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Example Questions
Example Question #1 : Quadrilaterals
Note: Figure NOT drawn to scale.
Refer to the above figure. .
.
Give the ratio of the area of the shaded region to the area of .
The ratio of the areas of similar rectangles is the square of the similarity ratio, so the ratio of the area of  to that ofÂ
 isÂ
.
So if the area of  isÂ
, the area ofÂ
 isÂ
The area of the shaded region is the difference between the areas of the rectangles, making this area
.
The desired ratio is 24 to 25.
Example Question #2 : Calculating Whether Rectangles Are Similar
;Â
.
Which of the following must be equal to ?
The perimeter of  divided by the perimeter ofÂ
.Â
None of the other choices gives a correct answer.
The area of  divided by the area ofÂ
, soÂ
; this is the similarity ratio ofÂ
 toÂ
.
 andÂ
 are not corresponding sides, nor are they congruent to corresponding sides, so it may or may not be true thatÂ
.
Â
The ratio of the perimeters of similar rectangles is the same as their actual similarity ratio, but the choice gives the rectangles in the original order; the quotient of the perimeters as given is 3, not .
Â
Â
The ratio of the areas of similar rectangles is the square of the similarity ratio, so the quotient in the given choice is .
Â
However, by similarity, and the fact that opposite sides  andÂ
 are congruent,
.
The correct choice is .
Example Question #2 : Rectangles
In the above diagram,Â
.
 andÂ
. Give the area ofÂ
.
, so
The area of the rectangle isÂ
Â
Â
Example Question #1 : Rectangles
, andÂ
.
All the following quantities MUST be equal to 2 except for __________.
The perimeter of  divided by the perimeter ofÂ
.Â
All of the quantities in the other choices must be equal to .
The two rectangles are similar with similarity ratio 2.
Corresponding sides of similar rectangles are in proportion, so
.
Since opposite sides of a rectangle are congruent, , so
.
 andÂ
 are diagonals of the rectangle. If they are constructed, then, since
 andÂ
 (both are right angles), by the Side-Angle-Side Similarity Theorem,
. By similarity,Â
.
Â
The ratio of the perimeters of the rectangles is
,
It follows from  and a property of proportions that this ratio is equal to
.
Â
However,Â
is not a ratio of corresponding sides of the rectangle, so it does not have any restrictions on it. This is the correct choice.
Example Question #2 : Rectangles
A certain rectangle has a length of  and a width ofÂ
. Â Which of the following dimensions would another rectangle need in order for it to be similar?
In order for two rectangles to be similar, the ratio of their dimensions must be equal. We can first check the ratio of the length to the width for the given rectangle, and then see which option has the same ratio, which will tell us whether or not the rectangle is similar:
So in order for a rectangle to be similar, the ratio of its length to its width must be the same. All we must do then is check the answer options, in no particular order, for the rectangle with the same ratio:
Â
A rectangle with a length of  and a width ofÂ
 has the same ratio of dimensions as a rectangle with a length ofÂ
 and a width ofÂ
, so these two rectangles are similar.
Example Question #1 : Rectangles
An engineer is making a scale model of a building. The real building needs to have a width of  and a length ofÂ
. If the engineer's scale model has a width ofÂ
, what does the length of the model need to be?
An engineer is making a scale model of a building. The real building needs to have a width of  and a length ofÂ
. If the engineer's scale model has a width ofÂ
, what does the length of the model need to be?
To begin, we need to know what a scale model is. A scale model is a smaller version of something that is "to scale." In other words, it is similar but not congruent.Â
So, we find a length that will make the model accurate, we need a ratio. Try the following:
Example Question #1 : Rectangles
A rectangle has a length of and width of
. Solve for the perimeter.
Example Question #2 : Rectangles
A farmer decides to build a fence two feet around his rectangular field. The field is  feet long and
 feet wide. How long should the fencing be in order to build the fence around the field?
The fence is 2 feet around the field. Therefore the area actually enclosed by the fence is 4 feet longer and 4 feet wider than the field.
The length of fencing needed is the perimeter of the area enclosed which is calculated as follows:
The fencing should be 90 feet.
Example Question #352 : Gmat Quantitative Reasoning
If a rectangle has an area of  and a length of
, what is its perimeter?
To find the perimeter, we need the length and the width. We are only given the length, so first we must find the width using the given area:
The perimeter is simply two times the length plus two times the width, so we can now use the known length and width to calculate the perimeter:
Example Question #4 : Calculating The Perimeter Of A Rectangle
The diagonal  of the rectangle
 is
 cm long and
 is
 cm long. What is the perimeter of the rectangle?
We can see that the hypotenuse AD of triangle ABD is 15 cm. We should check whether ABD is a Pythagorean Triple, whose sides are in the ratio , whereÂ
 is a constant. Since AD is 15 and BD is 9, the triangle must be a Pythagorean Triple withÂ
, therefore AB must be 12 cm long. Now we know all the lengths of the sides of our triangle, we can find the perimeter which will be given byÂ
, which gives us 42, our final answer.
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