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High School Math : Sequences and Series

Study concepts, example questions & explanations for High School Math

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Example Questions

Example Question #1 : Finding Partial Sums In A Series

Find the sum of all even integers from to .

Possible Answers:

930

900

870

990

950

Correct answer:

930

Explanation:

The formula for the sum of an arithmetic series is

$S = \frac{n}{2}(t_{1}+t_{n})$ ,

where is the number of terms in the series, $t_{1}$ is the first term, and $t_{n}$ is the last term.

$S=\frac{30}{2}(2+60)=15(62)=930$

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Example Question #2063 : High School Math

Find the sum of the even integers from 250 to 350 .

Possible Answers:

16,300

16,000

15,500

15,000

15,300

Correct answer:

15,300

Explanation:

The sum of even integers represents an arithmetic series.

The formula for the partial sum of an arithmetic series is

$S = \frac{n}{2}(2(a_1)+(n-1)d)$ ,

where a_1 is the first value in the series, is the number of terms, and is the difference between sequential terms.

Plugging in our values, we get:

$S = \frac{51}{2}(2(250)+(51-1)2)$

S = 25.5(500+100)

S=15,300

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Example Question #32 : Sequences And Series

Find the value for $\sum_{i=0}^{\infty} (\frac{1}{2})^i$

Possible Answers:

1.5

1.25

Correct answer:

Explanation:

To best understand, let's write out the series. So

$\sum_{i=0}^{\infty} (\frac{1}{2})^i = 1+1/2+(1/2)^2 + (1/2)^3+...+(1/2)^\infty$

We can see this is an infinite geometric series with each successive term being multiplied by $\frac{1}{2}$ .

A definition you may wish to remember is

$1+r+r^2+r^3+... +r^\infty= 1/(1-r)$ where stands for the common ratio between the numbers, which in this case is $\frac{1}{2}$ or . So we get

1/(1-r) = 1/(1-.5) = 1/.5 = 2

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Example Question #2 : Finding Sums Of Infinite Series

Evaluate:

$1 + \frac{1}{7} + \frac{1}{49} + \frac{1}{343} +...$

Possible Answers:

The series does not converge.

$\frac{4}{3}$

$\frac{7}{6}$

$\frac{9}{8}$

$\frac{6}{5}$

Correct answer:

$\frac{7}{6}$

Explanation:

This is a geometric series whose first term is $a_{0} = 1$ and whose common ratio is $r = \frac{1}{7}$ . The sum of this series is:

$\frac{a_{0}}{1-r} = \frac{1}{1- \frac{1}{7} } = \frac{1}{\frac{7}{7}- \frac{1}{7}}= \frac{1}{\frac{6}{7}} =\frac{7}{6}$

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Example Question #2 : Sums Of Infinite Series

Evaluate:

$1 - \frac{1}{6} + \frac{1}{36} - \frac{1}{216} +...$

Possible Answers:

The series does not converge.

$\frac{7}{8}$

$\frac{4}{5}$

$\frac{2}{3}$

$\frac{6}{7}$

Correct answer:

$\frac{6}{7}$

Explanation:

This is a geometric series whose first term is $a_{0} = 1$ and whose common ratio is $r = - \frac{1}{6}$ . The sum of this series is:

$\frac{a_{0}}{1-r} = \frac{1}{1- \left (- \frac{1}{6} \right )} = \frac{1}{\frac{6}{6}+ \frac{1}{6}}= \frac{1}{\frac{7}{6}} =\frac{6}{7}$

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High School Math : Sequences and Series

Study concepts, example questions & explanations for High School Math

All High School Math Resources

Example Questions

Example Question #1 : Finding Partial Sums In A Series

Example Question #2063 : High School Math

Example Question #32 : Sequences And Series

Example Question #2 : Finding Sums Of Infinite Series

Example Question #2 : Sums Of Infinite Series

All High School Math Resources

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