To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, \(\displaystyle A=l\times w\), we can solve for the area of both of our rectangles

\(\displaystyle A=7\times 3\)            \(\displaystyle A=6\times 3\)

\(\displaystyle A=21in^2\)           \(\displaystyle A=18in^2\)

To find our final answer, we need to add the areas together. 

\(\displaystyle 21in^2+18in^2=39in^2\)

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, \(\displaystyle A=l\times w\), we can solve for the area of both of our rectangles

\(\displaystyle A=8\times 3\)            \(\displaystyle A=7\times 4\)

\(\displaystyle A=24in^2\)           \(\displaystyle A=28in^2\)

To find our final answer, we need to add the areas together. 

\(\displaystyle 24in^2+28in^2=52in^2\)

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, \(\displaystyle A=l\times w\), we can solve for the area of both of our rectangles

\(\displaystyle A=10\times 9\)            \(\displaystyle A=9\times 4\)

\(\displaystyle A=90in^2\)           \(\displaystyle A=36in^2\)

To find our final answer, we need to add the areas together. 

\(\displaystyle 90in^2+36in^2=126in^2\)

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, \(\displaystyle A=l\times w\), we can solve for the area of both of our rectangles

\(\displaystyle A=7\times 5\)            \(\displaystyle A=5\times 3\)

\(\displaystyle A=35in^2\)           \(\displaystyle A=15in^2\)

To find our final answer, we need to add the areas together. 

\(\displaystyle 35in^2+15in^2=50in^2\)

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, \(\displaystyle A=l\times w\), we can solve for the area of both of our rectangles

\(\displaystyle A=6\times 6\)            \(\displaystyle A=4\times 4\)

\(\displaystyle A=36in^2\)           \(\displaystyle A=16in^2\)

To find our final answer, we need to add the areas together. 

\(\displaystyle 36in^2+16in^2=52in^2\)

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, \(\displaystyle A=l\times w\), we can solve for the area of both of our rectangles

\(\displaystyle A=5\times 10\)            \(\displaystyle A=5\times 3\)

\(\displaystyle A=50in^2\)           \(\displaystyle A=15in^2\)

To find our final answer, we need to add the areas together. 

\(\displaystyle 50in^2+15in^2=65in^2\)

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, \(\displaystyle A=l\times w\), we can solve for the area of both of our rectangles

\(\displaystyle A=4\times 4\)            \(\displaystyle A=12\times 3\)

\(\displaystyle A=16in^2\)           \(\displaystyle A=36in^2\)

To find our final answer, we need to add the areas together. 

\(\displaystyle 16in^2+36in^2=52in^2\)

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, \(\displaystyle A=l\times w\), we can solve for the area of both of our rectangles

\(\displaystyle A=9\times 6\)            \(\displaystyle A=7\times 5\)

\(\displaystyle A=54in^2\)           \(\displaystyle A=35in^2\)

To find our final answer, we need to add the areas together. 

\(\displaystyle 54in^2+35in^2=89in^2\)

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, \(\displaystyle A=l\times w\), we can solve for the area of both of our rectangles

\(\displaystyle A=11\times 3\)            \(\displaystyle A=3\times 3\)

\(\displaystyle A=33in^2\)           \(\displaystyle A=9in^2\)

To find our final answer, we need to add the areas together. 

\(\displaystyle 33in^2+9in^2=42in^2\)

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, \(\displaystyle A=l\times w\), we can solve for the area of both of our rectangles

\(\displaystyle A=7\times 3\)            \(\displaystyle A=5\times 2\)

\(\displaystyle A=21in^2\)           \(\displaystyle A=10in^2\)

To find our final answer, we need to add the areas together. 

\(\displaystyle 21in^2+10in^2=31in^2\)