Call Now to Set Up Tutoring:

(888) 888-0446

High School Physics : Understanding Motion in One Dimension

Study concepts, example questions & explanations for High School Physics

Create An Account

All High School Physics Resources

6 Diagnostic Tests 233 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

← Previous 1 2 3 4 Next →

Example Question #21 : Understanding Motion In One Dimension

A ball rolls at $0.77\frac{m}{s}$ . Assuming no outside forces, how long will it take to roll 9.23m ?

Possible Answers:

11.99s

5.82s

0.141s

7.12s

0.083s

Correct answer:

11.99s

Explanation:

The relationship between distance, velocity, and time is given by the equation for velocity:

$v=\frac{\Delta x}{\Delta t}$

We can rearrange this formula for solve for the time.

$\Delta t =\frac{\Delta x}{v}$

Using the given values for the velocity and distance traveled, we can solve for the time.

$\Delta t =\frac{9.23m}{0.77\frac{m}{s}}$

$\Delta t=11.99s$

Report an Error

Example Question #21 : Linear Motion

A ball begins to roll with a velocity of $0.02\frac{m}{s}$ . If it has an acceleration of $0.5\frac{m}{s^2}$ and rolls for , what is the final velocity?

Possible Answers:

$0.42\frac{m}{s}$

$8.04\frac{m}{s}$

$2.01\frac{m}{s}$

$0.84\frac{m}{s}$

$4.02\frac{m}{s}$

Correct answer:

$4.02\frac{m}{s}$

Explanation:

For this question, we will need to use the acceleration formula:

$a=\frac{\Delta v}{\Delta t}=\frac{v_2-v_1}{\Delta t}$

We are given the initial velocity, acceleration, and time. Using these values in the equation, we can solve for the final velocity.

$0.5\frac{m}{s^2}=\frac{v_2-0.02\frac{m}{s}}{8s}$

$4\frac{m}{s}=v_2-0.02\frac{m}{s}$

$4.02\frac{m}{s}=v_2$

Report an Error

Example Question #23 : Understanding Motion In One Dimension

A stone is thrown downward with a speed of $8\frac{m}{s}$ from a height of 15m. What is the speed of the stone just before it collides with the ground?

$g=10\frac{m}{s^2}$

Possible Answers:

$40\frac{m}{s}$

$19.1\frac{m}{s}$

$10\frac{m}{s}$

$25.2\frac{m}{s}$

$32.3\frac{m}{s}$

Correct answer:

$19.1\frac{m}{s}$

Explanation:

To solve this problem we use a kinematic equation that relates the square of the final velocity to the sum of the initial velocity squared and the change of position.

$V^{2}=V_{0}^2+2a(y-y_{0})$

All values needed to find the final velocity are given, plug them in and solve.

$V^{2}=8^2+2(10)(15)$

$V^{2}=8^2+2(10)(15)=364$

$\sqrt{V^{2}}=\sqrt{364}$

$V=19.1\frac{m}{s}$

Report an Error

Example Question #21 : Understanding Motion In One Dimension

An object is dropped from the roof of a building, how fast is it traveling after 9s? How far would it have fallen? Assume the building is tall enough for the object to have not hit the ground during this time and neglect air resistance.

$g=10\frac{m}{s^2}$

Possible Answers:

$90\frac{m}{s};500m$

$85\frac{m}{s}; 405m$

$45\frac{m}{s};405m$

$90\frac{m}{s}; 405m$

$45\frac{m}{s}; 500m$

Correct answer:

$90\frac{m}{s}; 405m$

Explanation:

The only force accelerating the object is gravity since it was dropped, not thrown. Thus, to find out the speed of the object after some time, simply multiply the time the object has fallen by the acceleration of gravity. We will use $g=10\frac{m}{s^2}$ . Then use the average velocity to calculate the distance the phone fell.

Final velocity after 9s:

$V_f=g*t=10\frac{m}{s^2}*9={90\frac{m}{s}}$

Distance the phone has fallen during the 9s of free fall:

$V_{avg}=\frac{ V_{0} +V_{f}}{2}=\frac{0+90}{2}=45\frac{m}{s}$

$V_{avg}=\frac{d}{t}\rightarrow d= V_{avg}*t=45\frac{m}{s}*9s=405m$

Report an Error

Example Question #25 : Understanding Motion In One Dimension

If Bob threw an orange straight up with an initial velocity of $22\frac{m}{s}$ , what height would the orange reach? Disregard the height it Bob's your hand.

$g=10\frac{m}{s^2}$

Possible Answers:

None of these

$\Delta y=30m$

$\Delta y=32.3m$

$\Delta y=24.2m$

$\Delta y=28.6m$

Correct answer:

$\Delta y=24.2m$

Explanation:

Use a kinematic equation. Select the correct one by variables we have or do not have. We were given initial velocity, we know the final velocity will be zero because the orange has to hit the ground, and we know the acceleration of gravity. These parameters fit closest with the equation:

$V_{f}^2=V_{0}^2+2a\Delta y$

Plug in the variables we know or were given:

$0=(22\frac{m}{s})^2+2(-10\frac{m}{s^2})\Delta y$

Solve for vertical displacement:

$-484\frac{m^2}{s^2}=+2(-10\frac{m}{s^2})\Delta y$

$-484\frac{m^2}{s^2}=-20\frac{m}{s^2}\Delta y$

$\frac{-484\frac{m^2}{s^2}}{-20\frac{m}{s^2}}=\Delta y$

$\Delta y=24.2m$

Report an Error

Example Question #21 : Linear Motion

A remote control car accelerates from rest across a parking lot at $1.5\frac{m}{s^2}$ and does so for 12s. What distance did it travel during this time?

Possible Answers:

$\Delta x=108m$

$\Delta x=114m$

$\Delta x=120m$

$\Delta x=81m$

$\Delta x=78m$

Correct answer:

$\Delta x=108m$

Explanation:

Use a kinematic equation. Based on the variables we were given, the best equation to use is:

$\Delta x=V_{0}t+.5at^2$

$a=1.5\frac{m}{s^2}$ and t=12s . We know initial velocity is 0 because it started from rest. Plug in known values:

$\Delta x={\color{Red} V_{0}t}+.5(1.5\frac{m}{s^2})12^2$

The red term becomes 0.

Solve for horizontal displacement:

$\Delta x=.75\frac{m}{s^2}*12s^2$

$\Delta x=.75\frac{m}{s^2}*144s^2$

$\Delta x=108m$

Report an Error

Example Question #21 : Linear Motion

You are trying to determine the height of water in a well by dropping a rock into it. If you hear it hit the water after 6s, what is the distance to the surface of the water? Ignore friction.

$g=10\frac{m}{s^2}$

Possible Answers:

$\Delta x=190m$

$\Delta x=160m$

None of these

$\Delta x=173m$

$\Delta x=165m$

Correct answer:

None of these

Explanation:

Based on the variables given select the appropriate kinematic equation. We only know gravity and time, but we need to solve for distance.

$\Delta x=V_{0}t+.5at^2$

$\Delta x={\color{Red} V_{0}t}+.5(10\frac{m}{s^2})6^2$

The red term becomes 0 because the rock was dropped. Its initial velocity is 0.

$\Delta x=(5\frac{m}{s^2})36s^2=180m$

Report an Error

Example Question #21 : Understanding Motion In One Dimension

A person base jumps off a tall mountain peak and freefalls for 3.5s before deploying his parachute. What was the person's final speed before deploying the parachute? Ignore air resistance.

$g=10\frac{m}{s^2}$

Possible Answers:

$V=-35\frac{m}{s}$

None of these

$V=25\frac{m}{s}$

$V=35\frac{m}{s}$

$V=-25\frac{m}{s}$

Correct answer:

$V=-35\frac{m}{s}$

Explanation:

A person falling without air resistance only has the force of gravity acting on them. Thus, the acceleration of gravity multiplied by time yields the final speed of $V=-35\frac{m}{s}$ . The negative sign just indicates that the person is falling downward.

Report an Error

Example Question #21 : Motion And Mechanics

Usain Bolt accelerates from rest to $13.4\frac{m}{s}$ over a distance of 100m. What is his acceleration? Assume the acceleration is constant.

Possible Answers:

$a=.898\frac{m}{s^2}$

$a=.869\frac{m}{s^2}$

$a=9.8\frac{m}{s^2}$

$a=.847\frac{m}{s^2}$

$a=.879\frac{m}{s^2}$

Correct answer:

$a=.898\frac{m}{s^2}$

Explanation:

We are given final velocity and we know initial velocity is 0. We can use the following kinematics formula to relate final speed, initial speed, acceleration, and displacement:

$V^2={\color{Red} V_{0}^2}+2a\Delta x$

The red term is zero since Usain starts from rest. Plug in the remaining values and solve for acceleration.

$(13.4\frac{m}{s})^2=2a(100m)$

$(13.4\frac{m}{s})^2=200m(a)$

$179.56\frac{m^2}{s^2}=200m(a)$

$a=.898\frac{m}{s^2}$

Report an Error

Example Question #21 : Understanding Motion In One Dimension

A drone needs to reach $50\frac{m}{s}$ to take off and it takes 600m to reach this speed. What is its acceleration?

Possible Answers:

$a=3.1\frac{m}{s^2}$

$a=1.2\frac{m}{s^2}$

$a=2.8\frac{m}{s^2}$

$a=2.1\frac{m}{s^2}$

$a=1.3\frac{m}{s^2}$

Correct answer:

$a=2.1\frac{m}{s^2}$

Explanation:

We were given final velocity and displacement and we know initial velocity is 0. Choose the following kinematics equation:

$V^2={\color{Red} V_{0}^2}+2a\Delta x$

Initial velocity is zero and thus disappears from the equation. Plug in known values and solve for acceleration.

$(50\frac{m}{s})^2=2a(600m)$

$2500\frac{m^2}{s^2}=2a(600m)$

$2500\frac{m^2}{s^2}=a(1200m)$

$\frac{(2500\frac{m^2}{s^2}}{(1200m)}=a$

$a=2.1\frac{m}{s^2}$

Report an Error

← Previous 1 2 3 4 Next →

View Tutors

Kurosh
Certified Tutor

University of tehran, Bachelor of Engineering, Electrical Engineering.

View Tutors

Susan
Certified Tutor

Carson-Newman College, Bachelor in Arts, Chemistry. University of Maryland-College Park, Master of Science, Chemistry.

View Tutors

Haani
Certified Tutor

University of North Carolina at Chapel Hill, Bachelor in Arts, Economics. North Carolina State University at Raleigh, Master ...

All High School Physics Resources

6 Diagnostic Tests 233 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Chemistry Tutors in Atlanta, Spanish Tutors in San Diego, Algebra Tutors in San Francisco-Bay Area, Math Tutors in Denver, Calculus Tutors in Washington DC, SSAT Tutors in Chicago, Math Tutors in Dallas Fort Worth, Algebra Tutors in Philadelphia, Spanish Tutors in Atlanta, English Tutors in Dallas Fort Worth

Popular Courses & Classes

MCAT Courses & Classes in Dallas Fort Worth, GRE Courses & Classes in New York City, SSAT Courses & Classes in Denver, SSAT Courses & Classes in Miami, ACT Courses & Classes in New York City, SAT Courses & Classes in Denver, LSAT Courses & Classes in Atlanta, SAT Courses & Classes in Phoenix, ISEE Courses & Classes in New York City, ISEE Courses & Classes in Washington DC

Popular Test Prep

LSAT Test Prep in Dallas Fort Worth, SSAT Test Prep in Dallas Fort Worth, SAT Test Prep in Seattle, GMAT Test Prep in San Francisco-Bay Area, GRE Test Prep in Houston, SSAT Test Prep in San Diego, ISEE Test Prep in Seattle, LSAT Test Prep in Atlanta, LSAT Test Prep in Chicago, MCAT Test Prep in Philadelphia

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

High School Physics : Understanding Motion in One Dimension

Study concepts, example questions & explanations for High School Physics

All High School Physics Resources

Example Questions

Example Question #21 : Understanding Motion In One Dimension

Example Question #21 : Linear Motion

Example Question #23 : Understanding Motion In One Dimension

Example Question #21 : Understanding Motion In One Dimension

Example Question #25 : Understanding Motion In One Dimension

Example Question #21 : Linear Motion

Example Question #21 : Linear Motion

Example Question #21 : Understanding Motion In One Dimension

Example Question #21 : Motion And Mechanics

Example Question #21 : Understanding Motion In One Dimension

All High School Physics Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: