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High School Chemistry : High School Chemistry

Study concepts, example questions & explanations for High School Chemistry

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6 Diagnostic Tests 143 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

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Example Question #1 : Precision, Accuracy, And Error

A student measures that a piece of string is 2.6 cm, but the actual length of the string is 2.9 cm. What is the student's percent error?

Possible Answers:

$19.7\%$

$38.5\%$

$20.6\%$

$10.3\%$

Correct answer:

$10.3\%$

Explanation:

Use the following formula to find the percent error:

$\frac{|\text{accepted value-experimental value}|}{\text{accepted value}}\cdot100\%$

For this experiment, our accepted value is the same as the theoretical value.

$\text{Percent error}=\frac{|2.9-2.6|}{2.9}\cdot100\%=10.3\%$

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Example Question #1 : Calculating Error

A standard mass of 100.0 grams was placed on a balance. The balance indicated that the mass was 101.6 grams. What is the percent error for the balance?

Possible Answers:

$1.6\%$

$4.7\%$

$2.9\%$

$3.2\%$

Correct answer:

$1.6\%$

Explanation:

Use the following formula to find the percent error:

$\frac{|\text{accepted value-experimental value}|}{\text{accepted value}}\cdot100\%$

For this experiment, our accepted value is the same as the theoretical value.

$\text{Percent error}=\frac{|100-101.6|}{100}\cdot100\%=1.6\%$

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Example Question #1 : Calculating Error

From an experiment, a student found the density of a rubber eraser was $3.3\frac{g}{cm^3}$ . However, the actual density of the eraser is $2.9\frac{g}{cm^3}$ . What is the student's percent error?

Possible Answers:

$11.7\%$

$15.9\%$

$13.8\%$

$12.2\%$

Correct answer:

$13.8\%$

Explanation:

Use the following formula to find the percent error:

$\frac{|\text{accepted value-experimental value}|}{\text{accepted value}}\cdot100\%$

For this experiment, our accepted value is the same as the theoretical value.

$\text{Percent error}=\frac{|2.9-3.3|}{2.9}\cdot100\%=13.8\%$

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Example Question #1 : Calculating Error

The experimental value obtained for the specific heat of gold was $0.33\frac{J}{g^{\text o}C}$ . The known specific heat of gold is $0.219\frac{J}{g^{\text o}C}$ . What is the percent error?

Possible Answers:

$50.7\%$

$33.6\%$

$47.3\%$

$40.2\%$

Correct answer:

$50.7\%$

Explanation:

Use the following formula to find the percent error:

$\frac{|\text{accepted value-experimental value}|}{\text{accepted value}}\cdot100\%$

For this experiment, our accepted value is the same as the theoretical value.

$\text{Percent error}=\frac{|0.219-0.33|}{0.219}\cdot100\%=50.7\%$

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Example Question #6 : Precision, Accuracy, And Error

A reaction produced 98.5 grams of nitrogen dioxide gas. However, the calculated theoretical value indicates that 115.2 grams of nitrogen dioxide gas should have been produced. What is the percent error?

Possible Answers:

$24.9\%$

$16.3\%$

$14.5\%$

$10.1\%$

Correct answer:

$14.5\%$

Explanation:

Use the following formula to find the percent error:

$\frac{|\text{accepted value-experimental value}|}{\text{accepted value}}\cdot100\%$

For this experiment, our accepted value is the same as the theoretical value.

$\text{Percent error}=\frac{|115.5-98.5|}{115.2}\cdot100\%=14.5\%$

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Example Question #11 : Precision, Accuracy, And Error

A student found out through experimentation that it requires 23.6 mL of a NaOH solution to completely neutralize 25 mL of a HCl solution. However, the actual amount of NaOH solution needed to neutralize 25 mL of the HCl solution is 22.8 mL. What is the percent error?

Possible Answers:

$3.5\%$

$4.9\%$

$1.6\%$

$8.2\%$

Correct answer:

$3.5\%$

Explanation:

Use the following formula to find the percent error:

$\frac{|\text{accepted value-experimental value}|}{\text{accepted value}}\cdot100\%$

For this experiment, our accepted value is the same as the theoretical value.

$\text{Percent error}=\frac{|22.8-23.6|}{22.8}\cdot100\%=3.5\%$

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Example Question #71 : High School Chemistry

Joseph calculated that the concentration of an acid solution was 13.2M. The actual concentration of the solution was 16.3M. What is Joseph's percent error?

Possible Answers:

$19.0\%$

$22.9\%$

$16.3\%$

$3.3\%$

Correct answer:

$19.0\%$

Explanation:

Use the following formula to find the percent error:

$\frac{|\text{accepted value-experimental value}|}{\text{accepted value}}\cdot100\%$

For this experiment, our accepted value is the same as the theoretical value.

$\text{Percent error}=\frac{|16.3-13.2|}{16.3}\cdot100\%=19.0\%$

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Example Question #13 : Calculating Error

Patricia measured that the density of a given block of iron was $7.1\frac{g}{cm^3}$ . The actual density of iron is $7.9\frac{g}{cm^3}$ . What is Patricia's percent error?

Possible Answers:

$16.3\%$

$10.1\%$

$8.9\%$

$6.6\%$

Correct answer:

$10.1\%$

Explanation:

Use the following formula to find the percent error:

$\frac{|\text{accepted value-experimental value}|}{\text{accepted value}}\cdot100\%$

For this experiment, our accepted value is the same as the theoretical value.

$\text{Percent error}=\frac{|7.9-7.1|}{7.9}\cdot100\%=10.1\%$

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Example Question #72 : High School Chemistry

Steven calculated that the melting point of tin is 462 degrees Fahrenheit. The actual melting point of tin is 450 degrees Fahrenheit. What is Steven's percent error?

Possible Answers:

$2.9\%$

$8.4\%$

$2.2\%$

$1.7\%$

Correct answer:

$2.2\%$

Explanation:

Use the following formula to find the percent error:

$\frac{|\text{accepted value-experimental value}|}{\text{accepted value}}\cdot100\%$

For this experiment, our accepted value is the same as the theoretical value.

$\text{Percent error}=\frac{|450-460|}{450}\cdot100\%=2.2\%$

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Example Question #73 : High School Chemistry

Through experimentation, Luke found the boiling point of ethanol to be 143 degrees Fahrenheit. The actual boiling point of ethanol is 173 degrees Fahrenheit. What is Luke's percent error?

Possible Answers:

$6.7\%$

$13.6\%$

$19.2\%$

$17.3\%$

Correct answer:

$17.3\%$

Explanation:

Use the following formula to find the percent error:

$\frac{|\text{accepted value-experimental value}|}{\text{accepted value}}\cdot100\%$

For this experiment, our accepted value is the same as the theoretical value.

$\text{Percent error}=\frac{|173-143|}{173}\cdot100\%=17.3\%$

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High School Chemistry : High School Chemistry

Study concepts, example questions & explanations for High School Chemistry

All High School Chemistry Resources

Example Questions

Example Question #1 : Precision, Accuracy, And Error

Example Question #1 : Calculating Error

Example Question #1 : Calculating Error

Example Question #1 : Calculating Error

Example Question #6 : Precision, Accuracy, And Error

Example Question #11 : Precision, Accuracy, And Error

Example Question #71 : High School Chemistry

Example Question #13 : Calculating Error

Example Question #72 : High School Chemistry

Example Question #73 : High School Chemistry

All High School Chemistry Resources

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