All GRE Math Resources
Example Questions
Example Question #2 : Midpoint Formula
What is the other endpoint of a line segment with one point that is and a midpoint of ?
What is the other endpoint of a line segment with one point that is and a midpoint of ?
Recall that the midpoint formula is like finding the average of the and values for two points. For two points and , it is:
For our points, we are looking for . We know:
We can solve for each of these coordinates separately:
X-Coordinate
Y-Coordinate:
Therefore, our point is
Example Question #1 : How To Find The Midpoint Of A Line Segment
What is the midpoint of (2, 5) and (14, 18)?
(1, 2.5)
(16, 23)
(–10, –13)
(7, 9)
(8, 11.5)
(8, 11.5)
The midpoint between two given points is found by solving for the average of each of the correlative coordinates of the given points. That is:
Midpoint = ( (2 + 14)/2 , (18 + 5)/2) = (16/2, 23/2) = (8, 11.5)
Example Question #2 : How To Find The Midpoint Of A Line Segment
What is the midpoint between the points (1,3,7) and (–3,1,3)?
(–1,2,5)
(3,1,2)
(2,–1,5)
(5,2,4)
(2,2,5)
(–1,2,5)
To find the midpoint, we add up the corresponding coordinates and divide by 2.
[1 + –3] / 2 = –1
[3 + 1] / 2 = 2
[7 + 3] / 2 = 5
Then the midpoint is (–1,2,5).
Example Question #71 : Lines
A line which cuts another line segment into two equal parts is called a ___________.
bisector
midpoint
horizontal line
parallel line
transversal
bisector
This is the definition of a bisector.
A midpoint is the point on a line that divides it into two equal parts. The bisector cuts the line at the midpoint, but the midpoint is not a line.
A transversal is a line that cuts across two or more lines that are usually parallel.
Parallel line and horizontal line don't make sense as answer choices here. The answer is bisector.
Example Question #1 : How To Find Out If Lines Are Perpendicular
what would be the slope of a line perpendicular to
4x+3y = 6
4
-4/3
3/4
-3/4
4/3
3/4
switch 4x+ 3y = 6 to "y=mx+b" form
3y= -4x + 6
y = -4/3 x + 2
m = -4/3; the perpendicular line will have the negative reciprocal of this line so it would be 3/4
Example Question #2 : How To Find Out If Lines Are Perpendicular
Which line is perpendicular to the line between the points (22,24) and (31,4)?
y = –3x + 5
the line between the points (9, 5) and (48, 19)
y = x
y = .45x + 10
the line between the points (4, 7) and (7, 4)
y = .45x + 10
The line will be perpendicular if the slope is the negative reciprocal.
First we need to find the slope of our line between points (22,24) and (31,4). Slope = rise/run = (24 – 4)/(22 – 31) = 20/–9 = –2.22.
The negative reciprocal of this must be a positive fraction, so we can eliminate y = –3x + 5 (because the slope is negative).
The negative reciprocal of –2.22, and therefore the slope of the perpendicular line, will be –1/–2.22 = .45, so we can also eliminate y = x (slope of 1).
Now let's look at the line between points (9, 5) and (48, 19). This slope = (5 – 19)/(9 – 48) = .358, which is incorrect.
The next answer choice is y = .45x + 10. The slope is .45, which is what we're looking for so this is the correct answer.
To double check, the last answer choice is the line between (4, 7) and (7, 4). This slope = (7 – 4) / (4 – 7) = –1, which is also incorrect.
Example Question #3 : How To Find Out If Lines Are Perpendicular
Which best describes the relationship between the lines and ?
The lines are parallel.
The equations describe the same line.
None of the above.
The lines are perpendicular.
The lines are perpendicular.
We first need to recall the following relationships:
Lines with the same slope and same -intercept are really the same line.
Lines with the same slope and different -intercepts are parallel.
Lines with slopes that are negative reciprocals are perpendicular.
Then we identify the slopes of the two lines by comparing the equations to the slope-intercept form , where is the slope and is the -intercept. By inspection we see the lines have slopes of and . Since these are different, the "parallel" and "same line" choices are eliminated. To test if the slopes are negative reciprocals, we take one of the slopes, change its sign, and flip it upside-down. Starting with and changing the sign gives , then flipping gives . This is the same as the slope of the second line, so the two slopes are negative reciprocals and the lines are perpendicular.
Example Question #1461 : Gre Quantitative Reasoning
Which of the following lines is perpendicular to the line defined as ?
To begin, the best thing to do is to put your equation into slope-intercept format. That is, into the format:
For your equation, you need to solve for :
, which is the same as
Then, divide both sides by :
So, the slope of this line is . The perpendicular of a line is opposite and reciprocal. Therefore, the perpendicular line will have a slope of . Of the options given, only matches this (which you can figure out when you solve for ).
Example Question #1461 : Gre Quantitative Reasoning
Which of the following lines is perpendicular to the line passing through the points and ?
Remember, to be perpendicular, two lines must have opposite and reciprocal slopes. Therefore, you need to begin by solving for the slope of your given line. You do this by finding:
For two points and , this is:
For our points, this is:
The slope of the perpendicular line will be (remember) opposite and reciprocal. Therefore, it will be . Now, among your equations, the only one that has this slope is:
If you solve this for , you get:
According to the slope-intercept form (), this means that the slope is .
Example Question #1 : How To Find Out If Lines Are Perpendicular
Which of the following lines is perpendicular to the line ?
Perpendicular lines will have slopes that are negative reciprocals of one another. Our first step will be to find the slope of the given line by putting the equation into slope-intercept form.
The slope of this line is . The negative reciprocal will be , which will be the slope of the perpendicular line.
Now we need to find the answer choice with this slope by converting to slope-intercept form.
This equation has a slope of , and must be our answer.