GRE Math : How to find rate

Study concepts, example questions & explanations for GRE Math

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Example Questions

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Example Question #541 : Arithmetic

Ben mows the lawn in 1 hour. Kent mows the lawn in 2 hours. How long will it take them to mow the lawn working together?

Possible Answers:

45 minutes

50 minutes

40 minutes

1 1/2 hours

1 hour

Correct answer:

40 minutes

Explanation:

Ben mows 1 lawn in 1 hour, or 1/60 of the lawn in 1 minute. Ken mows 1 lawn in 2 hours, or 1/120 of the lawn in 1 minute. Then each minute they mow 1/60 + 1/120 = 3/120 = 1/40 of the lawn. That means the entire lawn takes 40 minutes to mow.

Example Question #542 : Arithmetic

A train travels at 50 feet per second. If there are 5280 feet in a mile, how many miles will the train travel in an hour?

Possible Answers:

0.6

70

950,400,000

34

264,000

Correct answer:

34

Explanation:

First, we must determine how many feet per hour the train travels.

50 feet per second * 60 seconds in a minute * 60 minutes in an hour.

50 * 60 * 60 = 180,000

Then, it's just a matter of converting 180,000 feet to miles.  Because there are 5280 feet in a mile, just divide.

180,000 / 5280 = 34.091

Example Question #11 : How To Find Rate

John can paint a room in 4 hours, and Susan can paint the same room in 6 hours. How many minutes would it take them to paint the room together?

Possible Answers:

\dpi{100} \small 128 minutes

\dpi{100} \small 180 minutes

\dpi{100} \small 144 minutes

\dpi{100} \small 150 minutes

\dpi{100} \small 164 minutes

Correct answer:

\dpi{100} \small 144 minutes

Explanation:

First find what fraction of the job is completed per hour. If John can paint the room in 4 hours, then he completes \dpi{100} \small \frac{1}{4} of it per hour. Similarly, Susan paints \dpi{100} \small \frac{1}{6} of it per hour. So together they paint \dpi{100} \small \frac{1}{4}+\frac{1}{6} of the room per hour. 

Add \dpi{100} \small \frac{1}{4}+\frac{1}{6} by rewriting them with the same common denominator (least common multiple of 4 and 6 is 12, so 12 is the least common denominator):

\dpi{100} \small \frac{1}{4} + \frac{1}{6} = \frac{1\times 3}{4\times 3} + \frac{1\times 2}{6\times 2} = \frac{3}{12} + \frac{2}{12} = \frac{5}{12}

This means \dpi{100} \small \frac{5}{12} of the job is completed per hour. To find the number of hours for the whole job (1 room), divide the whole by the fraction completed per hour:

\dpi{100} \small 1 \div \frac{5}{12} = 1\times \frac{12}{5} = \frac{12}{5} hours

Convert hours to minutes:

\dpi{100} \small \frac{12}{5} hours \times \frac{60 minutes}{1 hour} = \frac{720}{5} = 144 minutes

Example Question #544 : Arithmetic

Carol ate 3 pancakes in 5 minutes. If she continues to eat at the same rate, how many whole pancakes can she eat in 24 minutes?

Possible Answers:

\dpi{100} \small 15

\dpi{100} \small 8

\dpi{100} \small 14

\dpi{100} \small 12

\dpi{100} \small 6

Correct answer:

\dpi{100} \small 14

Explanation:

If Carol ate 3 pancakes in 5 minutes, she can eat \dpi{100} \small \frac{3}{5} of a pancake every minute. \dpi{100} \small \frac{3}{5}\ pancakes\times 24\ minutes=14.4\ pancakes.

That means she ate 14 whole pancakes (and an additional 2/5 of another pancake).

Example Question #545 : Arithmetic

If 24 machines can make 5 devices in 30 minutes, how many hours will it take 4 machines to make 15 devices?

Possible Answers:

5 hours

12 hours

3 hours

6 hours

9 hours

Correct answer:

9 hours

Explanation:

Approach this problem with the following reasoning.

Unit of work done = number of workers * rate * time

In our case, we are given 24 "workers," able to make 5 "units of work," in 0.5 "time." The rate is not given, but can be solved for with our given information.

Units of work = 5

Number of workers = 24

Time = 0.5 hours (30 minutes)

Now, since we know the rate, which does not chage, we can solve for the new time when the number of machines is decreased and the number of devices is increased.

 Unit of work done = number of workers * rate * time

Example Question #546 : Arithmetic

Mario can solve  problems in  hours. At this rate, how many problems can he solve in  hours?

Possible Answers:

Correct answer:

Explanation:

The rate is given by amount of probems over time.

To find the amount of problems done in a given amount of time, mulitply the rate by the given amount of time.

We can combine our y terms and cancel our n terms to simplify.

Example Question #543 : Arithmetic

It takes Mary 45 minutes to completely frost 100 cupcakes, and it takes Benjamin 80 minutes to completely frost 110 cupcakes.  How many cupcakes can they completely frost, working together, in 1 hour?

Possible Answers:

Correct answer:

Explanation:

In this rate word problem, we need to find the rates at which Mary and Bejamin frost their respective cupcakes, and then sum their respective rates per hour. In one hour Mary frosts 133 cupcakes. (Note: the question specifies COMPLETELY frosted cupcakes only, so the fractional results here will need to be rounded down to the nearest integer.)  Benjamin frosts 82 cupcakes.

82 + 133=215

Example Question #548 : Arithmetic

If John can paint a house in  hours and Jill can paint a house in  hours, how long will it take for both John and Jill to paint a house together?

Possible Answers:

Correct answer:

Explanation:

This problem states that John can paint a house in  hours. That means in  hour he will be able to paint  of a house.

The problem also states that Jill can paint a house in  hours. This means that in  hour, Jill can paint  of a house.

If they are painting together, you simply add the rate at which the paint separately together to find the rate at which they paint together. This means in  hour, they can paint  of a house. Now to find the time that paint an entire house, we simply invert that fraction, meaning that to paint an entire house together it would take them   of an hour, or .

 

The general formula for solving these work problems is , where  is the amount of time it takes worker A to finish the job alone and  is the amount of time it would take worker B to finish the job alone.

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