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High School Math : Mathematical Relationships and Basic Graphs

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Example Questions

Example Question #1 : Logarithms

$\log_7118=?$

Possible Answers:

0.06

2.45

16.86

0.56

1.92

Correct answer:

2.45

Explanation:

Most of us don't know what the exponent would be if 7^x=118 and unfortunately there is no $\log_7$ on a graphing calculator -- only $\log$ (which stands for $\log_{10}$ ).

Fortunately we can use the base change rule: $\log_ba=\frac{\log_{10}a}{\log_{10}b}$

Plug in our given values.

$\log_7118=\frac{\log_{10}118}{\log_{10}7}$

$\log_7118=\frac{2.07}{0.845}$

$\log_7118=2.45$

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Example Question #1 : Logarithms

Based on the definition of logarithms, what is ${\log_{10}1000}$ ?

Possible Answers:

100

Correct answer:

Explanation:

For any equation $\log_{10}(y) = x$ , $10^{x } = y$ . Thus, we are trying to determine what power of 10 is 1000. 1000 = 10^3 , so our answer is 3.

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Example Question #2 : Logarithms

What is the value of that satisfies the equation $\log_x128=7$ ?

Possible Answers:

$\frac{1}{2}$

Correct answer:

Explanation:

$\log_xa=b$ is equivalent to x^b=a . In this case, you know the value of (the argument of a logarithmic equation) and b (the answer to the logarithmic equation). You must find a solution for the base.

$x^{7}=128$

$\sqrt[7]{x}=\sqrt[7]{128}$

x=2

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Example Question #1 : Simplifying Logarithms

Simplify $log_{5}75 - log_{5}3$ .

Possible Answers:

0.75

1.50

Correct answer:

Explanation:

Using properties of logs we get:

$log_{5}75 - log_{5}3 = log_{5}\frac{75}{3}= log_{5}25$

$log_{5}25= log_{5}5^{2}= 2log_{5}5= 2\cdot 1=2$

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Example Question #1 : Simplifying Logarithms

Simplify the following expression:

log(4) + log(12)

Possible Answers:

log(16)

log(48)

log(8)

log(3)

Correct answer:

log(48)

Explanation:

Recall the log rule:

log(a) + log(b) = log(ab)

In this particular case, a = 4 and b = 12 . Thus, our answer is $log(4\cdot 12) = log(48)$ .

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Example Question #1 : Simplifying Logarithms

Use the properties of logarithms to solve the following equation:

$log_{6}(n-3)+log_{6}(n+2)=log_{3}(3)$

Possible Answers:

n=-3

n=4

n=3

n=-4

No real solutions

Correct answer:

n=4

Explanation:

Since the bases of the logs are the same and the logarithms are added, the arguments can be multiplied together. We then simplify the right side of the equation:

$log_{6}(n-3)+log_{6}(n+2)=log_{3}(3)$

$log_{6}(n-3)(n+2)=1$

The logarithm can be converted to exponential form:

$(n-3)(n+2)=6^{1}$

n^2-n-6=6

n^2-n-12=0

Factor the equation:

(n-4)(n+3)=0

n=4

Although there are two solutions to the equation, logarithms cannot be negative. Therefore, the only real solution is .

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Example Question #1 : Simplifying Logarithms

Which of the following represents a simplified form of log(5x) ?

Possible Answers:

log(5)^x

5 * log(x)

log(5) + log(x)

log(5) * log(x)

$\frac{log(5) }{ log(x) }$

Correct answer:

log(5) + log(x)

Explanation:

The rule for the addition of logarithms is as follows:

log(ab) = log(a)+log(b) .

As an application of this, log(5x) = log(5)+log(x) .

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Example Question #1 : Logarithms

Simplify the expression using logarithmic identities.

log_47-log_45

Possible Answers:

log_4(35)

$log_4(\frac{7}{5})$

$log_4(\frac{5}{7})$

log_4(2)

The expression cannot be simplified

Correct answer:

$log_4(\frac{7}{5})$

Explanation:

The logarithm of a fraction is equal to the logarithm of the numerator minus the logarithm of the denominator.

$log_A(\frac{B}{C})=log_AB-log_AC$

If we encounter two logarithms with the same base, we can likely combine them. In this case, we can use the reverse of the above identity.

$log_AB-log_AC=log_A(\frac{B}{C})$

$A=4,\ B=7,\ C=5$

$log_47-log_45=log_4(\frac{7}{5})$

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Example Question #2 : Logarithms

Evaluate by hand $\log_2(4^{\log_2(4^{5})})$

Possible Answers:

Cannot be found by hand

Correct answer:

Explanation:

Using the logarithm rules, exponents within logarithms can be removed and simply multiplied by the remaining logarithm. This expression can be simplified as $5\log_2(4)\log_2(4)$

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Example Question #1 : Simplifying Logarithms

Solve for

log 2^x = 6

Possible Answers:

19.93

-8.6562

1.5897

Correct answer:

19.93

Explanation:

log 2^x = 6

Use the power reducing theorem:

$\log a^x = b \rightarrow x\log a = b$

a=2 and b=6

$x\log 2 = 6$

$x= \frac{6}{\log 2}$

x=19.93

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High School Math : Mathematical Relationships and Basic Graphs

Study concepts, example questions & explanations for High School Math

All High School Math Resources

Example Questions

Example Question #1 : Logarithms

Example Question #1 : Logarithms

Example Question #2 : Logarithms

Example Question #1 : Simplifying Logarithms

Example Question #1 : Simplifying Logarithms

Example Question #1 : Simplifying Logarithms

Example Question #1 : Simplifying Logarithms

Example Question #1 : Logarithms

Example Question #2 : Logarithms

Example Question #1 : Simplifying Logarithms

All High School Math Resources

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