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Intermediate Geometry : Triangles

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Example Questions

Example Question #131 : Acute / Obtuse Triangles

Given: $\bigtriangleup ABC$ and $\bigtriangleup DEF$ .

$m \angle A = 56 ^{\circ }$

$m \angle B = 72 ^{\circ }$

$m \angle E = 72^{\circ }$

$m \angle F = 52^{\circ }$

True or false: From the above four statements, it follows that $\bigtriangleup ABC \sim \bigtriangleup DEF$ .

Possible Answers:

True

False

Correct answer:

True

Explanation:

As we are establishing whether or not $\bigtriangleup ABC \sim \bigtriangleup DEF$ , then , , and correspond respectively to , , and .

The sum of the measures of the interior angles of a triangle is $180^{\circ }$ . Therefore,

$m \angle A + m \angle B + m \angle C = 180^{\circ }$

Set $m \angle A = 56 ^{\circ }$ and $m \angle B = 72 ^{\circ }$ , and solve for $m \angle C$ :

$56 ^{\circ } + 72 ^{\circ } + m \angle C = 180^{\circ }$

$128 ^{\circ } + m \angle C = 180^{\circ }$

$128 ^{\circ } + m \angle C - 128 ^{\circ } = 180^{\circ } - 128 ^{\circ }$

$m \angle C = 52 ^{\circ }$

By the Angle-Angle Similarity Postulate (AA), two triangles are similar if two angles of the first triangle are congruent to those of their counterparts in the second. $m \angle B = 72 ^{\circ }$ and $m \angle E = 72^{\circ }$ , so $\angle B \cong \angle E$ ; $m \angle C = 52 ^{\circ }$ and $m \angle F = 52^{\circ }$ , so $\angle C \cong \angle F$ . The conditions of AA are met, so it follows that $\bigtriangleup ABC \sim \bigtriangleup DEF$ . The correct response is "true".

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Example Question #132 : Acute / Obtuse Triangles

Given: $\bigtriangleup ABC$ and $\bigtriangleup DEF$ .

$\angle A \cong \angle C$

$\angle B \cong \angle E$

$\angle D \cong \angle F$

True or false: From the above three statements, it follows that $\bigtriangleup ABC \sim \bigtriangleup DEF$ .

Possible Answers:

True

False

Correct answer:

True

Explanation:

As we are establishing whether or not $\bigtriangleup ABC \sim \bigtriangleup DEF$ , then , , and correspond respectively to , , and .

Let $x = m \angle B = m \angle E$ .

Let $y = m \angle A = m \angle C$

The measures of the interior angles of a triangle total $180^{\circ }$ . Therefore,

$m \angle A + m \angle B + m \angle C = 180^{\circ }$

Substituting:

$y + x + y= 180^{\circ }$

$2 y + x = 180^{\circ }$

$2 y + x - x = 180^{\circ }- x$

$2 y = 180^{\circ }- x$

$\frac{2y}{2} = \frac{180^{\circ }- x}{2}$

$y = \frac{180^{\circ }- x}{2}$

$m \angle A = \frac{180^{\circ }- x}{2}$

By the same reasoning,

$m \angle D = \frac{180^{\circ }- x}{2}$

Therefore, $\angle A \cong \angle D$ .

By the Angle-Angle Similarity Postulate (AA), two triangles are similar if two angles of the first triangle are congruent to those of their counterparts in the second. $\angle A \cong \angle D$ and $\angle B \cong \angle E$ , so the conditions of AA are met; it follows that $\bigtriangleup ABC \sim \bigtriangleup DEF$ .

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Example Question #16 : How To Find If Two Acute / Obtuse Triangles Are Similar

Given: $\bigtriangleup ABC$ , with Point on $\overline{AB}$ and Point on $\overline{AC}$ .

AM = 10

MB = 15

AN= 8

NC = 16

True or false: From the given information, it follows that $\bigtriangleup ABC \sim \bigtriangleup AMN$ .

Possible Answers:

False

True

Correct answer:

False

Explanation:

As we are establishing whether or not $\bigtriangleup ABC \sim \bigtriangleup AMN$ , then , , and correspond respectively to , , and .

If two triangles are similar, then it must hold that corresponding sides are in proportion. Specifically, if $\bigtriangleup ABC \sim \bigtriangleup AMN$ , it must hold that

$\frac{AB}{AM} = \frac{AC}{AN}$

By the Segment Addition Postulate,

AB = AM + MB = 10+15 = 25

and

AC = AN + NC = 8 + 16 = 24

Set AB = 25 , AC = 24 , AM = 10 , AN = 8 in the above proportion statement, which becomes

$\frac{25}{10} = \frac{24}{8}$

Reduce both ratios to lowest terms:

$\frac{5}{2} = \frac{3}{1}$

The corresponding sides are not proportional, so the statement $\bigtriangleup ABC \sim \bigtriangleup AMN$ is false.

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Example Question #133 : Acute / Obtuse Triangles

Given: $\bigtriangleup ABC$ , with Point on $\overline{AB}$ and Point on $\overline{AC}$ .

AM = 6

MB = 12

AN= 9

NC = 18

True or false: From the given information, it follows that $\bigtriangleup ABC \sim \bigtriangleup AMN$ .

Possible Answers:

True

False

Correct answer:

True

Explanation:

As we are establishing whether or not $\bigtriangleup ABC \sim \bigtriangleup AMN$ , then , , and correspond respectively to , , and .

By the Side-Angle-Side Similarity Theorem (SASS), two triangles are similar if two pairs of corresponding sides are in proportion and their included angles are congruent.

Examine two pairs of corresponding sides: $\overline{AB}$ and $\overline{AM}$ , and $\overline{AC}$ and $\overline{AN}$ . In both cases, their included angle is $\angle A$ ; by the Reflexive Property of Congruence, $\angle A \cong \angle A$ .

It remains to be demonstrated that

$\frac{AB}{AM} = \frac{AC}{AN}$

By the Segment Addition Postulate,

AB = AM + MB = 6+12 = 18

and

AC = AN + NC = 9+18 = 27

Set AB = 18 , AC = 27 , AM = 6 , AN= 9 in the above proportion statement, which becomes

$\frac{18}{6} = \frac{27}{9}$

Reduce both ratios to lowest terms:

$\frac{3}{1} = \frac{3}{1}$

The corresponding sides are proportional.

The conditions of SASS have been proved, so the statement $\bigtriangleup ABC \sim \bigtriangleup AMN$ is true.

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Example Question #134 : Acute / Obtuse Triangles

Given: $\bigtriangleup ABC$ and $\bigtriangleup DEF$ such that

$\angle A \cong \angle D$

$\angle B \cong \angle E$

Which statement(s) must be true?

(a) $\bigtriangleup ABC \sim \bigtriangleup DEF$

(b) $\bigtriangleup ABC \cong \bigtriangleup DEF$

Possible Answers:

(b) but not (a)

(a) but not (b)

(a) and (b)

Neither (a) nor (b)

Correct answer:

(a) but not (b)

Explanation:

The two given angle congruences set up the conditions of the Angle-Angle Similarity Postulate - if two angles of one triangle are congruent to the two corresponding angles of another triangle, the two triangles are similar. It follows that

$\bigtriangleup ABC \sim \bigtriangleup DEF$ .

However, congruence cannot be proved, since at least one side congruence is needed to prove this. This is not given in the problem.

Therefore, statement (a) must hold, but not necessarily statement (b).

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Example Question #1 : How To Find The Height Of An Acute / Obtuse Triangle

Inter_geo_tri_series_

Find the height of the triangle shown above.

Possible Answers:

$2\sqrt{64}$

Correct answer:

Explanation:

Use the Pythagorean Theorem to find the height of this triangle: a^2+b^2=c^2 , where the height of the triangle.

a^2+10^2=164

a^2+100=164

a^2=64

$a=\sqrt{64}=8$

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Example Question #1 : How To Find The Height Of An Acute / Obtuse Triangle

Tri_vt

Find the height of the obtuse triangle shown above.

Possible Answers:

Correct answer:

Explanation:

To solve this solution, first work backwards using the formula:

$Area=\frac{b\cdot h}{2}$

Plugging in the given values we are able to solve for the height.
$27=\frac{9h}{2}$

54=

$h=\frac{54}{9}=6$

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Example Question #1 : How To Find The Height Of An Acute / Obtuse Triangle

Tri_vt

Find the height of the acute triangle shown above.

Possible Answers:

Correct answer:

Explanation:

To solve this solution, work backwards using the formula:

$Area=\frac{b\cdot h}{2}$

Plugging in the given values we are able to solve for the height.
$160=\frac{16h}{2}$

16h=320

$h=320\div16=20$

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Example Question #3 : How To Find The Height Of An Acute / Obtuse Triangle

A triangle has a base of and an area of square units. Find the height of the triangle.

Possible Answers:

Correct answer:

Explanation:

To solve this solution, work backwards using the formula:

$Area=\frac{b\cdot h}{2}$

Plugging in the given values we are able to solve for the height.
$9=\frac{3h}{2}$

3h=18

$h=18\div3=6$

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Example Question #4 : How To Find The Height Of An Acute / Obtuse Triangle

An obtuse triangle has a base of and an area of 225 square units. Find the height of the triangle.

Possible Answers:

Correct answer:

Explanation:

To solve this solution, work backwards using the formula:

$Area=\frac{b\cdot h}{2}$

Plugging in the given values we are able to solve for the height.

$225=\frac{30h}{2}$

30h=450

$h=\frac{450}{30}=15$

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Intermediate Geometry : Triangles

Study concepts, example questions & explanations for Intermediate Geometry

All Intermediate Geometry Resources

Example Questions

Example Question #131 : Acute / Obtuse Triangles

Example Question #132 : Acute / Obtuse Triangles

Example Question #16 : How To Find If Two Acute / Obtuse Triangles Are Similar

Example Question #133 : Acute / Obtuse Triangles

Example Question #134 : Acute / Obtuse Triangles

Example Question #1 : How To Find The Height Of An Acute / Obtuse Triangle

Example Question #1 : How To Find The Height Of An Acute / Obtuse Triangle

Example Question #1 : How To Find The Height Of An Acute / Obtuse Triangle

Example Question #3 : How To Find The Height Of An Acute / Obtuse Triangle

Example Question #4 : How To Find The Height Of An Acute / Obtuse Triangle

All Intermediate Geometry Resources

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