GMAT Math : GMAT Quantitative Reasoning

Study concepts, example questions & explanations for GMAT Math

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Example Questions

Example Question #2 : Discount

Data sufficiency question

During a semi-annual sale, the price of a shirt is discounted. Calculate the percent discount.

1. The sale price is $23.

2. The sale price is $6 less than the original price.

Possible Answers:

Each statement alone is sufficient

Both statements taken together are sufficient to answer the question, but neither statement alone is sufficient

Statements 1 and 2 together are not sufficient, and additional data is needed to answer the question

Statement 1 alone is sufficient, but statement 2 alone is not sufficient to answer the question

Statement 2 alone is sufficient, but statement 1 alone is not sufficient to answer the question

Correct answer:

Both statements taken together are sufficient to answer the question, but neither statement alone is sufficient

Explanation:

In order to calculate the percent discount, both the original price and the sale price must be known. From statement 1, we know the sale price and with the additional information from statement 2, we can calculate the original price and then overall percent discount.

Example Question #3 : Discount

A store owner applies a certain percentage of discount on items bought by customers who have a rewards card. What is the percentage of discount applied?

(1) A customer without a reward card pays 1.5 times what a customer with a reward card pays on the same articles.

(2) A customer with a reward card pays two thirds of any listed price.

Possible Answers:

Statements (1) and (2) TOGETHER are not sufficient.

Each Statement ALONE is sufficient.

Both statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient.

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient.

Correct answer:

Each Statement ALONE is sufficient.

Explanation:

(1) A customer without a reward card pays 1.5 times what a customer with a reward card pays on the same articles.

Let x be the price a customer with a reward card pays, a customer without a reward card pays 1.5x, 1.5x being the original selling price. We can calculate the percentage of discount as:

\(\displaystyle \frac{x-1.5x}{1.5x}=\frac{-.5x}{1.5x}=-\frac{1}{3}\)

Statement (1) is sufficient.

 

(2) A customer with a reward card pays two thirds of any listed price.

Let y be the listed price of a given article. A customer with reward card pays \(\displaystyle \frac{2}{3}y\).

The percentage of discount is:

\(\displaystyle \frac{\frac{2}{3}y-y}{y}=\frac{-\frac{1}{3}y}{y}=-\frac{1}{3}\)

Statement (2) is sufficient.

Each Statement ALONE is sufficient.

 

Example Question #4 : Dsq: Calculating Discounts

What is the amount of tuition for a MBA degree at University X?

(1) Students with a GMAT score above 700 receive a 50% discount on the tuition.

(2) The average tuition paid by 5 students is $50,000, if only 2 of these students received a 50% discount.

Possible Answers:

Both statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient.

Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient.

Statements (1) and (2) TOGETHER are not sufficient.

Each Statement ALONE is sufficient.

Correct answer:

Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient.

Explanation:

(1) Students with a GMAT score above 700 receive a 50% discount on the tuition.

Statement (1) is not sufficient as we do not know how much half of the tuition is.

(2) The average tuition paid by 5 students is $50,000, if only 2 of these students received a 50% discount. Let x be the full amount of tuition for the MBA program.

\(\displaystyle \frac{.5x+.5x+x+x+x}{5}=50000\)

\(\displaystyle 4x=250,000\)

\(\displaystyle x=\frac{250000}{4}=62500\)

Statement(2) Alone is sufficient.

Example Question #4 : Dsq: Calculating Discounts

How many dollars does Jane save when using a coupon to buy a purse at a local store?

(1) The original price of the purse is $400.

(2) When using the coupon, Jane saves 25%.

Possible Answers:

Both statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient.

Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient.

Statements (1) and (2) TOGETHER are not sufficient.

Each Statement ALONE is sufficient.

Correct answer:

Both statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Explanation:

Note that the question does not ask for the percentage of discount but the amount of money saved.

(1) The original price of the purse is $400.

Statement (1) alone is not sufficient because it only gives the selling price prior to using the coupon.

(2) When using the coupon, Jane saves 25%.

Statement (2) alone is not sufficient. Even though we know the percentage of discount, we do not have the original price.

However, combining both statements, we get the amount of money saved as:

\(\displaystyle \frac{25}{100}\times400=100\)

Jane saved $100 by using the coupon.

Both statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Example Question #6 : Dsq: Calculating Discounts

A lawn-mower is initially offerred at \(\displaystyle \$250\). Its price is discounted \(\displaystyle 8\%\) off the full price. What is the final price?

Possible Answers:

\(\displaystyle \$240.00\)

\(\displaystyle \$150.00\)

\(\displaystyle \$172.20\)

\(\displaystyle \$200.00\)

\(\displaystyle \$230.00\)

Correct answer:

\(\displaystyle \$230.00\)

Explanation:

If the initial price is \(\displaystyle P=\$250\), and the discount is \(\displaystyle d=8\%\), the final sale price is

\(\displaystyle S=(1-d/100)\cdot P\)

\(\displaystyle \$250\cdot(1-8/100)) = \$230\)
 

 

Example Question #2 : Discount

A lawn-mower is discounted \(\displaystyle 10\%\) off the full price. A second discount of \(\displaystyle 25\%\) is applied at the register. What is the final discount?

Possible Answers:

\(\displaystyle 10.5\%\)

\(\displaystyle 32.5\%\)

\(\displaystyle 53.2\%\)

\(\displaystyle 68.3\%\)

\(\displaystyle 25.2\%\)

Correct answer:

\(\displaystyle 32.5\%\)

Explanation:

If the initial price is P, and it is discounted twice at rates \(\displaystyle d{_{1}}\) and \(\displaystyle d{_{2}}\), the final price \(\displaystyle S\) is

\(\displaystyle S=P\cdot(1-d_{1}/100)\cdot (1-d_{2}}/100)%\)

Substituting values this is

\(\displaystyle \frac{S}{P}=(1-10/100)\cdot(1-25/100)%\)

 \(\displaystyle D=1-100\cdot S/P\)

or  \(\displaystyle 1-0.675\cdot 100 = 32.5\%\)

Example Question #2201 : Gmat Quantitative Reasoning

A lawn-mower is initially listed at \(\displaystyle \$250\). Its price is discounted off the full price some unknown amount, \(\displaystyle D\). An employee uses their \(\displaystyle 50\%\) discount at the register and is charged \(\displaystyle \$100\).

What is the unknown initial discount,\(\displaystyle D\)?

Possible Answers:

\(\displaystyle 10\%\)

\(\displaystyle 25\%\)

\(\displaystyle 5\%\)

\(\displaystyle 15\%\)

\(\displaystyle 20\%\)

Correct answer:

\(\displaystyle 20\%\)

Explanation:

The relationship between the list price, \(\displaystyle L=\$250\), sale price, \(\displaystyle \$100\), and the employee's discount, \(\displaystyle D=50\%\), is

\(\displaystyle S =L\cdot (1-E/100) \cdot(1-D/100)\)

Inserting values and re-organizing:

\(\displaystyle D = 100\cdot (1-\frac{\$100}{\$250 (1-50/100) })= 20\%\)

Example Question #9 : Dsq: Calculating Discounts

A lawn-mower is initially listed at \(\displaystyle \$600\). Its price is discounted \(\displaystyle 10\%\) off the full price. How much does the customer save relative to the initial list price?

Possible Answers:

\(\displaystyle \$60.00\)

\(\displaystyle \$405.00\)

\(\displaystyle \$540.00\)

\(\displaystyle \$270.00\)

\(\displaystyle \$30.00\)

Correct answer:

\(\displaystyle \$60.00\)

Explanation:

If the initial price is \(\displaystyle L=\$600\), and the discount is \(\displaystyle D=10\%\), the savings are

\(\displaystyle L\cdot D/100 = \$600\cdot (10/100) = \$60\)

 

Example Question #2202 : Gmat Quantitative Reasoning

A lawn-mower is initially listed at \(\displaystyle P\).  Its price is discounted \(\displaystyle D\%\) off the full price.

In terms of \(\displaystyle P\), and \(\displaystyle D\), with \(\displaystyle D\) expressed in percent, what is the formula for the amount charged, \(\displaystyle Q\) at the register?

Possible Answers:

\(\displaystyle Q=100\cdot P\cdot (1-D)\)

\(\displaystyle Q= P\cdot D\)

\(\displaystyle Q=100\cdot P\cdot D\)

\(\displaystyle Q= P\cdot D/100\)

\(\displaystyle Q=P\cdot(1-D/100)\)

Correct answer:

\(\displaystyle Q=P\cdot(1-D/100)\)

Explanation:

The relationship between the list price, \(\displaystyle P\), the discount \(\displaystyle D\) in \(\displaystyle \%\), the price charged at the register is

\(\displaystyle Q=P\cdot(1-D/100)\).

The factor of \(\displaystyle 100\) represents the conversion from \(\displaystyle \%\) to a decimal value.

Example Question #91 : Data Sufficiency Questions

A lawn-mower is initially listed at a full price of \(\displaystyle P\). Its the ticket lists a discount of \(\displaystyle D\%\) off the full price.  The item is placed in a 'extra discount' location where all prices are listed as being discounted \(\displaystyle E\%\) off the already discounted ticket price.

In terms of \(\displaystyle P\)\(\displaystyle D\) and \(\displaystyle E\), with discounts \(\displaystyle D\) and \(\displaystyle E\) expressed in percent, what is the formula for the amount, \(\displaystyle Q\), charged at the register.

Possible Answers:

\(\displaystyle Q= P\cdot D\cdot E\)

\(\displaystyle Q=100\cdot P\cdot (1-D)\cdot (1-E)\)

\(\displaystyle Q= P\cdot (D+E)/100\)

\(\displaystyle Q=P\cdot (D/100)\cdot (E/100)\)

\(\displaystyle Q=P\cdot (1-D/100)\cdot (1-E/100)\)

Correct answer:

\(\displaystyle Q=P\cdot (1-D/100)\cdot (1-E/100)\)

Explanation:

The relationship between the original list price  and the price charged after two discounts is obtained by applying the formula for a discount serially:

\(\displaystyle Q=P\cdot (1-D/100) \cdot (1-E/100)\)

The factors of \(\displaystyle 100\) represent the conversion from \(\displaystyle \%\) to decimal values.

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