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ISEE Middle Level Quantitative : Whole Numbers

Study concepts, example questions & explanations for ISEE Middle Level Quantitative

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All ISEE Middle Level Quantitative Resources

6 Diagnostic Tests 110 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #128 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}6\\ \times\phantom{0}3\space{\,}4 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

29240

2914

2934

2924

Correct answer:

2924

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 34 is the multiplier and 86 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 4 and 6

$\begin{array}{r}\overset{2 \space{\ }}{\ 8} \space{\,}6\\ \times \phantom{0} 3\space{\,}4\\ \hline \phantom{\,} \,4\end{array}$

Then, we multiply 4 and 8 and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 8} \space{\,}6\\ \times \phantom{0} 3\space{\,}4 \\ \hline \phantom{\,}3\,4\,4\end{array}$

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a 0 as a place holder in the ones position.

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}6\\ \times \phantom{0} 3\space{\,}4 \\ \hline \phantom{\,}3\,4\,4 \\ \, 0 \end{array}$

Next, we multiply 3 and 6

$\begin{array}{r}\overset{1 \space{\ }}{\ 8} \space{\,}6\\ \times \phantom{0} 3\space{\,}4 \\ \hline \phantom{\,}3\,4\,4 \\ \, 8 \, 0\end{array}$

Then, we multiply 3 and 8and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 8} \space{\,}6\\ \times \phantom{0} 3\space{\,}4 \\ \hline \phantom{\,}3\,4\,4 \\ \, 2 \, 5 \, 8 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{1 \space{\ }}{\ 8} \space{\,}6\\ \times \phantom{0} 3\space{\,}4 \\ \hline \phantom{\,}3\,4\,4 \\+\, 2 \, 5 \, 8 \, 0\\ \hline 2\, 9 \, 2\, 4\end{array}$

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Example Question #121 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}7\\ \times\phantom{0}3\space{\,}3 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

2221

22110

2211

2201

Correct answer:

2211

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 33 is the multiplier and 67 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 3 and 7

$\begin{array}{r}\overset{2 \space{\ }}{\ 6} \space{\,}7\\ \times \phantom{0} 3\space{\,}3\\ \hline \phantom{\,} \,1\end{array}$

Then, we multiply 3 and 6 and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 6} \space{\,}7\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}2\,0\,1\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}7\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}2\,0\,1 \\ \, 0 \end{array}$

Next, we multiply 3 and 7

$\begin{array}{r}\overset{2 \space{\ }}{\ 6} \space{\,}7\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}2\,0\,1 \\ \, 1 \, 0\end{array}$

Then, we multiply 3 and 6and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 6} \space{\,}7\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}2\,0\,1 \\ \, 2 \, 0 \, 1 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{2 \space{\ }}{\ 6} \space{\,}7\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}2\,0\,1 \\+\, 2 \, 0 \, 1 \, 0\\ \hline 2\, 2 \, 1\, 1\end{array}$

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Example Question #122 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}0\\ \times\phantom{0}7\space{\,}2 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

4320

43200

4330

4310

Correct answer:

4320

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 72 is the multiplier and 60 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 2 and 0

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}0\\ \times \phantom{0} 7\space{\,}2 \\ \hline \phantom{\,} \,0\end{array}$

Then, we multiply 2 and 6

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}0\\ \times \phantom{0} 7\space{\,}2 \\ \hline \phantom{\,}1\,2\,0\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}0\\ \times \phantom{0} 7\space{\,}2 \\ \hline \phantom{\,}1\,2\,0 \\ \, 0 \end{array}$

Next, we multiply 7 and 0

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}0\\ \times \phantom{0} 7\space{\,}2 \\ \hline \phantom{\,}1\,2\,0 \\ \, 0 \, 0\end{array}$

Then, we multiply 7 and 6

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}0\\ \times \phantom{0} 7\space{\,}2 \\ \hline \phantom{\,}1\,2\,0 \\ \, 4\, 2\, 0 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}0\\ \times \phantom{0} 7\space{\,}2 \\ \hline \phantom{\,}1\,2\,0 \\+\, 4\, 2\, 0 \, 0\\ \hline 4\, 3 \, 2\, 0\end{array}$

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Example Question #131 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}1\\ \times\phantom{0}6\space{\,}7 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

4077

40870

4087

4097

Correct answer:

4087

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 67 is the multiplier and 61 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 7 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}1\\ \times \phantom{0} 6\space{\,}7 \\ \hline \phantom{\,} \,7\end{array}$

Then, we multiply 7 and 6

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}1\\ \times \phantom{0} 6\space{\,}7 \\ \hline \phantom{\,}4\,2\,7\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}1\\ \times \phantom{0} 6\space{\,}7 \\ \hline \phantom{\,}4\,2\,7 \\ \, 0 \end{array}$

Next, we multiply 6 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}1\\ \times \phantom{0} 6\space{\,}7 \\ \hline \phantom{\,}4\,2\,7 \\ \, 6 \, 0\end{array}$

Then, we multiply 6 and 6

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}1\\ \times \phantom{0} 6\space{\,}7 \\ \hline \phantom{\,}4\,2\,7 \\ \, 3\, 6\, 6 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}1\\ \times \phantom{0} 6\space{\,}7 \\ \hline \phantom{\,}4\,2\,7 \\+\, 3\, 6\, 6 \, 0\\ \hline 4\, 0 \, 8\, 7\end{array}$

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Example Question #132 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}7\\ \times\phantom{0}4\space{\,}1 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

27470

2737

2747

2757

Correct answer:

2747

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 41 is the multiplier and 67 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 1 and 7

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}7\\ \times \phantom{0} 4\space{\,}1 \\ \hline \phantom{\,} \,7\end{array}$

Then, we multiply 1 and 6

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}7\\ \times \phantom{0} 4\space{\,}1 \\ \hline \phantom{\,} \,6\,7\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}7\\ \times \phantom{0} 4\space{\,}1 \\ \hline \phantom{\,} \,6\,7 \\ \, 0 \end{array}$

Next, we multiply 4 and 7

$\begin{array}{r}\overset{2 \space{\ }}{\ 6} \space{\,}7\\ \times \phantom{0} 4\space{\,}1 \\ \hline \phantom{\,} \,6\,7 \\ \, 8 \, 0\end{array}$

Then, we multiply 4 and 6and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 6} \space{\,}7\\ \times \phantom{0} 4\space{\,}1 \\ \hline \phantom{\,} \,6\,7 \\ \, 2 \, 6 \, 8 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{2 \space{\ }}{\ 6} \space{\,}7\\ \times \phantom{0} 4\space{\,}1 \\ \hline \phantom{\,} \,6\,7 \\+\, 2 \, 6 \, 8 \, 0\\ \hline 2\, 7 \, 4\, 7\end{array}$

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Example Question #133 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times\phantom{0}2\space{\,}3 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

19320

1942

1922

1932

Correct answer:

1932

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 23 is the multiplier and 84 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 3 and 4

$\begin{array}{r}\overset{1 \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 2\space{\,}3\\ \hline \phantom{\,} \,2\end{array}$

Then, we multiply 3 and 8 and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 2\space{\,}3 \\ \hline \phantom{\,}2\,5\,2\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 2\space{\,}3 \\ \hline \phantom{\,}2\,5\,2 \\ \, 0 \end{array}$

Next, we multiply 2 and 4

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 2\space{\,}3 \\ \hline \phantom{\,}2\,5\,2 \\ \, 8 \, 0\end{array}$

Then, we multiply 2 and 8

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 2\space{\,}3 \\ \hline \phantom{\,}2\,5\,2 \\ \, 1\, 6\, 8 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 2\space{\,}3 \\ \hline \phantom{\,}2\,5\,2 \\+\, 1\, 6\, 8 \, 0\\ \hline 1\, 9 \, 3\, 2\end{array}$

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All ISEE Middle Level Quantitative Resources

6 Diagnostic Tests 110 Practice Tests Question of the Day Flashcards Learn by Concept

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ISEE Middle Level Quantitative : Whole Numbers

Study concepts, example questions & explanations for ISEE Middle Level Quantitative

All ISEE Middle Level Quantitative Resources

Example Questions

Example Question #128 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #121 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #122 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #131 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #132 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #133 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

All ISEE Middle Level Quantitative Resources

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