All GRE Subject Test: Math Resources
Example Questions
Example Question #115 : Calculus
Find the derivative of: .
None of the Above
Step 1: We need to define the quotient rule. The quotient rule says: , where is the derivative of and is the derivative of
Step 2: We need to review how to take derivatives of different kinds of terms. When we are taking the derivative of terms in a polynomial, we need to follow these rules:
Rule 1: For any term with an exponent, the derivative of that term says: Drop the exponent and multiply it to the coefficient of that term. The new exponent of the derivative is lower than the previous exponent.
Example:
Rule 2: For any term in the form , the derivative of that term is just , the coefficient of that term.
Ecample:
Rule 3: The derivative of any constant is always
Step 3: Find and :
Step 4: Plug in all equations into the quotient rule:
Step 5: Simplify the fraction in step 4:
Step 6: Combine terms in the numerator in step 5:
.
The derivative of is
Example Question #11 : Finding Derivatives
Find the derivative of:
Step 1: Define .
Step 2: Find .
Step 3: Plug in the functions/values into the formula for quotient rule:
The derivative of the expression is
Example Question #1 : Quotient Rule
Find derivative .
This question yields to application of the quotient rule:
So find and to start:
So our answer is:
Example Question #5 : Quotient Rule
Find the second derivative of:
None of the Above
None of the Above
Finding the First Derivative:
Step 1: Define
Step 2: Find
Step 3: Plug in all equations into the quotient rule formula:
Step 4: Simplify the fraction in step 3:
Step 5: Factor an out from the numerator and denominator. Simplify the fraction..
We have found the first derivative..
Finding Second Derivative:
Step 6: Find from the first derivative function
Step 7: Find
Step 8: Plug in the expressions into the quotient rule formula:
Step 9: Simplify:
I put "..." because the numerator is very long. I don't want to write all the terms...
Step 10: Combine like terms:
Step 11: Factor out and simplify:
Final Answer: .
This is the second derivative.
The answer is None of the Above. The second derivative is not in the answers...
Example Question #1 : Chain Rule
Compute the derivative:
This question requires application of multiple chain rules. There are 2 inner functions in , which are and .
The brackets are to identify the functions within the function where the chain rule must be applied.
Solve the derivative.
The sine of sine of an angle cannot be combined to be sine squared.
Therefore, the answer is:
Example Question #12 : Derivatives & Integrals
Find the derivative of the following function:
Recall chain rule for this problem
So if we are given the following,
We can think of it like this
Clean it up a bit to get:
Example Question #1 : Chain Rule
What is the derivative of
Chain Rule:
For this problem
Plug the values into the Chain Rule formula and simplify:
Example Question #1 : Defining Derivatives With Limits
Evaluate:
Does Not Exist
Step 1: Try plugging in into the denominator of the function. We want to make sure that the bottom does not become ...
.. We got zero, and we cannot have zero in the denominator. So, we must try and factor the function (numerator and denominator):
Step 2: Factor:
Step 3: Reduce:
Step 4: Now that we got rid of the factor that made the denominator zero, we know that this function has a limit.
Step 5: Plug in into the reduced factor form:
Simplify as much as possible...
The limit of this function as x approaches is
Example Question #1 : Implicit Differentiation
Differentiate the following with respect to .
The first step is to differentiate both sides with respect to :
Note: Those that are functions of can be differentiated with respect to , just remember to mulitply it by
Now we can solve for :
Example Question #2 : Implicit Differentiation
Find
for .
Our first step would be to differentiate both sides with respect to :
The functions of can be differentiated with respect to , just remember to multiply by .
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