Call Now to Set Up Tutoring:

(888) 888-0446

ISEE Middle Level Quantitative : ISEE Middle Level (grades 7-8) Quantitative Reasoning

Study concepts, example questions & explanations for ISEE Middle Level Quantitative

Create An Account

All ISEE Middle Level Quantitative Resources

6 Diagnostic Tests 110 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1071 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times\phantom{0}6\space{\,}6 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

3366

3376

33660

3356

Correct answer:

3366

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 66 is the multiplier and 51 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 6 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 6\space{\,}6 \\ \hline \phantom{\,} \,6\end{array}$

Then, we multiply 6 and 5

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 6\space{\,}6 \\ \hline \phantom{\,}3\,0\,6\end{array}$

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a 0 as a place holder in the ones position.

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 6\space{\,}6 \\ \hline \phantom{\,}3\,0\,6 \\ \, 0 \end{array}$

Next, we multiply 6 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 6\space{\,}6 \\ \hline \phantom{\,}3\,0\,6 \\ \, 6 \, 0\end{array}$

Then, we multiply 6 and 5

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 6\space{\,}6 \\ \hline \phantom{\,}3\,0\,6 \\ \, 3\, 0\, 6 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 6\space{\,}6 \\ \hline \phantom{\,}3\,0\,6 \\+\, 3\, 0\, 6 \, 0\\ \hline 3\, 3 \, 6\, 6\end{array}$

Report an Error

Example Question #1072 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}8\\ \times\phantom{0}5\space{\,}6 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

10080

1008

1018

998

Correct answer:

1008

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 56 is the multiplier and 18 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 6 and 8

$\begin{array}{r}\overset{4 \space{\ }}{\ 1} \space{\,}8\\ \times \phantom{0} 5\space{\,}6\\ \hline \phantom{\,} \,8\end{array}$

Then, we multiply 6 and 1 and add the 4 that was carried

$\begin{array}{r}\overset{4 \space{\ }}{\ 1} \space{\,}8\\ \times \phantom{0} 5\space{\,}6 \\ \hline \phantom{\,}1\,0\,8\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}8\\ \times \phantom{0} 5\space{\,}6 \\ \hline \phantom{\,}1\,0\,8 \\ \, 0 \end{array}$

Next, we multiply 5 and 8

$\begin{array}{r}\overset{4 \space{\ }}{\ 1} \space{\,}8\\ \times \phantom{0} 5\space{\,}6 \\ \hline \phantom{\,}1\,0\,8 \\ \, 0 \, 0\end{array}$

Then, we multiply 5 and 1and add the 4 that was carried

$\begin{array}{r}\overset{4 \space{\ }}{\ 1} \space{\,}8\\ \times \phantom{0} 5\space{\,}6 \\ \hline \phantom{\,}1\,0\,8 \\ \, 9 \, 0 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{4 \space{\ }}{\ 1} \space{\,}8\\ \times \phantom{0} 5\space{\,}6 \\ \hline \phantom{\,}1\,0\,8 \\+\, 9 \, 0 \, 0\\ \hline 1\, 0 \, 0\, 8\end{array}$

Report an Error

Example Question #1073 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 2} \space{\,}6\\ \times\phantom{0}4\space{\,}7 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

1232

1212

12220

1222

Correct answer:

1222

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 47 is the multiplier and 26 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 7 and 6

$\begin{array}{r}\overset{4 \space{\ }}{\ 2} \space{\,}6\\ \times \phantom{0} 4\space{\,}7\\ \hline \phantom{\,} \,2\end{array}$

Then, we multiply 7 and 2 and add the 4 that was carried

$\begin{array}{r}\overset{4 \space{\ }}{\ 2} \space{\,}6\\ \times \phantom{0} 4\space{\,}7 \\ \hline \phantom{\,}1\,8\,2\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 2} \space{\,}6\\ \times \phantom{0} 4\space{\,}7 \\ \hline \phantom{\,}1\,8\,2 \\ \, 0 \end{array}$

Next, we multiply 4 and 6

$\begin{array}{r}\overset{2 \space{\ }}{\ 2} \space{\,}6\\ \times \phantom{0} 4\space{\,}7 \\ \hline \phantom{\,}1\,8\,2 \\ \, 4 \, 0\end{array}$

Then, we multiply 4 and 2and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 2} \space{\,}6\\ \times \phantom{0} 4\space{\,}7 \\ \hline \phantom{\,}1\,8\,2 \\ \, 1 \, 0 \, 4 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{2 \space{\ }}{\ 2} \space{\,}6\\ \times \phantom{0} 4\space{\,}7 \\ \hline \phantom{\,}1\,8\,2 \\+\, 1 \, 0 \, 4 \, 0\\ \hline 1\, 2 \, 2\, 2\end{array}$

Report an Error

Example Question #81 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times\phantom{0}1\space{\,}5 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

1270

12600

1260

1250

Correct answer:

1260

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 15 is the multiplier and 84 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 5 and 4

$\begin{array}{r}\overset{2 \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 1\space{\,}5\\ \hline \phantom{\,} \,0\end{array}$

Then, we multiply 5 and 8 and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 1\space{\,}5 \\ \hline \phantom{\,}4\,2\,0\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 1\space{\,}5 \\ \hline \phantom{\,}4\,2\,0 \\ \, 0 \end{array}$

Next, we multiply 1 and 4

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 1\space{\,}5 \\ \hline \phantom{\,}4\,2\,0 \\ \, 4 \, 0\end{array}$

Then, we multiply 1 and 8

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 1\space{\,}5 \\ \hline \phantom{\,}4\,2\,0 \\ \, 8 \, 4 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 1\space{\,}5 \\ \hline \phantom{\,}4\,2\,0 \\+\, 8 \, 4 \, 0\\ \hline 1\, 2 \, 6\, 0\end{array}$

Report an Error

Example Question #1075 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}6\\ \times\phantom{0}1\space{\,}1 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

386

3960

396

406

Correct answer:

396

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 11 is the multiplier and 36 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 1 and 6

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}6\\ \times \phantom{0} 1\space{\,}1 \\ \hline \phantom{\,} \,6\end{array}$

Then, we multiply 1 and 3

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}6\\ \times \phantom{0} 1\space{\,}1 \\ \hline \phantom{\,} \,3\,6\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}6\\ \times \phantom{0} 1\space{\,}1 \\ \hline \phantom{\,} \,3\,6 \\ \, 0 \end{array}$

Next, we multiply 1 and 6

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}6\\ \times \phantom{0} 1\space{\,}1 \\ \hline \phantom{\,} \,3\,6 \\ \, 6 \, 0\end{array}$

Then, we multiply 1 and 3

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}6\\ \times \phantom{0} 1\space{\,}1 \\ \hline \phantom{\,} \,3\,6 \\ \, 3 \, 6 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}6\\ \times \phantom{0} 1\space{\,}1 \\ \hline \phantom{\,} \,3\,6 \\+\, 3 \, 6 \, 0\\ \hline 3\, 9 \, 6\end{array}$

Report an Error

Example Question #111 : How To Multiply

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}2\\ \times\phantom{0}4\space{\,}3 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

3516

3526

3536

35260

Correct answer:

3526

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 43 is the multiplier and 82 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 3 and 2

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}2\\ \times \phantom{0} 4\space{\,}3 \\ \hline \phantom{\,} \,6\end{array}$

Then, we multiply 3 and 8

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}2\\ \times \phantom{0} 4\space{\,}3 \\ \hline \phantom{\,}2\,4\,6\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}2\\ \times \phantom{0} 4\space{\,}3 \\ \hline \phantom{\,}2\,4\,6 \\ \, 0 \end{array}$

Next, we multiply 4 and 2

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}2\\ \times \phantom{0} 4\space{\,}3 \\ \hline \phantom{\,}2\,4\,6 \\ \, 8 \, 0\end{array}$

Then, we multiply 4 and 8

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}2\\ \times \phantom{0} 4\space{\,}3 \\ \hline \phantom{\,}2\,4\,6 \\ \, 3\, 2\, 8 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}2\\ \times \phantom{0} 4\space{\,}3 \\ \hline \phantom{\,}2\,4\,6 \\+\, 3\, 2\, 8 \, 0\\ \hline 3\, 5 \, 2\, 6\end{array}$

Report an Error

Example Question #1077 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}3\\ \times\phantom{0}3\space{\,}3 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

2399

24090

2409

2419

Correct answer:

2409

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 33 is the multiplier and 73 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 3 and 3

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,} \,9\end{array}$

Then, we multiply 3 and 7

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}2\,1\,9\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}2\,1\,9 \\ \, 0 \end{array}$

Next, we multiply 3 and 3

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}2\,1\,9 \\ \, 9 \, 0\end{array}$

Then, we multiply 3 and 7

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}2\,1\,9 \\ \, 2\, 1\, 9 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}2\,1\,9 \\+\, 2\, 1\, 9 \, 0\\ \hline 2\, 4 \, 0\, 9\end{array}$

Report an Error

Example Question #1078 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}1\\ \times\phantom{0}6\space{\,}1 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

661

681

6710

671

Correct answer:

671

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 61 is the multiplier and 11 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 1 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}1\\ \times \phantom{0} 6\space{\,}1 \\ \hline \phantom{\,} \,1\end{array}$

Then, we multiply 1 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}1\\ \times \phantom{0} 6\space{\,}1 \\ \hline \phantom{\,} \,1\,1\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}1\\ \times \phantom{0} 6\space{\,}1 \\ \hline \phantom{\,} \,1\,1 \\ \, 0 \end{array}$

Next, we multiply 6 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}1\\ \times \phantom{0} 6\space{\,}1 \\ \hline \phantom{\,} \,1\,1 \\ \, 6 \, 0\end{array}$

Then, we multiply 6 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}1\\ \times \phantom{0} 6\space{\,}1 \\ \hline \phantom{\,} \,1\,1 \\ \, 6 \, 6 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}1\\ \times \phantom{0} 6\space{\,}1 \\ \hline \phantom{\,} \,1\,1 \\+\, 6 \, 6 \, 0\\ \hline 6\, 7 \, 1\end{array}$

Report an Error

Example Question #1079 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}0\\ \times\phantom{0}3\space{\,}6 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

3600

370

350

360

Correct answer:

360

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 36 is the multiplier and 10 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 6 and 0

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}0\\ \times \phantom{0} 3\space{\,}6 \\ \hline \phantom{\,} \,0\end{array}$

Then, we multiply 6 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}0\\ \times \phantom{0} 3\space{\,}6 \\ \hline \phantom{\,} \,6\,0\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}0\\ \times \phantom{0} 3\space{\,}6 \\ \hline \phantom{\,} \,6\,0 \\ \, 0 \end{array}$

Next, we multiply 3 and 0

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}0\\ \times \phantom{0} 3\space{\,}6 \\ \hline \phantom{\,} \,6\,0 \\ \, 0 \, 0\end{array}$

Then, we multiply 3 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}0\\ \times \phantom{0} 3\space{\,}6 \\ \hline \phantom{\,} \,6\,0 \\ \, 3 \, 0 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}0\\ \times \phantom{0} 3\space{\,}6 \\ \hline \phantom{\,} \,6\,0 \\+\, 3 \, 0 \, 0\\ \hline 3\, 6 \, 0\end{array}$

Report an Error

Example Question #1080 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}5\\ \times\phantom{0}8\space{\,}5 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

6385

6375

63750

6365

Correct answer:

6375

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 85 is the multiplier and 75 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 5 and 5

$\begin{array}{r}\overset{2 \space{\ }}{\ 7} \space{\,}5\\ \times \phantom{0} 8\space{\,}5\\ \hline \phantom{\,} \,5\end{array}$

Then, we multiply 5 and 7 and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 7} \space{\,}5\\ \times \phantom{0} 8\space{\,}5 \\ \hline \phantom{\,}3\,7\,5\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}5\\ \times \phantom{0} 8\space{\,}5 \\ \hline \phantom{\,}3\,7\,5 \\ \, 0 \end{array}$

Next, we multiply 8 and 5

$\begin{array}{r}\overset{4 \space{\ }}{\ 7} \space{\,}5\\ \times \phantom{0} 8\space{\,}5 \\ \hline \phantom{\,}3\,7\,5 \\ \, 0 \, 0\end{array}$

Then, we multiply 8 and 7and add the 4 that was carried

$\begin{array}{r}\overset{4 \space{\ }}{\ 7} \space{\,}5\\ \times \phantom{0} 8\space{\,}5 \\ \hline \phantom{\,}3\,7\,5 \\ \, 6 \, 0 \, 0 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{4 \space{\ }}{\ 7} \space{\,}5\\ \times \phantom{0} 8\space{\,}5 \\ \hline \phantom{\,}3\,7\,5 \\+\, 6 \, 0 \, 0 \, 0\\ \hline 6\, 3 \, 7\, 5\end{array}$

Report an Error

View Tutors

Gabby
Certified Tutor

University of Oregon, Bachelor in Arts, Journalism. University of Oregon, Current Grad Student, Communication, General.

View Tutors

Liban
Certified Tutor

Emory University, Bachelor of Science, Mathematics/Economics.

View Tutors

Gregory
Certified Tutor

Pennsylvania State University-Main Campus, Bachelor of Science, Chemical Engineering. Carnegie Mellon University, Doctor of P...

All ISEE Middle Level Quantitative Resources

6 Diagnostic Tests 110 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

SSAT Tutors in Los Angeles, Statistics Tutors in Phoenix, LSAT Tutors in Dallas Fort Worth, Physics Tutors in Miami, Spanish Tutors in Atlanta, Algebra Tutors in Houston, French Tutors in San Diego, Calculus Tutors in Miami, LSAT Tutors in Washington DC, Spanish Tutors in San Francisco-Bay Area

Popular Courses & Classes

ISEE Courses & Classes in Washington DC, LSAT Courses & Classes in Los Angeles, Spanish Courses & Classes in San Francisco-Bay Area, ISEE Courses & Classes in Houston, LSAT Courses & Classes in Philadelphia, ACT Courses & Classes in Boston, Spanish Courses & Classes in Washington DC, GMAT Courses & Classes in Boston, ISEE Courses & Classes in Los Angeles, ACT Courses & Classes in Washington DC

Popular Test Prep

ACT Test Prep in Washington DC, ISEE Test Prep in Chicago, ISEE Test Prep in Denver, SSAT Test Prep in Denver, GRE Test Prep in Denver, ACT Test Prep in New York City, GRE Test Prep in Los Angeles, ISEE Test Prep in San Diego, ISEE Test Prep in Washington DC, SAT Test Prep in Phoenix

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

ISEE Middle Level Quantitative : ISEE Middle Level (grades 7-8) Quantitative Reasoning

Study concepts, example questions & explanations for ISEE Middle Level Quantitative

All ISEE Middle Level Quantitative Resources

Example Questions

Example Question #1071 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Example Question #1072 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Example Question #1073 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Example Question #81 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #1075 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Example Question #111 : How To Multiply

Example Question #1077 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Example Question #1078 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Example Question #1079 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Example Question #1080 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

All ISEE Middle Level Quantitative Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: