All GRE Math Resources
Example Questions
Example Question #141 : Algebra
Steve sells cars. His monthly salary is $1,000. He gets a $500 commission for each car he sells. If Steve wants to make $7,500 this month, how many cars would he have to sell?
Let = money earned and = number of cars sold
So
and solving shows that he needs to sell 13 cars to make $7,500.
Example Question #1813 : Sat Mathematics
A chemistry student needs to dilute some acid. How much pure water should be added to 2 gallons of 80% acid solution to yield 20% acid solution?
Let pure water = 0 % and pure acid = 100%
The general equation to use is:
where is the volume and is the percent solution.
So the equation to solve becomes and gallons of pure water needs to be added to get a 20% acid solution.
Example Question #41 : How To Find The Solution To An Equation
The Widget Company makes widgets. The monthly fixed costs are $750. It costs $45 to make each widget. The widgets sell for $75 a piece.
What is the monthly break-even point?
The break-even point is where the costs equal revenue.
Let = # of widgets sold.
Costs:
Revenue:
So the equation to solve becomes
So the break-even point occurs when they sell 25 widgets.
Example Question #41 : Equations / Inequalities
The Widget Company makes widgets. The monthly fixed costs are $750. It costs $45 to make each widget. The widgets sells for $75 a piece.
The Widget Company wants to make a profit of $3,000. How many widgets must be sold?
Profits = Revenues - Costs
Revenue:
Costs:
Profit:
So the equation to solve becomes
So a $3,000 profit occurs when they sell 125 widgets
Example Question #1 : New Sat Math Calculator
Sally sells custom picture frames. Her monthly fixed costs are $350. It costs $10 to make each frame. Sally sells her picture frames for $35 each.
How many picture frames must Sally sell in order to break even?
The break-even point is where the costs equal the revenues.
Let = # of frames sold
Costs:
Revenues:
Thus,
So 14 picture frames must be sold each month to break-even.
Example Question #41 : How To Find The Solution To An Equation
Sally sells custom picture frames. Her monthly fixed costs are $350. It costs $10 to make each frame. Sally sells her picture frames for $35 each.
To make a profit of $500, how many frames need to be sold?
Let = # of frames sold
Revenues:
Costs:
Profits =
So the equation to solve becomes
So 34 picture frames must be sold to make a $500 profit.
Example Question #41 : Equations / Inequalities
How much pure water must be added to 2 gallons of 90% pure cleaning solution to yield a 30% pure cleaning solution?
Let pure water be 0% and pure solution be 100%.
So the general equation to solve is:
where is the volume and the is percent solution.
So the equation to solve becomes
Solving shows that we need to add 4 gallons of pure water to 2 gallons of 90% pure cleaning solution to get a 30% pure solution.
Example Question #101 : Linear / Rational / Variable Equations
Susan got a new piggy bank and counted the change she put into it. She had one more nickel than dimes and two fewer quarters than nickles. The value of her change was $1.40. How many total coins did she have?
Let = number of dimes, = number of nickels, and
= number of quarters.
The general equation to use is:
where is the money value and is the number of coins
So the equation to solve becomes
Thus, solving the equation shows that she had five nickels, four dimes, and three quarters giving a total of 12 coins.
Example Question #145 : Algebra
How much pure water should be added to of 80% cleaning solution to dilute it to 25% cleaning solution.
Pure water is 0% and pure solution is 100%
where is the volume and is the percent.
So the equation to solve becomes
So we need to add pure water to of 80% cleaning solution to yield 25% cleaning solution.
Example Question #41 : Equations / Inequalities
Luke purchased a tractor for $1200. The value of the tractor decreases by 25 percent each year. The value, , in dollars, of the tractor at years from the date of purchase is given by the function .
In how many years from the date of purchase will the value of the tractor be $675?
4
5
1
2
3
2
We are looking for the value of t that gives $675 as the result when plugged in V (t ). While there are many ways to do this, one of the fastest is to plug in the answer choices as values of t .
When we plug t = 1 into V (t ), we get V (1) = 1200(0.75)1 = 1000(0.75) = $900, which is incorrect.
When we plug t = 2 into V (t ), we get V (2) = 1200(0.75)2 = $675, so this is our solution.
The value of the tractor will be $675 after 2 years.
Finally, we can see that if t = 3, 4, or 5, the resulting values of the V (t ) are all incorrect.