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Example Question #51 : Common Core Math: Grade 4

It takes Megan $3\textup { minutes}$ to get dressed in the morning. It takes her older sister, Stephanie, times as long. How long does it take Stephanie to get dressed?

Possible Answers:

$24\textup { minutes}$

$20\textup { minutes}$

$21\textup { minutes}$

$23\textup { minutes}$

$22\textup { minutes}$

Correct answer:

$24\textup { minutes}$

Explanation:

The phrase " times as long" tells you that we are going to multiply by

Let's have represent how long it takes Stephanie to get dressed.

$3\times8=t$

Think: minutes times would be how many minutes?

Screen shot 2015 10 06 at 10.52.44 am

$3\times8=24$

Report an Error

Example Question #52 : Common Core Math: Grade 4

It takes Tracy $5\textup { minutes}$ to get dressed in the morning. It takes her older sister, Angie, times as long. How long does it take Angie to get dressed?

Possible Answers:

$44\textup { minutes}$

$40\textup { minutes}$

$41\textup { minutes}$

$43\textup { minutes}$

$42\textup { minutes}$

Correct answer:

$40\textup { minutes}$

Explanation:

The phrase " times as long" tells you that we are going to multiply by

Let's have represent how long it takes Angie to get dressed.

$5\times8=t$

Think: minutes times would be how many minutes?

Screen shot 2015 10 06 at 10.56.03 am

$5\times8=40$

Report an Error

Example Question #2 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\frac{\begin{array}[b]{r}1 3\\ \times\ 11\end{array}}{\ \ \ \ }$

Possible Answers:

130

143

113

164

133

Correct answer:

143

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 3}\\ \times\ {1\color{Red} 1}\end{array}}{\ \ \ \ \ 3}$

Then, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}3\\ \times\ {1\color{Red} 1}\end{array}}{\ \ \ 13}$

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a as a place holder in the ones position.

$\frac{\begin{array}[b]{r}1 3\\ \times\ 11\end{array}}{\ \ \ 13 }\\ {\ \ \ \ \ \ \ \ \ \ \ 0}$

Next, we multiply and

$\frac{\begin{array}[b]{r}1 {\color{Red} 3}\\ \times\ {\color{Red} 1}1\end{array}}{\ \ \ 13 }\\ {\ \ \ \ \ \ \ \ \ 30}$

Then, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1} {\color{Black} 3}\\ \times\ {\color{Red} 1}1\end{array}}{\ \ \ 13 }\\ {\ \ \ \ \ \ \ \ 1 30}$

Finally, we add the two products together to find our final answer

$\frac{\begin{array}[b]{r}13\\ \times \ \ \ 11\end{array}}{\frac{\begin{array}[b]{r}{\color{Red} 13}\\ \ +\ {\color{Red} 130} \end{array}}{\ }} \\ {\ \ \ \ \ \ \ \ \ \ \ 143}$

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Example Question #3 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\frac{\begin{array}[b]{r}21\\ \times\ 17\end{array}}{\ \ \ \ }$

Possible Answers:

147

257

357

432

210

Correct answer:

357

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}2{\color{Red} 1}\\ \times\ {1\color{Red} 7}\end{array}}{\ \ \ \ \ 7}$

Then, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 2}1\\ \times\ {1\color{Red} 7}\end{array}}{\ \ 147}$

$\frac{\begin{array}[b]{r}21\\ \times\ 17\end{array}}{\ \ 147 }\\ {\ \ \ \ \ \ \ \ \ \ \ 0}$

Next, we multiply and

$\frac{\begin{array}[b]{r}2 {\color{Red} 1}\\ \times\ {\color{Red} 1}7\end{array}}{\ \ 147 }\\ {\ \ \ \ \ \ \ \ \ \ 10}$

Then, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 2} {\color{Black} 1}\\ \times\ {\color{Red} 1}7\end{array}}{\ \ 147 }\\ {\ \ \ \ \ \ \ \ 210}$

Finally, we add the two products together to find our final answer

$\frac{\begin{array}[b]{r}21\\ \times \ \ \ 17\end{array}}{\frac{\begin{array}[b]{r}{\color{Red} 147}\\ \ +\ {\color{Red} 210} \end{array}}{\ }} \\ {\ \ \ \ \ \ \ \ \ \ \ 357}$

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Example Question #4 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\frac{\begin{array}[b]{r}3 6\\ \times\ 12\end{array}}{\ \ \ \ }$

Possible Answers:

512

660

486

256

432

Correct answer:

432

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}^13{\color{Red} 6}\\ \times\ {1\color{Red} 2}\end{array}}{\ \ \ \ \ 2}$

Then, we multiply and and add the that was carried

$\frac{\begin{array}[b]{r}^{\color{Red} 1}{\color{Red} 3}6\\ \times\ {1\color{Red} 2}\end{array}}{\ \ \ \ 72}$

$\frac{\begin{array}[b]{r}3 6\\ \times\ 12\end{array}}{\ \ \ 72 }\\ {\ \ \ \ \ \ \ \ \ \ \ 0}$

Next, we multiply and

$\frac{\begin{array}[b]{r}3 {\color{Red} 6}\\ \times\ {\color{Red} 1}2\end{array}}{\ \ \ 72 }\\ {\ \ \ \ \ \ \ \ \ 60}$

Then, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 3} {\color{Black} 6}\\ \times\ {\color{Red} 1}2\end{array}}{\ \ \ 72 }\\ {\ \ \ \ \ \ \ \ 360}$

Finally, we add the two products together to find our final answer

$\frac{\begin{array}[b]{r}36\\ \times \ \ \ 12\end{array}}{\frac{\begin{array}[b]{r}{\color{Red} 72}\\ \ +\ {\color{Red} 360} \end{array}}{\ }} \\ {\ \ \ \ \ \ \ \ \ \ \ 432}$

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Example Question #5 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\frac{\begin{array}[b]{r}3 3\\ \times\ 23\end{array}}{\ \ \ \ }$

Possible Answers:

627

834

960

759

554

Correct answer:

759

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}3{\color{Red} 3}\\ \times\ {2\color{Red} 3}\end{array}}{\ \ \ \ \ 9}$

Then, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 3}3\\ \times\ {2\color{Red} 3}\end{array}}{\ \ \ 99}$

$\frac{\begin{array}[b]{r}3 3\\ \times\ 23\end{array}}{\ \ \ 99 }\\ {\ \ \ \ \ \ \ \ \ \ \ 0}$

Next, we multiply and

$\frac{\begin{array}[b]{r}3 {\color{Red} 3}\\ \times\ {\color{Red} 2}3\end{array}}{\ \ \ 99 }\\ {\ \ \ \ \ \ \ \ \ 60}$

Then, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 3} {\color{Black} 3}\\ \times\ {\color{Red} 2}3\end{array}}{\ \ \ 99 }\\ {\ \ \ \ \ \ \ \ 660}$

Finally, we add the two products together to find our final answer

$\frac{\begin{array}[b]{r}33\\ \times \ \ \ 23\end{array}}{\frac{\begin{array}[b]{r}{\color{Red} 99}\\ \ +\ {\color{Red} 660} \end{array}}{\ }} \\ {\ \ \ \ \ \ \ \ \ \ \ 759}$

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Example Question #6 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\frac{\begin{array}[b]{r}14\\ \times\ 22\end{array}}{\ \ \ \ }$

Possible Answers:

396

226

308

432

476

Correct answer:

308

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 4}\\ \times\ {2\color{Red} 2}\end{array}}{\ \ \ \ \ 8}$

Then, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}4\\ \times\ {2\color{Red} 2}\end{array}}{\ \ \ 28}$

$\frac{\begin{array}[b]{r}1 4\\ \times\ 22\end{array}}{\ \ \ 28 }\\ {\ \ \ \ \ \ \ \ \ \ \ 0}$

Next, we multiply and

$\frac{\begin{array}[b]{r}1 {\color{Red} 4}\\ \times\ {\color{Red} 2}2\end{array}}{\ \ \ 28 }\\ {\ \ \ \ \ \ \ \ \ 80}$

Then, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1} {\color{Black} 4}\\ \times\ {\color{Red} 2}2\end{array}}{\ \ \ 28 }\\ {\ \ \ \ \ \ \ \ 280}$

Finally, we add the two products together to find our final answer

$\frac{\begin{array}[b]{r}14\\ \times \ \ \ 22\end{array}}{\frac{\begin{array}[b]{r}{\color{Red} 28}\\ \ +\ {\color{Red} 280} \end{array}}{\ }} \\ {\ \ \ \ \ \ \ \ \ \ \ 308}$

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Example Question #7 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\frac{\begin{array}[b]{r}43\\ \times\ 35\end{array}}{\ \ \ \ }$

Possible Answers:

804

932

$1\textup,505$

985

876

Correct answer:

$1\textup,505$

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}^14{\color{Red} 3}\\ \times\ {3\color{Red} 5}\end{array}}{\ \ \ \ \ 5}$

Then, we multiply and and add the that was carried

$\frac{\begin{array}[b]{r}^{\color{Red} 1}{\color{Red} 4}3\\ \times\ {3\color{Red} 5}\end{array}}{\ \ \ 215}$

$\frac{\begin{array}[b]{r}43\\ \times\ 35\end{array}}{\ \ \ 215 }\\ {\ \ \ \ \ \ \ \ \ \ \ \ 0}$

Next, we multiply and

$\frac{\begin{array}[b]{r}4 {\color{Red} 3}\\ \times\ {\color{Red} 3}5\end{array}}{\ \ \ 215 }\\ {\ \ \ \ \ \ \ \ \ \ 90}$

Then, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 4} {\color{Black} 3}\\ \times\ {\color{Red} 3}5\end{array}}{\ \ \ 215 }\\ {\ \ \ \ \ \ \ 1290}$

Finally, we add the two products together to find our final answer

$\frac{\begin{array}[b]{r}43\\ \times \ \ \ 35\end{array}}{\frac{\begin{array}[b]{r}{\color{Red} 215}\\ \ +\ {\color{Red} 1290} \end{array}}{\ }} \\ {\ \ \ \ \ \ \ \ \ \ \ 1505}$

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ISEE Middle Level Quantitative : Whole Numbers

Study concepts, example questions & explanations for ISEE Middle Level Quantitative

All ISEE Middle Level Quantitative Resources

Example Questions

Example Question #9 : Multiply Or Divide To Solve Word Problems Involving Multiplicative Comparison: Ccss.Math.Content.4.Oa.A.2

Example Question #10 : Multiply Or Divide To Solve Word Problems Involving Multiplicative Comparison: Ccss.Math.Content.4.Oa.A.2

Example Question #51 : Common Core Math: Grade 4

Example Question #52 : Common Core Math: Grade 4

Example Question #2 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #3 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #4 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #5 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #6 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #7 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

All ISEE Middle Level Quantitative Resources

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