GRE Math : Equilateral Triangles

Study concepts, example questions & explanations for GRE Math

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Example Questions

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Example Question #41 : Triangles

Quantity A: The height of an equilateral triangle with an area of 

Quantity B: 

Which of the following is true?

 

Possible Answers:

Quantity A is greater.

Quantity B is greater.

The two quantities are equal.

The relationship cannot be determined.

Correct answer:

Quantity B is greater.

Explanation:

This problem requires a bit of creative thinking (unless you have memorized the fact that an equilateral triangle always has an area equal to its side length times .

Consider the equilateral triangle:

Equilateral8

Since this kind of triangle is a species of isoceles triangle, we know that we can drop down a height from the top vertex. This will create two equivalent triangles, one of which will look like:

Equilateral8 2

This gives us a 30-60-90 triangle. We know that for such a triangle, the ratio of the side across from the 30-degree angle to the side across from the 60-degree angle is:

We can also say, given our figure, that the following equivalence must hold:

Solving for , we get:

Now, since , we know that  must be smaller than . This means that  or . Quantity B is larger than quantity A.

Example Question #41 : Triangles

Quantity A: The height of an equilateral triangle with perimeter of .

Quantity B: 

Which of the following is true?

Possible Answers:

Quantity A is larger.

The two quantities are equal.

The relationship cannot be determined.

Quantity B is larger.

Correct answer:

Quantity B is larger.

Explanation:

If the perimeter of our equilateral triangle is , each of its sides must be  or . This gives us the following figure:

Equilateral9

Since this kind of triangle is a species of isoceles triangle, we know that we can drop down a height from the top vertex. This will create two equivalent triangles, one of which will look like:

Equilateral9 2

 

This gives us a 30-60-90 triangle. We know that for such a triangle, the ratio of the side across from the 30-degree angle to the side across from the 60-degree angle is:

Therefore, we can also say, given our figure, that the following equivalence must hold:

Solving for , we get:

Now, since , we know that  must be smaller than . This means that  or 

Therefore, quantity B is larger than quantity A.

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