ISEE Middle Level Math : How to find the solution to an equation
Study concepts, example questions & explanations for ISEE Middle Level Math
All ISEE Middle Level Math Resources
Example Questions
Example Question #471 : Algebra
Solve for 
Divide each side by 24:
Answer:
Example Question #472 : Algebra
First perform the squaring:
Then multiply:
Answer:
Example Question #473 : Algebra
First remove the exponents:
Then take the product:
Answer:
Example Question #474 : Algebra
First look at any terms with exponents:
Then perform the multiplication:
Answer:
Example Question #475 : Algebra
When 10 has an exponent, simply add the appropriate number of zeroes:
Then multiply:
Answer:
Example Question #286 : How To Find The Solution To An Equation
What is the value of y in the equation
The first step in solving this problem is to add together the numbers in parentheses:
Next, add 40 to both sides of the equation.
Finally, subtract y from each side to get the answer.
Example Question #286 : How To Find The Solution To An Equation
What is the value of 
The first step is to combine the numbers in the equation that can be added together.
Next subtract 
Now divide each side by 3
Example Question #476 : Algebra
Solve:
To solve, divide each side by 11:
Answer:
Example Question #491 : Algebraic Concepts
Which of the following phrases can be written as the algebraic expression 
The correct answer is not given among the other responses
Three times the difference of fifty and a number
Three times a number subtracted from fifty
The cube of the difference of fifty and a number
The cube of a number subtracted from fifty
The cube of a number subtracted from fifty
Example Question #281 : Equations
Billy is at the store purchasing flowers for his mother, his grandmother, and his friend. He finds roses on sale by the half dozen (6), tulips selling by the dozen (12), and daisies selling groups of 18.
Billy wants to have the same number of flowers in each bouquet, so that he is able to give everyone the same number of each flower. How many bundles of roses, tulips, and daisies will he have to buy so he has the same amount of each? (Please answer by roses, tulips, then daisies.)
This is a least common multiple problem because we want to have the same number of each flower; meaning if I have 10 roses in each bouquet I should have 10 tulips and 10 daisies as well. In order to solve this problem we should break down the story problem. Let's look at the numbers we are having to work with: 6, 12, 18.
To do least common multiple we must look at the prime factors of each number and we can list them out. A factor is simply a number multiplied by a number to give us a product. A prime number is a number that contains only two factors, one of them being 1 and the other its own number.
So lets list the prime factors of 6, 12, and 18
Now we have the prime factors listed out for each of our numbers. Next is a fun trick. We must choose which number contains the most of each prime factor. In this case which number contains the most 2's? (12; because 12 has two 2 prime factors). Which number contains the most 3's? (18; because 18 has two 3 prime factors).
Our next step is to multiply the most of our prime factors so in this case:
36 is our least common multiple. So now what do you think we can do with this number? Well the 36 means that is the lowest number of flowers we need of each type in order to have an equal amount of each for the boquets.
Knowing this, if we need 36 roses, and we are able to buy 6 roses per bundle. We need 6 bundles of roses, because 36 divided by 6 is 6. If we get 12 tulips by the bundle, we take 36 divided by 12 to give us 3 bundles of tulips needed. Lastly we can buy 18 daisies per bundle, 36 divided by 18 gives us 2 bundles needed giving us our answers 6, 3, 2 (bundles of roses, tulips, and daisies).
All ISEE Middle Level Math Resources
